JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the rate law expression for a reaction with the rate equation rate = k[A]^2[B]?
A.
rate = k[A][B]
B.
rate = k[A]^2
C.
rate = k[A]^2[B]
D.
rate = k[B]
Show solution
Solution
The rate law expression is derived directly from the rate equation, which is given as rate = k[A]^2[B].
Correct Answer:
C
— rate = k[A]^2[B]
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Q. What is the real part of the complex number 5 - 7i?
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Solution
The real part of 5 - 7i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 2e^(iπ/3)?
Show solution
Solution
The real part is 2 * cos(π/3) = 2 * 1/2 = 1.
Correct Answer:
B
— 2
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Q. What is the real part of the complex number z = 4e^(iπ/3)?
Show solution
Solution
The real part is Re(z) = 4 * cos(π/3) = 4 * 1/2 = 2.
Correct Answer:
C
— 2√3
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Q. What is the real part of the complex number z = 5 - 2i?
Show solution
Solution
The real part of z = 5 - 2i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5 - 4i?
Show solution
Solution
The real part of z = 5 - 4i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5 - 6i?
Show solution
Solution
The real part of z = 5 - 6i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5e^(iπ/3)?
A.
5/2
B.
5/√3
C.
5√3/2
D.
5
Show solution
Solution
The real part is Re(z) = 5cos(π/3) = 5 * 1/2 = 5/2.
Correct Answer:
A
— 5/2
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Q. What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?
A.
MnO4-
B.
C2O4^2-
C.
H+
D.
CO2
Show solution
Solution
C2O4^2- is the reducing agent as it donates electrons.
Correct Answer:
B
— C2O4^2-
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Q. What is the reducing agent in the reaction Zn + CuSO4 → ZnSO4 + Cu?
A.
Zn
B.
Cu
C.
CuSO4
D.
ZnSO4
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Solution
Zinc (Zn) is the reducing agent as it donates electrons to copper.
Correct Answer:
A
— Zn
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Q. What is the reduction half-reaction for the conversion of MnO4- to Mn2+ in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 5e- → Mn2+ + 8H+ + 4H2O
C.
MnO4- + 4H2O + 5e- → Mn2+ + 8H+
D.
MnO4- + 5e- + 4H2O → Mn2+ + 8H+
Show solution
Solution
The correct reduction half-reaction in acidic medium is MnO4- + 8H+ + 5e- → Mn2+ + 4H2O.
Correct Answer:
A
— MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction 2MnO4- + 16H+ + 10e- → 2Mn2+ + 8H2O?
A.
MnO4- + 8H2O + 10e- → Mn2+ + 16H+
B.
MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
C.
MnO4- + 10e- → Mn2+ + 8H2O
D.
MnO4- + 16H+ → Mn2+ + 10e- + 8H2O
Show solution
Solution
The correct reduction half-reaction shows the gain of electrons and protons.
Correct Answer:
B
— MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction of copper(II) ions with zinc?
A.
Cu^2+ + 2e^- → Cu
B.
Zn → Zn^2+ + 2e^-
C.
Cu → Cu^2+ + 2e^-
D.
Zn^2+ + 2e^- → Zn
Show solution
Solution
The reduction half-reaction is Cu^2+ + 2e^- → Cu.
Correct Answer:
A
— Cu^2+ + 2e^- → Cu
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Q. What is the reduction half-reaction for the reaction of MnO4- in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 3e- → MnO2 + 2H2O
C.
MnO4- + 2e- → MnO2 + 4H+
D.
MnO4- + 4e- + 8H+ → MnO2 + 4H2O
Show solution
Solution
In acidic medium, MnO4- is reduced to Mn2+.
Correct Answer:
A
— MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30°?
A.
1.00
B.
1.15
C.
1.73
D.
2.00
Show solution
Solution
Using the formula n = 1/sin(θc), where θc = 30°, we find n = 1/sin(30°) = 1/0.5 = 2.00.
