4x - 1 ≤ 3x + 2 => x ≤ 3.

4x - 5 < 3x + 2 => x < 7.

4x - 5 ≥ 3 => 4x ≥ 8 => x ≥ 2.

4x - 7 < 9 => 4x < 16 => x < 4.

Subtract 5 from both sides: -2x < -4. Then divide by -2 (reverse the inequality): x > 2.

5 - 2x ≤ 1 => -2x ≤ -4 => x ≥ 2.

5 - 2x ≤ 3 => -2x ≤ -2 => x ≥ 1.

6 - 3x ≥ 0 => -3x ≥ -6 => x ≤ 2.

6x + 2 < 14 => 6x < 12 => x < 2.

6x + 2 ≤ 14 => 6x ≤ 12 => x ≤ 2.

6x + 4 < 2x + 20 => 4x < 16 => x < 4.

6x + 4 ≤ 2x + 16 => 4x ≤ 12 => x ≤ 3.

7 - 3x > 1 => -3x > -6 => x < 2.

7 - 3x < 1 => -3x < -6 => x > 2.

7x + 2 > 5 => 7x > 3 => x > 0.5.

7x + 2 > 5x + 6 => 2x > 4 => x > 2.

7x + 2 < 5 => 7x < 3 => x < -1.

7x + 3 > 24 => 7x > 21 => x > 3.

7x + 5 < 2x + 20 => 5x < 15 => x < 3.

7x - 4 < 3x + 8 => 4x < 12 => x < 3.

8 - 2x > 0 => -2x > -8 => x < 4.

x/2 - 1 ≤ 3 => x/2 ≤ 4 => x ≤ 8.

x/3 - 2 ≤ 1 => x/3 ≤ 3 => x ≤ 9.

The sum of the coefficients is found by substituting x = 1: (2 + 3*1)^4 = 5^4 = 625.

The sum of the coefficients is found by substituting x = 1, so (1 + 1)^5 = 2^5 = 32.

The sum of the coefficients is found by substituting x = 1, giving (1 + 1)^7 = 2^7 = 128.

The sum is (2 + 4) + (3 - 5)i = 6 - 2i.

S_5 = 1 + 1/2 + 1/4 + 1/8 + 1/16 = 1.5.

The sum S_n = n/2 * (2a + (n-1)d) = 6/2 * (2*10 + 5*5) = 3 * (20 + 25) = 135.

The first term a = 2, common difference d = 3. The sum of the first n terms S_n = n/2 * (2a + (n-1)d) = n/2 * (2 + (n-1) * 3).