Distance = Speed × Time = 60 km/h × 2.5 h = 150 km

Speed in m/s = (72 * 1000 m) / (3600 s) = 20 m/s.

Relative speed = 80 - 60 = 20 km/h. Distance apart after 1 hour = 20 km.

Relative speed = 80 - 60 = 20 km/h. Distance = speed * time = 20 * 2 = 40 km.

Time = Distance / Speed = 200 km / 80 km/h = 2.5 hours.

Time = Distance / Speed = 240 km / 80 km/h = 3 hours.

Time = Distance / Speed = 240 km / 80 km/h = 3 hours.

Time = Distance / Speed = 240 km / 80 km/h = 3 hours.

Minimum speed = Measured speed - Error = 60 - 2 = 58 km/h.

Absolute error = Relative error * Measured value = 0.05 * 60 = 3 km/h.

After the first year, the value is $25,000 - (20% of $25,000) = $20,000. After the second year, the value is $20,000 - (20% of $20,000) = $16,000.

After 1 year: $25,000 - (0.20 * 25,000) = $20,000. After 2 years: $20,000 - (0.20 * 20,000) = $16,000.

The depreciation amount is 20% of $20,000, which is $4,000. Therefore, the value after one year is $20,000 - $4,000 = $16,000.

Number of hearts = 13. Probability = 13/52 = 1/4.

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that it is red is 13/26 = 1/2.

There are 13 hearts and 4 queens, but one queen is a heart. So, the probability is (13 + 4 - 1)/52 = 16/52 = 4/13.

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that the card is red is 13/26 = 1/2.

There are 13 hearts in a deck of 52 cards. The probability of drawing a heart is 13/52 = 1/4.

There are 4 queens in a deck of 52 cards. Probability = 4/52 = 1/13.

There are 13 hearts and 4 queens, but one of the queens is a heart. Thus, the probability is (13 + 4 - 1)/52 = 16/52 = 4/13.

Using the Rule of 72, time = 72/r = 72/10 = 7.2 years.

Using A = P(1 + r)^t, we rearrange to find P = A / (1 + r)^t. Thus, P = 5000 / (1.12)^3 = $4000.

Using the formula A = P(1 + r)^n, we can set up the equation 3P = P(1 + r)^15. Solving for r gives approximately 6%.

The last term of an AP is given by a + (n-1)d. Here, 100 = 10 + (20-1)d. Solving gives d = 5.

The common difference d can be calculated using the formula for the nth term: a + (n-1)d = last term. Here, 12 + 9d = 48, solving gives d = 4.

The sum of the first n terms S_n = n/2 * (2a + (n-1)d). Here, S_10 = 10/2 * (2*7 + 9*2) = 5 * (14 + 18) = 5 * 32 = 160.

Population after 3 years = 200,000 * (1 - 0.10)^3 = 200,000 * 0.729 = 145,800.

Population after 1 year = 200,000 * (1 - 0.10) = 200,000 * 0.90 = 180,000.

Population after decrease = 200,000 * (1 - 0.10) = 200,000 * 0.90 = 180,000.

Amount allocated to primary education = 1,000,000 * 0.40 = $400,000.