Engineering & Architecture Admissions - Exam Prep Guide

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Engineering & Architecture Admissions

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Engineering & Architecture Admissions MCQ & Objective Questions

Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.

What You Will Practise Here

Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions

Exam Relevance

The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.

FAQs

Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?
Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.

Question: How can I improve my accuracy in solving MCQs?
Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.

Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.

JEE Main

Q. What is the mass of 3 moles of carbon dioxide (CO2)?

A. 44 g
B. 66 g
C. 132 g
D. 22 g

Solution

The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.

Correct Answer: A — 44 g

Q. What is the mass of 3 moles of NaCl?

A. 87 g
B. 58.5 g
C. 174 g
D. 3 g

Solution

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.

Correct Answer: C — 174 g

Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?

A. 98 g
B. 196 g
C. 294 g
D. 392 g

Solution

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.

Correct Answer: B — 196 g

Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?

A. 74.5 g
B. 10 g
C. 20 g
D. 30 g

Solution

10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.

Correct Answer: A — 74.5 g

Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?

A. 18 g
B. 36 g
C. 54 g
D. 9 g

Solution

2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.

Correct Answer: A — 18 g

Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?

A. 10%
B. 20%
C. 25%
D. 15%

Solution

Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.

Correct Answer: A — 10%

Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?

A. 10%
B. 20%
C. 25%
D. 15%

Solution

Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.

Correct Answer: B — 20%

Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?

A. 10%
B. 20%
C. 5%
D. 15%

Solution

Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.

Correct Answer: B — 20%

Q. What is the maximum intensity ratio in interference of two waves of equal amplitude?

A. 1:1
B. 2:1
C. 4:1
D. 3:1

Solution

Maximum intensity (I_max) = 4I_0 for two waves of equal amplitude (I_0). Thus, the ratio is 4:1.

Correct Answer: C — 4:1

Q. What is the maximum kinetic energy of photoelectrons emitted if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hf - Φ = (6.626 x 10^-34 J·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum kinetic energy of photoelectrons emitted when light of frequency 8 x 10^14 Hz is incident on a metal with work function 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum kinetic energy of photoelectrons if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?

A. 1 eV
B. 3 eV
C. 5 eV
D. 7 eV

Solution

Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.

Correct Answer: C — 5 eV

Q. What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?

A. 5
B. 10
C. 20
D. 50

Solution

The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.

Correct Answer: B — 10

Q. What is the maximum number of electrons in the d-subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The d-subshell can hold a maximum of 10 electrons.

Correct Answer: C — 10

Q. What is the maximum number of electrons in the n=2 shell?

A. 2
B. 4
C. 8
D. 6

Solution

The maximum number of electrons in the n=2 shell is 2(2^2) = 8.

Correct Answer: B — 4

Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?

A. 10
B. 18
C. 32
D. 50

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?

A. 8
B. 18
C. 32
D. 2

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.

Correct Answer: B — 18

Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?

A. 8
B. 18
C. 32
D. 2

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?

A. 2
B. 4
C. 8
D. 10

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.

Correct Answer: B — 4

Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?

A. 10
B. 18
C. 32
D. 50

Solution

The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.

Correct Answer: C — 32

Q. What is the maximum number of electrons that can occupy a p subshell?

A. 2
B. 6
C. 10
D. 14

Solution

A p subshell can hold a maximum of 6 electrons.

Correct Answer: B — 6

Q. What is the maximum number of electrons that can occupy a single orbital?

A. 1
B. 2
C. 3
D. 4

Solution

A single orbital can hold a maximum of 2 electrons, with opposite spins.

Correct Answer: B — 2

Q. What is the maximum number of electrons that can occupy a single p subshell?

A. 2
B. 6
C. 10
D. 14

Solution

A p subshell can hold a maximum of 6 electrons, as it has three orbitals each capable of holding 2 electrons.

Correct Answer: B — 6

Q. What is the maximum number of electrons that can occupy a single p-orbital?

A. 2
B. 6
C. 10
D. 14

Solution

A single p-orbital can hold a maximum of 2 electrons.

Correct Answer: A — 2

Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?

A. 2
B. 6
C. 10
D. 14

Solution

The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy the 3rd energy level?

A. 2
B. 8
C. 18
D. 32

Solution

The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.

Correct Answer: C — 18

Q. What is the maximum number of electrons that can occupy the d subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The d subshell can hold a maximum of 10 electrons.

Correct Answer: C — 10

Q. What is the maximum number of electrons that can occupy the f subshell?

A. 2
B. 6
C. 10
D. 14

Solution

The f subshell can hold a maximum of 14 electrons (7 orbitals, each can hold 2).

Correct Answer: D — 14

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