Correct Answer:
C
— 1.73
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30° when light travels to air?
A.
1.73
B.
1.00
C.
1.41
D.
1.50
Show solution
Solution
Using sin(30°) = 0.5, n = 1/sin(30°) = 1/0.5 = 2. Therefore, the refractive index is 2.
Correct Answer:
A
— 1.73
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Q. What is the relationship between angular momentum L and moment of inertia I for a rotating object?
A.
L = Iω
B.
L = I²ω
C.
L = ω/I
D.
L = I + ω
Show solution
Solution
Angular momentum L is given by L = Iω, where ω is the angular velocity.
Correct Answer:
A
— L = Iω
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Q. What is the relationship between bulk modulus and compressibility?
A.
Bulk modulus is the inverse of compressibility
B.
Bulk modulus is equal to compressibility
C.
Bulk modulus is the square of compressibility
D.
There is no relationship
Show solution
Solution
Bulk modulus is defined as the reciprocal of compressibility, indicating how incompressible a material is.
Correct Answer:
A
— Bulk modulus is the inverse of compressibility
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Q. What is the relationship between Celsius and Kelvin?
A.
K = C + 273.15
B.
K = C - 273.15
C.
C = K + 273.15
D.
C = K - 273.15
Show solution
Solution
The relationship is K = C + 273.15, where K is the temperature in Kelvin and C is the temperature in Celsius.
Correct Answer:
A
— K = C + 273.15
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Q. What is the relationship between current and magnetic field in a long straight conductor?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The magnetic field around a long straight conductor is directly proportional to the current flowing through it.
Correct Answer:
A
— Directly proportional
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Q. What is the relationship between current, voltage, and resistance in an electrical circuit?
A.
Ohm's Law
B.
Kirchhoff's Law
C.
Faraday's Law
D.
Ampere's Law
Show solution
Solution
Ohm's Law defines the relationship between current (I), voltage (V), and resistance (R) as V = IR.
Correct Answer:
A
— Ohm's Law
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Q. What is the relationship between electric field and electric potential?
A.
E = -dV/dr
B.
E = dV/dr
C.
E = V/r
D.
E = V^2
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dr.
Correct Answer:
A
— E = -dV/dr
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Q. What is the relationship between electric field E and electric potential V?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and potential V in a uniform electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V/dx
Show solution
Solution
In a uniform electric field, the relationship is given by E = -dV/dx, indicating that the electric field points in the direction of decreasing potential.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and potential V in electrostatics?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V
Show solution
Solution
The electric field is the negative gradient of the electric potential, E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and surface charge density σ on a conductor?
A.
E = σ/ε₀
B.
E = σ/2ε₀
C.
E = 2σ/ε₀
D.
E = σ/4ε₀
Show solution
Solution
The electric field just outside a charged conductor is given by E = σ/ε₀.
Correct Answer:
A
— E = σ/ε₀
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Q. What is the relationship between electric potential (V) and electric field (E) in a uniform field?
A.
V = E × d
B.
V = E/d
C.
E = V × d
D.
E = V/d
Show solution
Solution
In a uniform electric field, the electric potential difference V is given by V = E × d, where d is the distance moved in the direction of the field.
Correct Answer:
A
— V = E × d
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Q. What is the relationship between electric potential and electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, expressed as E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between enthalpy (H), internal energy (U), and pressure-volume work (PV)?
A.
H = U + PV
B.
H = U - PV
C.
H = U * PV
D.
H = U / PV
Show solution
Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, and PV is the pressure-volume work.
Correct Answer:
A
— H = U + PV
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Q. What is the relationship between enthalpy (H), internal energy (U), pressure (P), and volume (V)?
A.
H = U + PV
B.
H = U - PV
C.
H = U + P/V
D.
H = U - P/V
Show solution
Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, P is pressure, and V is volume.
Correct Answer:
A
— H = U + PV
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