Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. If a 4 kg object is moving with a constant velocity, what can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is maximum

Solution

According to Newton's first law, if an object is moving with constant velocity, the net force acting on it is zero.

Correct Answer: A — It is zero

Q. If a 4 kg object is moving with a speed of 5 m/s, what is its kinetic energy?

A. 50 J
B. 40 J
C. 100 J
D. 80 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 4 kg × (5 m/s)² = 0.5 × 4 × 25 = 50 J.

Correct Answer: D — 80 J

Q. If a 4 kg object is moving with a velocity of 5 m/s, what is the momentum of the object? (2020)

A. 10 kg m/s
B. 15 kg m/s
C. 20 kg m/s
D. 25 kg m/s

Solution

Momentum = mass × velocity = 4 kg × 5 m/s = 20 kg m/s.

Correct Answer: C — 20 kg m/s

Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (g = 9.8 m/s²)

A. 490 J
B. 980 J
C. 245 J
D. 2450 J

Solution

Potential Energy (PE) = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 980 J

Q. If a 5 kg object is dropped from a height of 10 m, what is its potential energy just before it hits the ground? (2021)

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

PE = m × g × h = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 100 J

Q. If a 5 kg object is dropped from a height of 20 m, what is its potential energy at the top? (2021)

A. 100 J
B. 200 J
C. 50 J
D. 150 J

Solution

Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approx. 1000 J)

Correct Answer: B — 200 J

Q. If a 5 kg object is in free fall, what is the force acting on it due to gravity?

A. 5 N
B. 10 N
C. 50 N
D. 15 N

Solution

The force due to gravity F = mg = 5 kg * 10 m/s² = 50 N.

Correct Answer: C — 50 N

Q. If a 5 kg object is lifted to a height of 10 m, what is the potential energy gained by the object? (g = 9.8 m/s²)

A. 490 J
B. 980 J
C. 245 J
D. 2450 J

Solution

Potential Energy = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 980 J

Q. If a 5 kg object is lifted to a height of 10 m, what is the work done against gravity? (g = 9.8 m/s²)

A. 49 J
B. 98 J
C. 490 J
D. 980 J

Solution

Work done = mgh = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: C — 490 J

Q. If a 5 kg object is lifted to a height of 10 m, what is the work done against gravity?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Work done = mgh = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: D — 200 J

Q. If a 5 kg object is lifted to a height of 2 m, what is the potential energy gained by the object? (Use g = 9.8 m/s²) (2020)

A. 49 J
B. 98 J
C. 19.6 J
D. 39.2 J

Solution

Potential Energy = mgh = 5 kg × 9.8 m/s² × 2 m = 98 J

Correct Answer: B — 98 J

Q. If a 5 kg object is moving with a speed of 10 m/s, what is its total mechanical energy assuming no potential energy?

A. 250 J
B. 500 J
C. 100 J
D. 50 J

Solution

Total Mechanical Energy = Kinetic Energy = 0.5 * m * v² = 0.5 * 5 kg * (10 m/s)² = 250 J.

Correct Answer: B — 500 J

Q. If a 5 kg object is moving with a velocity of 10 m/s, what is its kinetic energy? (2019)

A. 25 J
B. 50 J
C. 100 J
D. 200 J

Solution

Kinetic Energy = 0.5 × Mass × Velocity² = 0.5 × 5 kg × (10 m/s)² = 250 J.

Correct Answer: C — 100 J

Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its kinetic energy? (2023)

A. 22.5 J
B. 30 J
C. 45 J
D. 60 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 5 kg × (3 m/s)² = 22.5 J

Correct Answer: C — 45 J

Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its momentum? (2023)

A. 5 kg·m/s
B. 10 kg·m/s
C. 15 kg·m/s
D. 20 kg·m/s

Solution

Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.

Correct Answer: C — 15 kg·m/s

Q. If a 5 kg object is subjected to a force of 20 N, what is its acceleration?

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Using F = ma, acceleration a = F/m = 20 N / 5 kg = 4 m/s².

Correct Answer: B — 4 m/s²

Q. If a 5 kg object is subjected to a net force of 20 N, what is its acceleration? (2023)

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².

