200 unread emails / 25 emails/day = 8 days.

At 10 Mbps, it takes approximately 40 seconds to download 50 MB.

In 5 hours, the user receives 50 emails. Reading 50 emails at 2 minutes each takes 100 minutes, which is 1 hour and 40 minutes, or approximately 2 hours.

50 received - 10 deleted = 40 emails left.

Remaining emails = 50 received - 20 deleted = 30 emails.

10 emails/day * 30 days = 300 emails.

Total size = 10 emails * 2 MB = 20 MB.

The total size of the email sent is 2 MB, regardless of the number of recipients.

The probability of infection after vaccination = Initial probability × (1 - reduction) = 0.2 × (1 - 0.75) = 0.2 × 0.25 = 0.05.

The new probability of infection after vaccination = Initial probability × (1 - reduction) = 0.1 × (1 - 0.75) = 0.1 × 0.25 = 0.025.

Using the formula: a = (v - u) / t = (60 - 0) / 12 = 5 m/s².

Total distance = 100 km + 50 km = 150 km; Total time = 2 h + 1 h = 3 h. Average speed = Total distance / Total time = 150 km / 3 h = 50 km/h.

Average Speed = Total Distance/Total Time = 120 km/2 h = 60 km/h

Speed = Distance / Time = 90 km / 1.5 hours = 60 km/h.

Range of possible volumes = 200 - 5 to 200 + 5 = 195 L to 205 L.

Wave speed = frequency × wavelength = 50 Hz × 2 m = 100 m/s.

Wave speed (v) can be calculated using the formula v = fλ. Here, v = 50 Hz * 3 m = 150 m/s.

The speed of a wave can be calculated using the formula v = f × λ. Here, v = 50 Hz × 4 m = 200 m/s.

Period (T) = 1/Frequency = 1/50 Hz = 0.02 s.

Using the wave equation v = fλ, we can rearrange it to find λ = v/f. Thus, λ = 300 m/s / 150 Hz = 2 m.

Total loading time = 5 pages * 3 seconds/page = 15 seconds.

Maximum true weight = Measured weight + Error = 10 kg + 0.2 kg = 10.2 kg.

The leading zeros are not significant. Therefore, 0.050 kg has 2 significant figures.

The distance traveled by the center of mass after one complete rotation is equal to the circumference of the wheel, which is 2πR.

Energy produced = 2 MW * 10 hours = 20 MWh

Ratio = 2500:1500 = 5:3.

Power is given by P = I^2 * R. Here, P = (3 A)^2 * 2 Ω = 9 * 2 = 18 W.

Power (P) is given by P = I^2 * R. Thus, P = (4 A)^2 * 2 Ω = 16 W.

Using the formula F = BIL, where B is the magnetic field, I is the current, and L is the length of the wire (1 m), F = 0.1 T * 5 A * 1 m = 0.5 N.

Using Ampere's Law, B = μ₀I/2πr, where μ₀ = 4π × 10^-7 Tm/A, we find B = (4π × 10^-7)(5)/(2π(0.1)) = 0.1 T.