Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the rate law expression for a reaction with the rate equation rate = k[A]^2[B]?
A.
rate = k[A][B]
B.
rate = k[A]^2
C.
rate = k[A]^2[B]
D.
rate = k[B]
Show solution
Solution
The rate law expression is derived directly from the rate equation, which is given as rate = k[A]^2[B].
Correct Answer:
C
— rate = k[A]^2[B]
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Q. What is the real part of the complex number 5 - 7i?
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Solution
The real part of 5 - 7i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 2e^(iπ/3)?
Show solution
Solution
The real part is 2 * cos(π/3) = 2 * 1/2 = 1.
Correct Answer:
B
— 2
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Q. What is the real part of the complex number z = 4e^(iπ/3)?
Show solution
Solution
The real part is Re(z) = 4 * cos(π/3) = 4 * 1/2 = 2.
Correct Answer:
C
— 2√3
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Q. What is the real part of the complex number z = 5 - 2i?
Show solution
Solution
The real part of z = 5 - 2i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5 - 4i?
Show solution
Solution
The real part of z = 5 - 4i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5 - 6i?
Show solution
Solution
The real part of z = 5 - 6i is 5.
Correct Answer:
A
— 5
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Q. What is the real part of the complex number z = 5e^(iπ/3)?
A.
5/2
B.
5/√3
C.
5√3/2
D.
5
Show solution
Solution
The real part is Re(z) = 5cos(π/3) = 5 * 1/2 = 5/2.
Correct Answer:
A
— 5/2
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Q. What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?
A.
MnO4-
B.
C2O4^2-
C.
H+
D.
CO2
Show solution
Solution
C2O4^2- is the reducing agent as it donates electrons.
Correct Answer:
B
— C2O4^2-
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Q. What is the reducing agent in the reaction Zn + CuSO4 → ZnSO4 + Cu?
A.
Zn
B.
Cu
C.
CuSO4
D.
ZnSO4
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Solution
Zinc (Zn) is the reducing agent as it donates electrons to copper.
Correct Answer:
A
— Zn
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Q. What is the reduction half-reaction for the conversion of MnO4- to Mn2+ in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 5e- → Mn2+ + 8H+ + 4H2O
C.
MnO4- + 4H2O + 5e- → Mn2+ + 8H+
D.
MnO4- + 5e- + 4H2O → Mn2+ + 8H+
Show solution
Solution
The correct reduction half-reaction in acidic medium is MnO4- + 8H+ + 5e- → Mn2+ + 4H2O.
Correct Answer:
A
— MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction 2MnO4- + 16H+ + 10e- → 2Mn2+ + 8H2O?
A.
MnO4- + 8H2O + 10e- → Mn2+ + 16H+
B.
MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
C.
MnO4- + 10e- → Mn2+ + 8H2O
D.
MnO4- + 16H+ → Mn2+ + 10e- + 8H2O
Show solution
Solution
The correct reduction half-reaction shows the gain of electrons and protons.
Correct Answer:
B
— MnO4- + 10e- + 8H+ → Mn2+ + 4H2O
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Q. What is the reduction half-reaction for the reaction of copper(II) ions with zinc?
A.
Cu^2+ + 2e^- → Cu
B.
Zn → Zn^2+ + 2e^-
C.
Cu → Cu^2+ + 2e^-
D.
Zn^2+ + 2e^- → Zn
Show solution
Solution
The reduction half-reaction is Cu^2+ + 2e^- → Cu.
Correct Answer:
A
— Cu^2+ + 2e^- → Cu
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Q. What is the reduction half-reaction for the reaction of MnO4- in acidic medium?
A.
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
B.
MnO4- + 3e- → MnO2 + 2H2O
C.
MnO4- + 2e- → MnO2 + 4H+
D.
MnO4- + 4e- + 8H+ → MnO2 + 4H2O
Show solution
Solution
In acidic medium, MnO4- is reduced to Mn2+.
Correct Answer:
A
— MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30°?
A.
1.00
B.
1.15
C.
1.73
D.
2.00
Show solution
Solution
Using the formula n = 1/sin(θc), where θc = 30°, we find n = 1/sin(30°) = 1/0.5 = 2.00.
Correct Answer:
C
— 1.73
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Q. What is the refractive index of a medium if the critical angle for total internal reflection is 30° when light travels to air?
