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Q. A car covers a distance of 150 km in 3 hours. What is the speed of the car in km/h? (2022)

A. 45 km/h
B. 50 km/h
C. 55 km/h
D. 60 km/h

Solution

Speed = Distance / Time = 150 km / 3 h = 50 km/h.

Correct Answer: B — 50 km/h

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Q. A car covers a distance of 240 km at a speed of 60 km/h. How long does the journey take?

A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours

Solution

Time = Distance / Speed = 240 km / 60 km/h = 4 hours.

Correct Answer: B — 4 hours

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Q. A car covers a distance of 240 km in 3 hours. What is its average speed? (2021)

A. 80 km/h
B. 70 km/h
C. 60 km/h
D. 90 km/h

Solution

Average Speed = Total Distance / Total Time = 240 km / 3 h = 80 km/h.

Correct Answer: A — 80 km/h

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Q. A car covers a distance of 240 km in 3 hours. What is its speed? (2022)

A. 70 km/h
B. 80 km/h
C. 90 km/h
D. 100 km/h

Solution

Speed = Distance / Time = 240 km / 3 h = 80 km/h

Correct Answer: B — 80 km/h

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Q. A car does 5000 J of work in moving a distance of 100 m. What is the average force exerted by the car? (2023)

A. 50 N
B. 100 N
C. 150 N
D. 200 N

Solution

Average Force = Work done / Distance = 5000 J / 100 m = 50 N

Correct Answer: A — 50 N

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Q. A car engine does 3000 J of work in 5 seconds. What is the average power output of the engine?

A. 600 W
B. 800 W
C. 1000 W
D. 1200 W

Solution

Using the formula P = W/t, we find P = 3000 J / 5 s = 600 W.

Correct Answer: C — 1000 W

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Q. A car engine does 3000 J of work in 5 seconds. What is the power of the engine?

A. 600 W
B. 800 W
C. 1000 W
D. 1200 W

Solution

Using the formula P = W/t, we have P = 3000 J / 5 s = 600 W.

Correct Answer: A — 600 W

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Q. A car is moving at 80 km/h and a motorcycle at 60 km/h in the same direction. What is the relative speed of the motorcycle with respect to the car?

A. 20 km/h
B. 60 km/h
C. 80 km/h
D. 140 km/h

Solution

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind).

Correct Answer: A — 20 km/h

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Q. A car is moving at 80 km/h and a motorcycle is moving at 100 km/h in the same direction. What is the relative speed of the motorcycle with respect to the car?

A. 20 km/h
B. 180 km/h
C. 100 km/h
D. 80 km/h

Solution

Relative speed = Speed of motorcycle - Speed of car = 100 km/h - 80 km/h = 20 km/h.

Correct Answer: A — 20 km/h

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Q. A car is moving at 80 km/h and a motorcycle is moving at 100 km/h in the same direction. What is the speed of the motorcycle relative to the car?

A. 20 km/h
B. 80 km/h
C. 100 km/h
D. 180 km/h

Solution

Relative speed = Speed of motorcycle - Speed of car = 100 km/h - 80 km/h = 20 km/h.

Correct Answer: A — 20 km/h

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Q. A car is moving at 80 km/h and a motorcycle is moving at 60 km/h in the same direction. What is the speed of the motorcycle relative to the car?

A. 20 km/h
B. 60 km/h
C. 80 km/h
D. 140 km/h

Solution

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind the car).

Correct Answer: A — 20 km/h

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Q. A car is moving at 80 km/h and a motorcycle is moving at 60 km/h in the same direction. What is the relative speed of the motorcycle with respect to the car?

A. 20 km/h
B. 60 km/h
C. 80 km/h
D. 140 km/h

Solution

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind).

Correct Answer: A — 20 km/h

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Q. A car is moving in a circular path of radius 50 m with a constant speed of 20 m/s. What is the centripetal acceleration of the car?

A. 2 m/s²
B. 4 m/s²
C. 8 m/s²
D. 10 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20 m/s)² / (50 m) = 8 m/s².

Correct Answer: B — 4 m/s²

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Q. A car is moving in a circular path of radius 50 m with a speed of 15 m/s. What is the angular displacement after 10 seconds?

A. 1 rad
B. 2 rad
C. 3 rad
D. 4 rad

Solution

Angular displacement θ = (v/r)t = (15/50)(10) = 3 rad.

