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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. What is the mass of 3 moles of carbon dioxide (CO2)?

A. 44 g
B. 66 g
C. 132 g
D. 22 g

Solution

The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.

Correct Answer: A — 44 g

Q. What is the mass of 3 moles of NaCl?

A. 87 g
B. 58.5 g
C. 174 g
D. 3 g

Solution

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.

Correct Answer: C — 174 g

Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?

A. 98 g
B. 196 g
C. 294 g
D. 392 g

Solution

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.

Correct Answer: B — 196 g

Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?

A. 74.5 g
B. 10 g
C. 20 g
D. 30 g

Solution

10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.

Correct Answer: A — 74.5 g

Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?

A. 18 g
B. 36 g
C. 54 g
D. 9 g

Solution

2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.

Correct Answer: A — 18 g

Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?

A. 10%
B. 20%
C. 25%
D. 15%

Solution

Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.

Correct Answer: A — 10%

Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?

A. 10%
B. 20%
C. 25%
D. 15%

Solution

Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.

Correct Answer: B — 20%

Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?

A. 10%
B. 20%
C. 5%
D. 15%

Solution

Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.

Correct Answer: B — 20%

Q. What is the maximum intensity ratio in interference of two waves of equal amplitude?

A. 1:1
B. 2:1
C. 4:1
D. 3:1

Solution

Maximum intensity (I_max) = 4I_0 for two waves of equal amplitude (I_0). Thus, the ratio is 4:1.

Correct Answer: C — 4:1

Q. What is the maximum kinetic energy of photoelectrons emitted if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hf - Φ = (6.626 x 10^-34 J·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum kinetic energy of photoelectrons emitted when light of frequency 8 x 10^14 Hz is incident on a metal with work function 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum kinetic energy of photoelectrons if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?

A. 5
B. 10
C. 20
D. 50

Solution

The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.

Correct Answer: B — 10

Q. What is the maximum number of electrons in the d-subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The d-subshell can hold a maximum of 10 electrons.

Correct Answer: C — 10

Q. What is the maximum number of electrons in the n=2 shell?

A. 2
B. 4
C. 8
D. 6

Solution

The maximum number of electrons in the n=2 shell is 2(2^2) = 8.

Correct Answer: B — 4

Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?

A. 8
B. 18
C. 32
D. 2

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?

A. 10
B. 18
C. 32
D. 50

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?

A. 8
B. 18
C. 32
D. 2

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.

Correct Answer: B — 18

Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?

A. 2
B. 4
C. 8
D. 10

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.

Correct Answer: B — 4

Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?

A. 10
B. 18
C. 32
D. 50

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can occupy a p subshell?

A. 2
B. 6
C. 10
D. 14

Solution

A p subshell can hold a maximum of 6 electrons.

Correct Answer: B — 6

Q. What is the maximum number of electrons that can occupy a single orbital?

A. 1
B. 2
C. 3
D. 4

Solution

A single orbital can hold a maximum of 2 electrons, with opposite spins.

Correct Answer: B — 2

Q. What is the maximum number of electrons that can occupy a single p subshell?

A. 2
B. 6
C. 10
D. 14

Solution

A p subshell can hold a maximum of 6 electrons, as it has three orbitals each capable of holding 2 electrons.

Correct Answer: B — 6

Q. What is the maximum number of electrons that can occupy a single p-orbital?

A. 2
B. 6
C. 10
D. 14

Solution

A single p-orbital can hold a maximum of 2 electrons.

Correct Answer: A — 2

Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy the 3rd energy level?

A. 2
B. 8
C. 18
D. 32

Solution

The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.

Correct Answer: C — 18

Q. What is the maximum number of electrons that can occupy the d subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The d subshell can hold a maximum of 10 electrons.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy the f subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The f subshell can hold a maximum of 14 electrons (7 orbitals, each can hold 2).

Correct Answer: D — 14

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