A.
1.73
B.
1.00
C.
1.41
D.
1.50
Show solution
Solution
Using sin(30°) = 0.5, n = 1/sin(30°) = 1/0.5 = 2. Therefore, the refractive index is 2.
Correct Answer:
A
— 1.73
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Q. What is the relationship between angular momentum L and moment of inertia I for a rotating object?
A.
L = Iω
B.
L = I²ω
C.
L = ω/I
D.
L = I + ω
Show solution
Solution
Angular momentum L is given by L = Iω, where ω is the angular velocity.
Correct Answer:
A
— L = Iω
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Q. What is the relationship between bulk modulus and compressibility?
A.
Bulk modulus is the inverse of compressibility
B.
Bulk modulus is equal to compressibility
C.
Bulk modulus is the square of compressibility
D.
There is no relationship
Show solution
Solution
Bulk modulus is defined as the reciprocal of compressibility, indicating how incompressible a material is.
Correct Answer:
A
— Bulk modulus is the inverse of compressibility
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Q. What is the relationship between Celsius and Kelvin?
A.
K = C + 273.15
B.
K = C - 273.15
C.
C = K + 273.15
D.
C = K - 273.15
Show solution
Solution
The relationship is K = C + 273.15, where K is the temperature in Kelvin and C is the temperature in Celsius.
Correct Answer:
A
— K = C + 273.15
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Q. What is the relationship between current and magnetic field in a long straight conductor?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential
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Solution
The magnetic field around a long straight conductor is directly proportional to the current flowing through it.
Correct Answer:
A
— Directly proportional
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Q. What is the relationship between current, voltage, and resistance in an electrical circuit?
A.
Ohm's Law
B.
Kirchhoff's Law
C.
Faraday's Law
D.
Ampere's Law
Show solution
Solution
Ohm's Law defines the relationship between current (I), voltage (V), and resistance (R) as V = IR.
Correct Answer:
A
— Ohm's Law
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Q. What is the relationship between electric field and electric potential?
A.
E = -dV/dr
B.
E = dV/dr
C.
E = V/r
D.
E = V^2
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dr.
Correct Answer:
A
— E = -dV/dr
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Q. What is the relationship between electric field E and electric potential V?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, given by E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and potential V in a uniform electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V/dx
Show solution
Solution
In a uniform electric field, the relationship is given by E = -dV/dx, indicating that the electric field points in the direction of decreasing potential.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and potential V in electrostatics?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/dx
D.
E = -V
Show solution
Solution
The electric field is the negative gradient of the electric potential, E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between electric field E and surface charge density σ on a conductor?
A.
E = σ/ε₀
B.
E = σ/2ε₀
C.
E = 2σ/ε₀
D.
E = σ/4ε₀
Show solution
Solution
The electric field just outside a charged conductor is given by E = σ/ε₀.
Correct Answer:
A
— E = σ/ε₀
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Q. What is the relationship between electric potential (V) and electric field (E) in a uniform field?
A.
V = E × d
B.
V = E/d
C.
E = V × d
D.
E = V/d
Show solution
Solution
In a uniform electric field, the electric potential difference V is given by V = E × d, where d is the distance moved in the direction of the field.
Correct Answer:
A
— V = E × d
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Q. What is the relationship between electric potential and electric field?
A.
E = -dV/dx
B.
E = dV/dx
C.
E = V/d
D.
E = -V/d
Show solution
Solution
The electric field E is the negative gradient of the electric potential V, expressed as E = -dV/dx.
Correct Answer:
A
— E = -dV/dx
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Q. What is the relationship between enthalpy (H), internal energy (U), and pressure-volume work (PV)?
A.
H = U + PV
B.
H = U - PV
C.
H = U * PV
D.
H = U / PV
Show solution
Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, and PV is the pressure-volume work.
Correct Answer:
A
— H = U + PV
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Q. What is the relationship between enthalpy (H), internal energy (U), pressure (P), and volume (V)?
A.
H = U + PV
B.
H = U - PV
C.
H = U + P/V
D.
H = U - P/V
Show solution
Solution
The relationship is given by H = U + PV, where H is enthalpy, U is internal energy, P is pressure, and V is volume.
Correct Answer:
A
— H = U + PV
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