Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the molecular geometry of BF3?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Bent
Show solution
Solution
BF3 has a trigonal planar geometry due to the three bonding pairs and no lone pairs on the central atom.
Correct Answer:
B
— Trigonal planar
Learn More →
Q. What is the molecular geometry of CH4 according to VSEPR theory?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
According to VSEPR theory, CH4 has four bonding pairs and no lone pairs, resulting in a tetrahedral geometry.
Correct Answer:
C
— Tetrahedral
Learn More →
Q. What is the molecular geometry of CH4?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
CH4 has a tetrahedral geometry due to four bonding pairs around the central carbon atom.
Correct Answer:
C
— Tetrahedral
Learn More →
Q. What is the molecular geometry of methane (CH4)?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
Methane has a tetrahedral molecular geometry due to sp3 hybridization of the carbon atom.
Correct Answer:
C
— Tetrahedral
Learn More →
Q. What is the molecular geometry of NH3 according to VSEPR theory?
A.
Trigonal planar
B.
Tetrahedral
C.
Bent
D.
Trigonal pyramidal
Show solution
Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal geometry.
Correct Answer:
D
— Trigonal pyramidal
Learn More →
Q. What is the molecular geometry of SF4?
A.
Tetrahedral
B.
Trigonal bipyramidal
C.
Seesaw
D.
Square planar
Show solution
Solution
SF4 has four bonding pairs and one lone pair, resulting in a seesaw molecular geometry.
Correct Answer:
C
— Seesaw
Learn More →
Q. What is the molecular geometry of SO2?
A.
Linear
B.
Trigonal planar
C.
Bent
D.
Tetrahedral
Show solution
Solution
SO2 has two bonding pairs and one lone pair, resulting in a bent molecular geometry.
Correct Answer:
C
— Bent
Learn More →
Q. What is the molecular geometry of the molecule with the electronic configuration of 1s2 2s2 2p2?
A.
Linear
B.
Trigonal Planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
The electronic configuration corresponds to C2, which has a tetrahedral geometry due to sp3 hybridization.
Correct Answer:
C
— Tetrahedral
Learn More →
Q. What is the molecular orbital configuration of F2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(π2p)⁴(π*2p)²
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Show solution
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
Learn More →
Q. What is the molecular orbital configuration of O2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)⁴
Show solution
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
Learn More →
Q. What is the molecular orbital configuration of the F2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Show solution
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
Learn More →
Q. What is the molecular orbital configuration of the O2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)²
Show solution
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
Learn More →
Q. What is the molecular shape of a molecule with the formula AX3E?
A.
Trigonal planar
B.
Tetrahedral
C.
Trigonal pyramidal
D.
Bent
Show solution
Solution
AX3E indicates three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer:
C
— Trigonal pyramidal
Learn More →
Q. What is the molecular shape of BF3 according to VSEPR theory?
A.
Bent
B.
Trigonal planar
C.
Tetrahedral
D.
Octahedral
Show solution
Solution
BF3 has three bonding pairs and no lone pairs, resulting in a trigonal planar shape.
Correct Answer:
B
— Trigonal planar
Learn More →
Q. What is the molecular shape of NH3 according to VSEPR theory?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Trigonal pyramidal
Show solution
Solution
NH3 has three bonding pairs and one lone pair, resulting in a trigonal pyramidal shape.
Correct Answer:
D
— Trigonal pyramidal
Learn More →
Q. What is the molecular weight of water (H2O)?
A.
16 g/mol
B.
18 g/mol
C.
20 g/mol
D.
22 g/mol
Show solution
Solution
The molecular weight of water is calculated as (2*1) + (16) = 18 g/mol.
Correct Answer:
B
— 18 g/mol
Learn More →
Q. What is the moment of inertia of a disk of mass M and radius R about an axis through its center and perpendicular to its plane?
A.
1/2 MR^2
B.
MR^2
C.
1/4 MR^2
D.
2/3 MR^2
Show solution
Solution
The moment of inertia of a disk about an axis through its center is I = 1/2 MR^2.
Correct Answer:
A
— 1/2 MR^2
Learn More →
Q. What is the moment of inertia of a solid cylinder of mass M and radius R about its central axis?
A.
1/2 MR^2
B.
1/3 MR^2
C.
MR^2
D.
