The RMS value of an AC is given by I_rms = I_peak / √2. Therefore, I_rms = 10 A / √2 = 7.07 A.

The RMS value of an AC is given by I_rms = I_peak / √2. Therefore, I_rms = 10 A / √2 = 7.07 A.

The root mean square speed (v_rms) is given by the formula v_rms = (3RT/M)^0.5, where R is the gas constant, T is the temperature, and M is the molar mass.

The root mean square speed of gas molecules is directly proportional to the square root of the absolute temperature, as given by the equation v_rms = sqrt(3kT/m).

The root mean square speed (v_rms) is given by the formula v_rms = sqrt(3kT/m) where k is the Boltzmann constant, T is the temperature, and m is the mass of a gas molecule.

The root mean square speed (v_rms) is given by the formula v_rms = sqrt(3RT/M), where R is the gas constant, T is the temperature, and M is the molar mass.

A · B = 3*0 + 4*0 + 0*5 = 0.

i · j = 0, since they are orthogonal.

The scalar product is 3*4 + 4*3 = 12 + 12 = 24.

Scalar product = 4*1 + (-3)*1 + 2*1 = 4 - 3 + 2 = 3.

Scalar product = 5*(-2) + (-3)*4 = -10 - 12 = -22.

Scalar product = 5*1 + 5*2 + 5*3 = 5 + 10 + 15 = 30.

A · B = 0*1 + 1*0 + 0*1 = 0.

A · B = 1*1 + 1*1 + 1*1 = 1 + 1 + 1 = 3.

A · B = 1*4 + 2*5 + 3*6 = 4 + 10 + 18 = 32.

A · B = 2*0 + (-1)*4 + 3*(-2) = 0 - 4 - 6 = -10.

A · B = 4*0 + 0*5 + (-3)*2 = 0 - 6 = -6.

K · L = 0*1 + 1*0 + 0*1 = 0 + 0 + 0 = 0.

Scalar projection = (3*1 + 4*0) / √(1^2) = 3

Scalar projection = (A · B) / |B| = (3*1 + 4*0) / 1 = 3.

Scalar triple product = (1, 2, 3) · ((4, 5, 6) × (7, 8, 9)) = 0.

Scalar triple product = A · (B × C) = 1.

Scalar triple product = a · (b × c). Since b and c are linearly dependent, b × c = 0, hence the scalar triple product is 0.

Using the product rule and chain rule, the second derivative is f''(x) = e^x (sin(x) + cos(x)).

The second derivative f''(x) = e^x.

f''(x) = 12x - 12.

A liquid droplet takes a spherical shape because a sphere has the minimum surface area for a given volume, minimizing the energy associated with surface tension.

AX3E indicates three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.

Ammonia has a trigonal pyramidal shape due to the presence of a lone pair on the nitrogen atom.

The d orbitals have a double dumbbell shape.