Engineering Entrance Exam Preparation Resources

Engineering Entrance

MHT-CET

Q. If 0.1 M acetic acid has a pH of 2.87, what is the concentration of H+ ions?

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 0.5 M

Solution

[H+] = 10^(-pH) = 10^(-2.87) ≈ 0.001 M.

Correct Answer: B — 0.01 M

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Q. If 0.5 moles of a gas occupy 12 liters at STP, what is the molar volume of the gas? (2023)

A. 22.4 L
B. 24 L
C. 12 L
D. 6 L

Solution

At STP, 1 mole of any gas occupies 22.4 L. Therefore, 0.5 moles occupy 0.5 x 22.4 L = 11.2 L, confirming the molar volume is 22.4 L.

Correct Answer: A — 22.4 L

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Q. If 0.5 moles of a gas occupy 12.2 liters at STP, what is the molar volume of the gas? (2023)

A. 22.4 L
B. 24 L
C. 12.2 L
D. 6.1 L

Solution

At STP, 1 mole of gas occupies 22.4 liters. Therefore, the molar volume is 22.4 L.

Correct Answer: A — 22.4 L

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Q. If 1 kg of water is heated from 25°C to 75°C, how much heat is absorbed? (Specific heat of water = 4.2 J/g°C) (2021)

A. 21000 J
B. 42000 J
C. 84000 J
D. 105000 J

Solution

Q = mcΔT = (1000 g)(4.2 J/g°C)(50°C) = 210000 J.

Correct Answer: B — 42000 J

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Q. If 1 mole of a gas occupies 22.4 liters at STP, how many liters will 0.5 moles occupy? (2023)

A. 11.2 L
B. 22.4 L
C. 44.8 L
D. 5.6 L

Solution

At STP, 1 mole of gas occupies 22.4 L. Therefore, 0.5 moles will occupy 0.5 x 22.4 L = 11.2 L.

Correct Answer: A — 11.2 L

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Q. If 10 g of glucose (C6H12O6) is dissolved in 200 g of water, what is the mass percentage of the solution? (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percentage = (mass of solute / mass of solution) x 100. Mass of solution = 10 g + 200 g = 210 g. Mass percentage = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: A — 4.76%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the sugar solution? (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percent = (mass of solute / mass of solution) x 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: A — 4.76%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (Molar mass of sugar = 342 g/mol) (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percent = (mass of solute / mass of solution) x 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: B — 5.00%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 20.00%

Solution

Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.

Correct Answer: B — 5.00%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percentage of the solution? (Molar mass of sugar = 342 g/mol) (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percentage = (mass of solute / mass of solution) x 100. Mass of solution = 10 g + 200 g = 210 g. Mass percentage = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: B — 5.00%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percentage of the sugar solution? (Molar mass of sugar = 342 g/mol) (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percentage = (mass of solute / mass of solution) x 100. Mass of solution = 10 g + 200 g = 210 g. Mass percentage = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: A — 4.76%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the sugar solution? (Molar mass of sugar = 342 g/mol) (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.

Correct Answer: A — 4.76%

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Q. If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of sugar in the solution? (Molar mass of sugar = 342 g/mol) (2023)

A. 4.76%
B. 5.00%
C. 10.00%
D. 2.50%

Solution

Mass percent = (mass of solute / total mass of solution) x 100. Total mass = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) x 100 = 4.76%.

Correct Answer: A — 4.76%

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Q. If 10 g of sugar is dissolved in 100 g of water, what is the mass percent of sugar in the solution? (2023)

A. 10%
B. 5%
C. 20%
D. 15%

Solution

Mass percent = (mass of solute / total mass of solution) x 100. Total mass = 10 g + 100 g = 110 g. Mass percent = (10 g / 110 g) x 100 = 9.09%, approximately 10%.

Correct Answer: A — 10%

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Q. If 10 g of sugar is dissolved in 100 g of water, what is the mass percentage of sugar in the solution? (2023)

A. 10%
B. 5%
C. 20%
D. 15%

Solution

Mass percentage = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 100 g = 110 g. Mass percentage = (10 g / 110 g) × 100 = 9.09%, approximately 10%.

Correct Answer: A — 10%

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Q. If 10 grams of NaCl is dissolved in 500 mL of water, what is the concentration in g/L? (2020)

A. 20 g/L
B. 10 g/L
C. 5 g/L
D. 15 g/L

Solution

Concentration = (10 g / 0.5 L) = 20 g/L.