Correct Answer: B — 4 m/s²

Q. If a 5 ohm resistor and a 10 ohm resistor are connected in series, what is the voltage across the 10 ohm resistor when a current of 2 A flows through the circuit?

A. 10 V
B. 20 V
C. 5 V
D. 15 V

Solution

Voltage across the 10 ohm resistor, V = I * R = 2 A * 10 Ω = 20 V.

Correct Answer: B — 20 V

Q. If a 5 ohm resistor is connected to a 10V battery, what is the energy consumed in 2 seconds?

A. 10 J
B. 20 J
C. 5 J
D. 15 J

Solution

Power P = V^2 / R = 10^2 / 5 = 20 W. Energy = Power * time = 20 W * 2 s = 40 J.

Correct Answer: B — 20 J

Q. If a 5 ohm resistor is connected to a 10V battery, what is the energy consumed in 2 minutes?

A. 60 J
B. 120 J
C. 240 J
D. 30 J

Solution

Power P = V^2/R = 10^2 / 5 = 20 W. Energy = Power * time = 20 W * 120 s = 2400 J.

Correct Answer: B — 120 J

Q. If a 5Ω resistor is connected in parallel with a 10Ω resistor, what is the equivalent resistance?

A. 3.33Ω
B. 5Ω
C. 7.5Ω
D. 15Ω

Solution

R_eq = 1/(1/5 + 1/10) = 3.33Ω.

Correct Answer: A — 3.33Ω

Q. If a 5Ω resistor is connected in series with a 10Ω resistor, what is the total resistance? (2022)

A. 15Ω
B. 5Ω
C. 10Ω
D. 20Ω

Solution

In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.

Correct Answer: A — 15Ω

Q. If a 5Ω resistor is connected to a 10V source, what is the power dissipated? (2023)

A. 2W
B. 5W
C. 10W
D. 20W

Solution

Power P = V²/R = (10V)² / 5Ω = 100 / 5 = 20W.

Correct Answer: C — 10W

Q. If a 5Ω resistor is connected to a 15V battery, what is the power dissipated by the resistor? (2023)

A. 15W
B. 20W
C. 25W
D. 30W

Solution

Power (P) can be calculated using P = V^2 / R. Here, P = 15V^2 / 5Ω = 45W.

Correct Answer: C — 25W

Q. If a 6 kg object is subjected to a net force of 24 N, what is its acceleration?

A. 4 m/s²
B. 6 m/s²
C. 8 m/s²
D. 10 m/s²

Solution

Using F = ma, acceleration a = F/m = 24 N / 6 kg = 4 m/s².

Correct Answer: A — 4 m/s²

Q. If a 60W bulb operates at 120V, what is the resistance of the bulb?

A. 240 ohms
B. 120 ohms
C. 60 ohms
D. 30 ohms

Solution

Using P = V^2 / R, R = V^2 / P = (120V)^2 / 60W = 240 ohms.

Correct Answer: B — 120 ohms

Q. If a 60W light bulb operates at 120V, what is the resistance of the bulb?

A. 240 ohms
B. 120 ohms
C. 60 ohms
D. 30 ohms

Solution

Power (P) = V^2 / R, so R = V^2 / P = (120V)^2 / 60W = 240 ohms.

Correct Answer: B — 120 ohms

Q. If a 6V battery is connected to a circuit with a total resistance of 3 ohms, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Using Ohm's law, I = V/R = 6V / 3 ohms = 2A.

Correct Answer: B — 2A

Q. If a 6Ω and a 3Ω resistor are connected in parallel, what is the equivalent resistance? (2022)

A. 2Ω
B. 4Ω
C. 1.5Ω
D. 9Ω

Solution

Using the formula for parallel resistors: 1/R_eq = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6. Therefore, R_eq = 2Ω.

Correct Answer: A — 2Ω

Q. If a 6Ω resistor is connected in parallel with a 3Ω resistor, what is the equivalent resistance? (2023)

A. 2Ω
B. 1.5Ω
C. 4Ω
D. 9Ω

Solution

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.

Correct Answer: A — 2Ω

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