Q. What is the mass of 0.5 moles of NaCl?
A.
29 g
B.
58 g
C.
14 g
D.
0.5 g
Show solution
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 0.5 moles x 58.5 g/mol = 29.25 g.
Correct Answer:
A
— 29 g
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Q. What is the mass of 0.5 moles of sodium chloride (NaCl)?
A.
29 g
B.
35 g
C.
58 g
D.
70 g
Show solution
Solution
The molar mass of NaCl is 58 g/mol. Therefore, 0.5 moles of NaCl = 0.5 x 58 g = 29 g.
Correct Answer:
C
— 58 g
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Q. What is the mass of 0.75 moles of sulfuric acid (H2SO4)?
A.
75 g
B.
98 g
C.
147 g
D.
50 g
Show solution
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.
Correct Answer:
B
— 98 g
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Q. What is the mass of 1 mole of water (H2O)?
A.
18 g
B.
16 g
C.
20 g
D.
22 g
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Solution
The molar mass of water (H2O) is 18 g/mol (2*1 for H + 16 for O).
Correct Answer:
A
— 18 g
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Q. What is the mass of 2 moles of carbon dioxide (CO2)?
A.
44 g
B.
22 g
C.
88 g
D.
66 g
Show solution
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 2 moles of CO2 weigh 2 x 44 g = 88 g.
Correct Answer:
A
— 44 g
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Q. What is the mass of 2 moles of sulfuric acid (H2SO4)?
A.
98 g
B.
196 g
C.
294 g
D.
392 g
Show solution
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 2 moles x 98 g/mol = 196 g.
Correct Answer:
B
— 196 g
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Q. What is the mass of 3 moles of carbon dioxide (CO2)?
A.
44 g
B.
66 g
C.
132 g
D.
22 g
Show solution
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.
Correct Answer:
A
— 44 g
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Q. What is the mass of 3 moles of NaCl?
A.
87 g
B.
58.5 g
C.
174 g
D.
3 g
Show solution
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer:
C
— 174 g
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Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?
A.
98 g
B.
196 g
C.
294 g
D.
392 g
Show solution
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.
Correct Answer:
B
— 196 g
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Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
A.
74.5 g
B.
10 g
C.
20 g
D.
30 g
Show solution
Solution
10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.
Correct Answer:
A
— 74.5 g
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Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?
A.
18 g
B.
36 g
C.
54 g
D.
9 g
Show solution
Solution
2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.
Correct Answer:
A
— 18 g
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Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?
A.
10%
B.
20%
C.
25%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.
Correct Answer:
A
— 10%
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Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?
A.
10%
B.
20%
C.
25%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.
Correct Answer:
B
— 20%
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Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?
A.
10%
B.
20%
C.
5%
D.
15%
Show solution
Solution
Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer:
B
— 20%
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Q. What is the maximum number of electrons in the n=2 shell?
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Solution
The maximum number of electrons in the n=2 shell is 2(2^2) = 8.
Correct Answer:
B
— 4
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Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.
Correct Answer:
C
— 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer:
B
— 18
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Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer:
C
— 32
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Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?
Show solution
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Correct Answer:
C
— 10
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Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?
Show solution
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.
Correct Answer:
B
— 4
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Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?
Show solution
Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer:
C
— 32
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Q. What is the maximum number of electrons that can occupy a p subshell?
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Solution
A p subshell can hold a maximum of 6 electrons.
Correct Answer:
B
— 6
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Q. What is the maximum number of electrons that can occupy a single orbital?
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Solution
A single orbital can hold a maximum of 2 electrons, with opposite spins.
Correct Answer:
B
— 2
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Q. What is the maximum number of electrons that can occupy a single p-orbital?
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Solution
A single p-orbital can hold a maximum of 2 electrons.
Correct Answer:
A
— 2
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?
Show solution
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.
Correct Answer:
C
— 10
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?
Show solution
Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.
Correct Answer:
C
— 10
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Q. What is the maximum number of electrons that can occupy the 3rd energy level?
Show solution
Solution
The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer:
C
— 18
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Q. What is the maximum number of electrons that can occupy the n=3 shell?
Show solution
Solution
The maximum number of electrons in a shell is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer:
C
— 18
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Q. What is the maximum number of orbitals in a subshell where l = 1?
Show solution
Solution
For l=1, the number of orbitals is given by 2l + 1 = 3.
Correct Answer:
B
— 3
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Q. What is the maximum number of orbitals in a subshell with l = 3?
Show solution
Solution
The number of orbitals in a subshell is given by 2l + 1. For l = 3, it is 2*3 + 1 = 7.
Correct Answer:
C
— 7
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Physical Chemistry MCQ & Objective Questions
Physical Chemistry is a crucial branch of chemistry that combines principles of physics and chemistry to explain how matter behaves. Mastering this subject is essential for students preparing for school exams and competitive tests. Practicing MCQs and objective questions in Physical Chemistry not only enhances conceptual clarity but also boosts your chances of scoring better in exams. Engaging with practice questions helps identify important topics and reinforces learning.
What You Will Practise Here
Thermodynamics: Laws, concepts, and applications
Kinetics: Rate laws, reaction mechanisms, and factors affecting reaction rates
Equilibrium: Chemical equilibrium, Le Chatelier's principle, and equilibrium constants
Quantum Chemistry: Basic principles and applications in atomic structure
Electrochemistry: Redox reactions, electrochemical cells, and Nernst equation
Solutions: Colligative properties and their calculations
Acids and Bases: pH calculations, buffer solutions, and titration curves
Exam Relevance
Physical Chemistry is a significant part of the syllabus for CBSE, State Boards, NEET, and JEE. Questions often focus on theoretical concepts, numerical problems, and application-based scenarios. Common patterns include direct questions on laws of thermodynamics, calculations involving reaction rates, and conceptual questions on equilibrium. Familiarity with these patterns can greatly enhance your exam preparation.
Common Mistakes Students Make
Misunderstanding the application of thermodynamic laws in different scenarios
Confusing reaction rates with equilibrium constants
Overlooking the significance of units in calculations
Neglecting to practice numerical problems, leading to poor time management during exams
FAQs
Question: What are the key topics to focus on in Physical Chemistry for exams?Answer: Focus on thermodynamics, kinetics, equilibrium, and electrochemistry as these are frequently tested.
Question: How can I improve my performance in Physical Chemistry MCQs?Answer: Regular practice of MCQs and understanding the underlying concepts will significantly improve your performance.
Now is the time to enhance your understanding of Physical Chemistry! Dive into our practice MCQs and test your knowledge to excel in your exams. Your success starts with practice!
