Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. If 'x' is a number in base 5 represented as '320', what is its decimal equivalent?

A. 75
B. 80
C. 85
D. 90

Solution

'320' in base 5 = 3*5^2 + 2*5^1 + 0*5^0 = 75.

Correct Answer: A — 75

Q. If 'X' is a prime number and 'Y' is an even number greater than 2, which of the following can be concluded?

A. X is even.
B. Y is prime.
C. X + Y is odd.
D. X + Y is even.

Solution

A prime number (X) greater than 2 is odd, and an even number (Y) added to an odd number results in an odd sum.

Correct Answer: C — X + Y is odd.

Q. If 'X' is a square and 'Y' is a rectangle, which of the following is true?

A. All squares are rectangles.
B. All rectangles are squares.
C. X is not a rectangle.
D. Y is a square.

Solution

All squares are rectangles because they meet the definition of a rectangle.

Correct Answer: A — All squares are rectangles.

Q. If 'X' is greater than 'Y' and 'Y' is less than 'Z', which of the following is true?

A. X < Z
B. Y > Z
C. X > Z
D. Y < X

Solution

'Y < X' is true since 'X' is greater than 'Y'.

Correct Answer: D — Y < X

Q. If 'X' is greater than 'Y' and 'Y' is less than 'Z', which statement is true?

A. X is less than Z
B. Y is greater than Z
C. X is greater than Z
D. Z is greater than X

Solution

If 'X' is greater than 'Y' and 'Y' is less than 'Z', then 'X' must also be less than 'Z'.

Correct Answer: A — X is less than Z

Q. If 'X' is to 'Y' as 'Z' is to _____? 'X' is a type of 'Y', and 'Z' is a type of which word?

A. A
B. B
C. C
D. D

Solution

If 'X' is a type of 'Y', then 'Z' must be a type of 'C' to maintain the relationship.

Correct Answer: C — C

Q. If 'X' is twice as fast as 'Y', and 'Y' takes 30 minutes to complete a task, how long will 'X' take?

A. 15 minutes
B. 30 minutes
C. 60 minutes
D. 45 minutes

Solution

'X' being twice as fast means it will take half the time of 'Y', which is 15 minutes.

Correct Answer: A — 15 minutes

Q. If 'XYZ' in a base-6 system equals 215 in decimal, what is the value of 'X'?

A. 3
B. 4
C. 5
D. 2

Solution

215 in decimal is '543' in base-6, so 'X' is 4.

Correct Answer: B — 4

Q. If 'XYZ' in base 5 equals 100 in decimal, what is the value of 'X'?

A. 1
B. 2
C. 3
D. 4

Solution

'XYZ' in base 5 means X*25 + Y*5 + Z = 100. The only valid solution is X=2.

Correct Answer: B — 2

Q. If 'XYZ' in base-3 equals 26 in decimal, what is the value of 'X'?

A. 2
B. 1
C. 0
D. 3

Solution

In base-3, 'XYZ' means X*9 + Y*3 + Z = 26. The only valid digit for X is 2.

Correct Answer: A — 2

Q. If 'XYZ' in base-4 equals 27 in decimal, what is the value of 'X'?

A. 1
B. 2
C. 3
D. 0

Solution

In base-4, 'XYZ' = 4^2*X + 4^1*Y + 4^0*Z = 27. The only valid combination is X=3, Y=3, Z=3.

Correct Answer: C — 3

Q. If -2 < x < 3, which of the following is true?

A. x + 1 > 0
B. x - 1 < 1
C. 2x < 5
D. x + 2 < 5

Solution

For -2 < x < 3, 2x < 6 is true, hence 2x < 5 is true.

Correct Answer: C — 2x < 5

Q. If -2x + 5 < 1, what is the value of x?

A. x < 2
B. x > 2
C. x < 3
D. x > 3

Solution

Rearranging gives -2x < -4, thus x > 2.

Correct Answer: A — x < 2

Q. If 0.1 M acetic acid (CH3COOH) is 1% ionized, what is the concentration of H+ ions?

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 0.2 M

Solution

Ionization = 1% of 0.1 M = 0.001 M, so [H+] = 0.001 M.

Correct Answer: B — 0.01 M

Q. If 0.1 M acetic acid has a pH of 2.87, what is the concentration of H+ ions?

A. 0.001 M
B. 0.01 M
C. 0.1 M
D. 0.5 M

Solution

[H+] = 10^(-pH) = 10^(-2.87) ≈ 0.001 M.

Correct Answer: B — 0.01 M

Q. If 0.1 M NaOH is mixed with 0.1 M HCl, what will be the resulting pH?

A. 0
B. 7
C. 14
D. 1

Solution

The reaction between NaOH and HCl neutralizes each other, resulting in a neutral solution with a pH of 7.

Correct Answer: B — 7

Q. If 0.1 M of a strong acid is mixed with 0.1 M of a strong base, what will be the resulting pH?

A. 0
B. 7
C. 14
D. 1

Solution

Strong acid and strong base neutralize each other, resulting in a neutral solution with pH = 7.

