Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. If a 10 ohm resistor is connected to a 20V battery, what is the energy consumed in 5 seconds?
A.
20 J
B.
40 J
C.
10 J
D.
50 J
Show solution
Solution
Power P = V^2 / R = 20^2 / 10 = 40 W. Energy = Power * time = 40 W * 5 s = 200 J.
Correct Answer:
B
— 40 J
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Q. If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?
A.
15 J
B.
30 J
C.
75 J
D.
150 J
Show solution
Solution
Power P = V^2 / R = (30V)^2 / 10 ohms = 90 W. Energy = Power * Time = 90 W * 5 s = 450 J.
Correct Answer:
C
— 75 J
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Q. If a 10 ohm resistor is connected to a 5V battery, what is the current flowing through the resistor? (2020)
A.
0.5 A
B.
1 A
C.
2 A
D.
5 A
Show solution
Solution
Using Ohm's law, I = V/R = 5V / 10Ω = 0.5 A.
Correct Answer:
B
— 1 A
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Q. If a 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output of the car's engine?
A.
2000 W
B.
4000 W
C.
6000 W
D.
8000 W
Show solution
Solution
First, calculate the work done: W = 0.5 * m * v^2 = 0.5 * 1000 kg * (20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.
Correct Answer:
C
— 6000 W
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Q. If a 1000 kg car is moving at a speed of 15 m/s, what is its kinetic energy?
A.
112,500 J
B.
225,000 J
C.
150,000 J
D.
75,000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer:
B
— 225,000 J
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Q. If a 1000 kg car is moving at a speed of 36 km/h, what is its kinetic energy? (2021)
A.
500 J
B.
1000 J
C.
2000 J
D.
3000 J
Show solution
Solution
Convert speed to m/s: 36 km/h = 10 m/s. KE = 1/2 * m * v^2 = 1/2 * 1000 kg * (10 m/s)^2 = 50000 J.
Correct Answer:
C
— 2000 J
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Q. If a 1000 kg car is moving with a speed of 15 m/s, what is its kinetic energy?
A.
112,500 J
B.
225,000 J
C.
75,000 J
D.
150,000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J
Correct Answer:
B
— 225,000 J
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Q. If a 1000 W heater is used for 3 hours, how much energy does it consume in kilowatt-hours?
A.
3 kWh
B.
2 kWh
C.
1 kWh
D.
0.5 kWh
Show solution
Solution
Energy consumed in kilowatt-hours is calculated as E = P (kW) * t (h). Here, P = 1000 W = 1 kW and t = 3 hours. Thus, E = 1 kW * 3 h = 3 kWh.
Correct Answer:
A
— 3 kWh
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Q. If a 1000 W heater runs for 2 hours, how much energy does it consume?
A.
7200 J
B.
14400 J
C.
20000 J
D.
3600000 J
Show solution
Solution
Energy = Power × Time = 1000 W × (2 × 3600 s) = 7200000 J.
Correct Answer:
D
— 3600000 J
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Q. If a 1000 W motor runs for 2 hours, how much work does it do? (2000)
A.
7200 J
B.
2000 J
C.
3600000 J
D.
100000 J
Show solution
Solution
Work = Power × Time = 1000 W × (2 hours × 3600 s/hour) = 1000 W × 7200 s = 7200000 J
Correct Answer:
C
— 3600000 J
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Q. If a 100Ω resistor is connected in series with a 200Ω resistor, what is the total resistance? (2023)
A.
300Ω
B.
100Ω
C.
200Ω
D.
400Ω
Show solution
Solution
In series, R_total = R1 + R2 = 100Ω + 200Ω = 300Ω.
Correct Answer:
A
— 300Ω
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Q. If a 10Ω resistor carries a current of 2A, what is the voltage across the resistor? (2023)
A.
5V
B.
10V
C.
20V
D.
30V
Show solution
Solution
Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.
Correct Answer:
C
— 20V
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Q. If a 10Ω resistor carries a current of 5A, what is the voltage across the resistor? (2023)
A.
10V
B.
20V
C.
30V
D.
50V
Show solution
Solution
Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.
