The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions? Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers? Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions? Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the result of 5.00 - 2.1, considering significant figures?
A.
2.90
B.
2.9
C.
2.8
D.
2.80
Solution
When subtracting, the result should be rounded to the least number of decimal places. 5.00 has two decimal places and 2.1 has one, so the result should be rounded to one decimal place: 5.00 - 2.1 = 2.90 becomes 2.9.
Q. What is the result of adding 12.11 and 0.3, considering significant figures?
A.
12.41
B.
12.4
C.
12.5
D.
12.3
Solution
When adding, the result should be rounded to the least number of decimal places. 12.11 has two decimal places and 0.3 has one, so the result should be rounded to one decimal place: 12.41 becomes 12.4.
Q. What is the result of dividing 100.0 by 4.00, considering significant figures?
A.
25.0
B.
25
C.
25.00
D.
24.99
Solution
In division, the result should have the same number of significant figures as the measurement with the least significant figures. 100.0 has 4 significant figures and 4.00 has 3 significant figures, so the answer should be 25.0 with 3 significant figures.
Q. What is the result of dividing 6.38 by 2.0, considering significant figures?
A.
3.19
B.
3.2
C.
3.0
D.
3.5
Solution
In division, the result should have the same number of significant figures as the measurement with the least significant figures. 6.38 has 3 significant figures and 2.0 has 2 significant figures, so the answer should be rounded to 2 significant figures: 3.19 becomes 3.2.
Q. What is the result of dividing 8.0 by 2.00, considering significant figures?
A.
4.0
B.
4
C.
4.00
D.
4.000
Solution
In division, the result should have the same number of significant figures as the measurement with the least significant figures. 8.0 has 2 significant figures and 2.00 has 3 significant figures, so the answer should be 4.0 (2 significant figures).
Q. What is the result of multiplying 6.02 x 10^23 by 3.0, considering significant figures?
A.
1.8 x 10^24
B.
1.806 x 10^24
C.
1.80 x 10^24
D.
1.8060 x 10^24
Solution
In multiplication, the result should have the same number of significant figures as the factor with the least significant figures. 6.02 x 10^23 has 3 significant figures and 3.0 has 2, so the answer should be 1.8 x 10^24.
Q. What is the result of subtracting 5.00 from 10.0, considering significant figures?
A.
5.0
B.
5
C.
5.00
D.
5.000
Solution
In subtraction, the result should be rounded to the least number of decimal places. 10.0 has one decimal place and 5.00 has two, so the result should be rounded to one decimal place: 5.0.
Q. What is the result of subtracting 5.678 from 10.0, considering significant figures?
A.
4.32
B.
4.3
C.
4.4
D.
4.00
Solution
In subtraction, the result should be rounded to the least number of decimal places. 10.0 has one decimal place and 5.678 has three, so the result should be rounded to one decimal place: 4.32 becomes 4.3.
Q. What is the RMS speed of an ideal gas in terms of its temperature and molar mass?
A.
sqrt((3RT)/M)
B.
sqrt((2RT)/M)
C.
sqrt((RT)/M)
D.
sqrt((3M)/RT)
Solution
The RMS speed (v_rms) of an ideal gas is given by the formula v_rms = sqrt((3RT)/M), where R is the universal gas constant, T is the absolute temperature, and M is the molar mass.
Q. What is the RMS speed of an ideal gas in terms of temperature and molar mass?
A.
sqrt((3RT)/M)
B.
sqrt((RT)/M)
C.
sqrt((3kT)/m)
D.
sqrt((2RT)/M)
Solution
The RMS speed (v_rms) of an ideal gas is given by the formula v_rms = sqrt((3RT)/M), where R is the universal gas constant, T is the temperature in Kelvin, and M is the molar mass.