Correct Answer: A — 20 g/L

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Q. If 10 grams of NaCl is dissolved in 500 mL of water, what is the mass/volume percent concentration? (2020) 2020

A. 2%
B. 5%
C. 10%
D. 20%

Solution

Mass/volume % = (mass of solute / volume of solution) * 100 = (10 g / 500 mL) * 100 = 2%.

Correct Answer: B — 5%

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Q. If 1000 J of heat is added to a gas and it expands doing 400 J of work, what is the change in internal energy? (2023)

A. 600 J
B. 400 J
C. 1000 J
D. 200 J

Solution

Using the first law of thermodynamics: ΔU = Q - W = 1000 J - 400 J = 600 J.

Correct Answer: A — 600 J

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Q. If 1000 J of heat is added to a system and 400 J of work is done by the system, what is the change in internal energy of the system? (2021)

A. 600 J
B. 400 J
C. 1000 J
D. 200 J

Solution

Using the first law of thermodynamics: ΔU = Q - W = 1000 J - 400 J = 600 J.

Correct Answer: A — 600 J

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Q. If 1000 J of heat is added to a system and it does 400 J of work, what is the change in internal energy? (2021)

A. 600 J
B. 400 J
C. 1000 J
D. 1400 J

Solution

Using the first law of thermodynamics, ΔU = Q - W = 1000 J - 400 J = 600 J.

Correct Answer: A — 600 J

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Q. If 15 g of sugar is dissolved in 300 mL of water, what is the concentration in g/mL? (2020)

A. 0.05 g/mL
B. 0.1 g/mL
C. 0.15 g/mL
D. 0.2 g/mL

Solution

Concentration = mass / volume = 15 g / 300 mL = 0.05 g/mL.

Correct Answer: B — 0.1 g/mL

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Q. If 20 grams of glucose (C6H12O6) is dissolved in 1 liter of water, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol) (2020) 2020

A. 0.11 M
B. 0.5 M
C. 0.2 M
D. 0.33 M

Solution

Moles of glucose = 20 g / 180 g/mol = 0.111 M. Molarity = 0.111 moles / 1 L = 0.11 M.

Correct Answer: A — 0.11 M

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Q. If 200 g of water at 80°C is mixed with 300 g of water at 20°C, what will be the final temperature of the mixture? (Assume no heat loss to the surroundings)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the formula m1c1T1 + m2c2T2 = (m1 + m2)cTfinal, we find Tfinal = 40°C.

Correct Answer: B — 40°C

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Q. If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy? (2023)

A. 150 J
B. 250 J
C. 200 J
D. 100 J

Solution

According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.

Correct Answer: A — 150 J

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Q. If 200 J of heat is added to a system and 50 J of work is done by the system, what is the change in internal energy of the system?

A. 150 J
B. 250 J
C. 200 J
D. 100 J

Solution

According to the first law of thermodynamics, ΔU = Q - W = 200 J - 50 J = 150 J.

Correct Answer: A — 150 J

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Q. If 2000 J of heat is added to a system and 500 J of work is done by the system, what is the change in internal energy of the system? (2021)

A. 1500 J
B. 2000 J
C. 2500 J
D. 3000 J

Solution

Using the first law of thermodynamics: ΔU = Q - W = 2000 J - 500 J = 1500 J.

Correct Answer: A — 1500 J

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Q. If 2x = 10, what is the value of x? (2015)

A. 5
B. 10
C. 2
D. 20

Solution

Dividing both sides by 2 gives x = 10/2 = 5.

Correct Answer: A — 5

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Q. If 3 moles of glucose are dissolved in 1 liter of solution, what is the molality of the solution? (2023)

A. 3 m
B. 1 m
C. 2 m
D. 0.5 m

Solution

Molality (m) = moles of solute / kg of solvent; assuming 1 L of water = 1 kg, m = 3 moles / 1 kg = 3 m

Correct Answer: A — 3 m

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Q. If 3x = 12, what is the value of x? (2019)

A. 3
B. 4
C. 5
D. 2

Solution

x = 12 / 3 = 4.

Correct Answer: B — 4

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Q. If 50 mL of 0.1 M H2SO4 is diluted to 250 mL, what is the new concentration?

A. 0.02 M
B. 0.04 M
C. 0.1 M
D. 0.5 M

Solution

C1V1 = C2V2; (0.1 M)(50 mL) = C2(250 mL); C2 = 0.02 M.

Correct Answer: B — 0.04 M

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Engineering Entrance

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