2/5 MR^2
Show solution
Solution
The moment of inertia of a solid cylinder about its central axis is given by I = 1/2 MR^2.
Correct Answer:
A
— 1/2 MR^2
Learn More →
Q. What is the moment of inertia of a solid disk about its central axis?
A.
(1/2)MR^2
B.
(1/3)MR^2
C.
(1/4)MR^2
D.
MR^2
Show solution
Solution
The moment of inertia of a solid disk about its central axis is (1/2)MR^2.
Correct Answer:
A
— (1/2)MR^2
Learn More →
Q. What is the moment of inertia of a solid sphere about an axis through its center?
A.
(2/5)mr^2
B.
(1/2)mr^2
C.
(1/3)mr^2
D.
(5/2)mr^2
Show solution
Solution
The moment of inertia of a solid sphere about an axis through its center is given by I = (2/5)mr^2.
Correct Answer:
A
— (2/5)mr^2
Learn More →
Q. What is the moment of inertia of a solid sphere of mass M and radius R about an axis through its center?
A.
2/5 MR^2
B.
3/5 MR^2
C.
1/2 MR^2
D.
MR^2
Show solution
Solution
The moment of inertia of a solid sphere about an axis through its center is I = 2/5 MR^2.
Correct Answer:
A
— 2/5 MR^2
Learn More →
Q. What is the moment of inertia of a thin circular hoop of mass M and radius R about an axis through its center?
A.
MR^2
B.
1/2 MR^2
C.
1/3 MR^2
D.
2/5 MR^2
Show solution
Solution
The moment of inertia of a thin circular hoop about an axis through its center is I = MR^2.
Correct Answer:
A
— MR^2
Learn More →
Q. What is the moment of inertia of a thin circular plate of mass M and radius R about an axis through its center and perpendicular to its plane?
A.
1/2 MR^2
B.
MR^2
C.
1/4 MR^2
D.
1/3 MR^2
Show solution
Solution
The moment of inertia of a thin circular plate about an axis through its center is I = 1/2 MR^2.
Correct Answer:
A
— 1/2 MR^2
Learn More →
Q. What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane through its center?
A.
MR^2
B.
1/2 MR^2
C.
1/3 MR^2
D.
2/5 MR^2
Show solution
Solution
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Correct Answer:
A
— MR^2
Learn More →
Q. What is the moment of inertia of a thin circular ring of mass M and radius R about an axis through its center?
A.
MR^2
B.
1/2 MR^2
C.
1/3 MR^2
D.
2/5 MR^2
Show solution
Solution
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Correct Answer:
A
— MR^2
Learn More →
Q. What is the moment of inertia of a thin circular ring of mass M and radius R about an axis through its center and perpendicular to its plane?
A.
MR^2
B.
1/2 MR^2
C.
2/3 MR^2
D.
1/3 MR^2
Show solution
Solution
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Correct Answer:
A
— MR^2
Learn More →
Q. What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
A.
MR^2
B.
1/2 MR^2
C.
1/3 MR^2
D.
2/5 MR^2
Show solution
Solution
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Correct Answer:
A
— MR^2
Learn More →
Q. What is the moment of inertia of a thin rod of length L about an axis perpendicular to it and passing through its center?
A.
(1/3)ML^2
B.
(1/12)ML^2
C.
(1/2)ML^2
D.
ML^2
Show solution
Solution
The moment of inertia of a thin rod about an axis through its center is given by I = (1/12)ML^2.
Correct Answer:
B
— (1/12)ML^2
Learn More →
Q. What is the moment of inertia of a thin rod of length L about an axis perpendicular to it and passing through one end?
A.
(1/3)ML^2
B.
(1/12)ML^2
C.
ML^2
D.
(1/2)ML^2
Show solution
Solution
The moment of inertia of a thin rod about an end is given by I = (1/3)ML^2.
Correct Answer:
A
— (1/3)ML^2
Learn More →
Q. What is the moment of inertia of a thin spherical shell of mass M and radius R about an axis through its center?
A.
2/3 MR^2
B.
1/2 MR^2
C.
MR^2
D.
2 MR^2
Show solution
Solution
The moment of inertia of a thin spherical shell about an axis through its center is I = 2/3 MR^2.
Correct Answer:
A
— 2/3 MR^2
Learn More →
Showing 7471 to 7500 of 10700 (357 Pages)