Correct Answer: B — 7

Q. If 0.1 M of a weak acid has a pH of 4.0, what is the Ka of the acid?

A. 1 x 10^-4
B. 1 x 10^-5
C. 1 x 10^-6
D. 1 x 10^-7

Solution

Using the formula Ka = [H+]^2 / [HA], where [H+] = 10^(-4) M and [HA] = 0.1 M, we find Ka = (10^-4)^2 / 0.1 = 1 x 10^-5.

Correct Answer: B — 1 x 10^-5

Q. If 0.125 is expressed as a fraction, what is it?

A. 1/8
B. 1/4
C. 1/2
D. 1/10

Solution

0.125 = 125/1000 = 1/8 after simplification.

Correct Answer: A — 1/8

Q. If 0.5 mol of a non-volatile solute is dissolved in 1 kg of water, what is the vapor pressure lowering? (Vapor pressure of pure water = 23.76 mmHg)

A. 1.88 mmHg
B. 2.88 mmHg
C. 3.88 mmHg
D. 4.88 mmHg

Solution

Vapor pressure lowering = (n_solute / n_solvent) * P°_solvent = (0.5 / 55.5) * 23.76 = 1.88 mmHg

Correct Answer: A — 1.88 mmHg

Q. If 0.5 moles of a gas occupy 11.2 liters at STP, what is the molar volume of the gas?

A. 22.4 L
B. 11.2 L
C. 5.6 L
D. 44.8 L

Solution

At STP, 1 mole of gas occupies 22.4 L. Therefore, the molar volume is 22.4 L.

Correct Answer: A — 22.4 L

Q. If 0.5 moles of a gas occupy 12 liters at STP, what is the molar volume of the gas? (2023)

A. 22.4 L
B. 24 L
C. 12 L
D. 6 L

Solution

At STP, 1 mole of any gas occupies 22.4 L. Therefore, 0.5 moles occupy 0.5 x 22.4 L = 11.2 L, confirming the molar volume is 22.4 L.

Correct Answer: A — 22.4 L

Q. If 0.5 moles of a gas occupy 12.2 liters at STP, what is the molar volume of the gas? (2023)

A. 22.4 L
B. 24 L
C. 12.2 L
D. 6.1 L

Solution

At STP, 1 mole of gas occupies 22.4 liters. Therefore, the molar volume is 22.4 L.

Correct Answer: A — 22.4 L

Q. If 0.5 moles of a non-volatile solute are dissolved in 1 kg of water, what is the expected change in boiling point? (Kb for water = 0.52 °C kg/mol) (2021)

A. 0.26 °C
B. 0.52 °C
C. 1.04 °C
D. 0.78 °C

Solution

Boiling point elevation = i * Kb * m = 1 * 0.52 * 0.5 = 0.26 °C, so change = 0.52 °C.

Correct Answer: C — 1.04 °C

Q. If 0.5 moles of a non-volatile solute are dissolved in 1 kg of water, what is the expected vapor pressure lowering? (2021)

A. 0.5 P0
B. 0.25 P0
C. 0.75 P0
D. 0.1 P0

Solution

Vapor pressure lowering = X_solute * P0 = (0.5 / (0.5 + 55.5)) * P0 ≈ 0.25 P0.

Correct Answer: B — 0.25 P0

Q. If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, what is the expected vapor pressure lowering? (2020)

A. 0.5 P0
B. 0.25 P0
C. 0.75 P0
D. 0.1 P0

Solution

Vapor pressure lowering = (moles of solute / moles of solvent) * P0 = (0.5 / 55.5) * P0 ≈ 0.25 P0.

Correct Answer: B — 0.25 P0

Q. If 0.5 moles of NaCl are dissolved in 1 liter of water, what is the concentration of NaCl in the solution?

A. 0.5 M
B. 1 M
C. 2 M
D. 0.25 M

Solution

Concentration (M) = moles of solute / liters of solution = 0.5 moles / 1 L = 0.5 M.

Correct Answer: A — 0.5 M

Q. If 0.5 moles of NaCl are dissolved in 1 liter of water, what is the concentration of NaCl?

A. 0.5 M
B. 1 M
C. 2 M
D. 0.25 M

Solution

Concentration (M) = moles of solute / liters of solution = 0.5 moles / 1 L = 0.5 M.

Correct Answer: A — 0.5 M

Q. If 0.5 moles of NaCl are dissolved in 1 liter of water, what is the molarity of the solution?

A. 0.5 M
B. 1 M
C. 2 M
D. 0.25 M

Solution

Molarity (M) = moles of solute / liters of solution = 0.5 moles / 1 L = 0.5 M.

Correct Answer: A — 0.5 M

Q. If 0.5 moles of NaCl is dissolved in 1 liter of water, what is the molality of the solution? (2022)

A. 0.5 m
B. 1 m
C. 2 m
D. 0.25 m

Solution

Molality (m) = moles of solute / kg of solvent. Assuming 1 L of water = 1 kg, molality = 0.5 moles / 1 kg = 0.5 m.

Correct Answer: A — 0.5 m

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