Correct Answer:
B
— 20V
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Q. If a 10Ω resistor is connected across a 20V battery, what is the power dissipated in the resistor? (2023)
A.
20W
B.
40W
C.
10W
D.
5W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40W.
Correct Answer:
B
— 40W
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2022)
A.
3.33Ω
B.
5Ω
C.
7.5Ω
D.
15Ω
Show solution
Solution
For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer:
A
— 3.33Ω
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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the total resistance? (2022)
A.
3.33Ω
B.
5Ω
C.
7.5Ω
D.
15Ω
Show solution
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.
Correct Answer:
A
— 3.33Ω
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Q. If a 10Ω resistor is connected to a 20V battery, what is the power consumed by the resistor? (2023)
A.
20W
B.
40W
C.
10W
D.
5W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20V^2 / 10Ω = 40W.
Correct Answer:
B
— 40W
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Q. If a 10Ω resistor is connected to a 20V battery, what is the power dissipated by the resistor?
A.
20W
B.
40W
C.
100W
D.
200W
Show solution
Solution
Power (P) can be calculated using P = V^2/R. Here, P = 20V^2 / 10Ω = 400 / 10 = 40W.
Correct Answer:
B
— 40W
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Q. If a 10Ω resistor is connected to a 20V source, what is the energy consumed in 5 seconds?
A.
20J
B.
40J
C.
50J
D.
100J
Show solution
Solution
Power P = V^2 / R = 20V^2 / 10Ω = 40W. Energy = Power * time = 40W * 5s = 200J.
Correct Answer:
B
— 40J
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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is increasing
Show solution
Solution
An object moving with constant velocity has a net force of zero according to Newton's first law.
Correct Answer:
A
— It is zero
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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 12 V battery is connected to a 4 ohm resistor, what is the current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
5 A
Show solution
Solution
Using Ohm's Law, I = V/R = 12 V / 4 ohm = 3 A.
Correct Answer:
B
— 3 A
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Q. If a 12 V battery is connected to a circuit with a resistance of 4 ohms, what is the current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
5 A
Show solution
Solution
Using Ohm's Law, I = V/R = 12 V / 4 ohm = 3 A.
Correct Answer:
A
— 2 A
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Q. If a 12 V battery is connected to a resistor of 4 ohms, what is the current flowing through the circuit?
A.
3 A
B.
4 A
C.
12 A
D.
0.33 A
Show solution
Solution
Using Ohm's Law (I = V/R), I = 12 V / 4 Ω = 3 A.
Correct Answer:
A
— 3 A
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Q. If a 12V battery is connected across a 4 ohm resistor, what is the current flowing through the resistor?
A.
2 A
B.
3 A
C.
4 A
D.
6 A
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3 A.
Correct Answer:
A
— 2 A
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Q. If a 12V battery is connected across a 4 ohm resistor, what is the power dissipated in the resistor?
A.
12 W
B.
24 W
C.
36 W
D.
48 W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 144 / 4 = 36 W.
Correct Answer:
B
— 24 W
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Q. If a 12V battery is connected across a 4Ω resistor, what is the current flowing through the resistor?
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer:
B
— 2A
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Q. If a 12V battery is connected to a 4 ohm resistor, what is the power dissipated by the resistor?
A.
12 W
B.
24 W
C.
36 W
D.
48 W
Show solution
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 36 W.
Correct Answer:
B
— 24 W
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Q. If a 1500 kg car is moving at a speed of 30 m/s, what is its kinetic energy?
A.
675,000 J
B.
450,000 J
C.
225,000 J
D.
900,000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (30 m/s)² = 675,000 J
Correct Answer:
B
— 450,000 J
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Q. If a 15Ω resistor is connected in parallel with a 30Ω resistor, what is the equivalent resistance? (2021)
A.
10Ω
B.
7.5Ω
C.
5Ω
D.
12Ω
Show solution
Solution
For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/15 + 1/30 = 2/30 + 1/30 = 3/30. Therefore, R_eq = 30/3 = 10Ω.
Correct Answer:
B
— 7.5Ω
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