Correct Answer: D — 4 rad

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Q. A car is moving in a circular track of radius 100 m at a speed of 20 m/s. What is the time period of one complete revolution?

A. 10 s
B. 20 s
C. 30 s
D. 40 s

Solution

Circumference = 2πr = 2π(100) = 200π m. Time period (T) = Circumference / Speed = 200π / 20 = 10π s.

Correct Answer: B — 20 s

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Q. A car is moving in a circular track of radius 100 m with a speed of 20 m/s. What is the time period of one complete revolution?

A. 10 s
B. 20 s
C. 30 s
D. 40 s

Solution

Circumference = 2πr = 2π(100) = 200π m. Time period (T) = Circumference / Speed = 200π / 20 = 10π s.

Correct Answer: B — 20 s

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Q. A car is moving in a circular track of radius 50 m with a speed of 15 m/s. What is the angular momentum of the car if its mass is 1000 kg? (2000)

A. 7500 kg m²/s
B. 10000 kg m²/s
C. 15000 kg m²/s
D. 20000 kg m²/s

Solution

Angular momentum L = mvr = 1000 * 15 * 50 = 750000 kg m²/s.

Correct Answer: A — 7500 kg m²/s

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Q. A car is moving in a circular track of radius 50 m with a speed of 15 m/s. What is the net force acting on the car if its mass is 1000 kg?

A. 200 N
B. 300 N
C. 400 N
D. 500 N

Solution

Centripetal force = mv²/r = 1000(15²)/50 = 4500 N.

Correct Answer: C — 400 N

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Q. A car is moving on a circular track of radius 100 m. If the maximum speed at which it can move without skidding is 20 m/s, what is the coefficient of friction between the tires and the road?

A. 0.1
B. 0.2
C. 0.3
D. 0.4

Solution

The centripetal force required is provided by friction: F = mv^2/r. The frictional force is μmg. Setting them equal gives μ = v^2/(rg). Here, μ = (20^2)/(100*9.8) ≈ 0.4.

Correct Answer: C — 0.3

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Q. A car is negotiating a curve of radius 100 m at a speed of 15 m/s. What is the minimum coefficient of friction required to prevent the car from skidding?

A. 0.15
B. 0.25
C. 0.30
D. 0.35

Solution

Frictional force = m * a_c; μmg = mv²/r; μ = v²/(rg) = (15 m/s)² / (100 m * 9.8 m/s²) ≈ 0.23.

Correct Answer: B — 0.25

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Q. A car moves in a circular path of radius 50 m at a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

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Q. A car moves in a circular path of radius 50 m with a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

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Q. A car moving at 15 m/s comes to a stop in 5 seconds. What is its acceleration? (2019)

A. -2 m/s²
B. -3 m/s²
C. -4 m/s²
D. -5 m/s²

Solution

Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 15) / 5 = -3 m/s².

Correct Answer: A — -2 m/s²

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Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)

A. 90 m
B. 120 m
C. 150 m
D. 180 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.

Correct Answer: B — 120 m

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Q. A car moving with a speed of 30 m/s applies brakes and comes to a stop in 5 seconds. What is the deceleration of the car?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Deceleration = (final velocity - initial velocity) / time = (0 - 30) / 5 = -6 m/s².

Correct Answer: A — 3 m/s²

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Q. A car of mass 1000 kg accelerates at 2 m/s². What is the net force acting on the car?

A. 2000 N
B. 500 N
C. 1000 N
D. 1500 N

Solution

Using F = ma, the net force is F = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: A — 2000 N

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s in 10 seconds. What is the net force acting on the car? (2000)

A. 100 N
B. 200 N
C. 300 N
D. 400 N

Solution

Acceleration a = (final speed - initial speed) / time = (20 m/s - 0) / 10 s = 2 m/s². Net force F = ma = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: B — 200 N

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the kinetic energy gained?

A. 200,000 J
B. 100,000 J
C. 50,000 J
D. 20,000 J

Solution

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (20 m/s)² = 200,000 J.

Correct Answer: B — 100,000 J

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done on the car?

A. 20000 J
B. 40000 J
C. 80000 J
D. 100000 J

Solution

Kinetic energy = 0.5 × m × v^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done by the engine? (2000)

A. 20000 J
B. 40000 J
C. 50000 J
D. 80000 J

Solution

Kinetic Energy = 0.5 × mass × velocity^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

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Major Competitive Exams

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