Q. If a line segment is divided into two parts in the ratio 2:3, what is the length of the longer part if the total length is 25 units?
-
A.
15 units
-
B.
10 units
-
C.
20 units
-
D.
5 units
Solution
Total parts = 2 + 3 = 5. Length of longer part = (3/5) * 25 = 15 units.
Correct Answer:
A
— 15 units
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Q. If a linear equation is represented in the form Ax + By = C, what does 'C' represent?
-
A.
The slope of the line
-
B.
The y-intercept
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C.
The x-intercept
-
D.
The constant term
Solution
'C' is the constant term in the equation, representing the value at which the line intersects the axes.
Correct Answer:
D
— The constant term
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Q. If a linear equation is represented in the form Ax + By = C, what does A, B, and C represent?
-
A.
Constants and variables
-
B.
Only constants
-
C.
Only variables
-
D.
Coefficients and a constant
Solution
In the equation Ax + By = C, A and B are coefficients of the variables x and y, while C is a constant.
Correct Answer:
D
— Coefficients and a constant
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Q. If a liquid droplet is formed on a surface, what shape does it take due to surface tension?
-
A.
Square
-
B.
Flat
-
C.
Sphere
-
D.
Triangle
Solution
A liquid droplet takes the shape of a sphere because this shape minimizes the surface area for a given volume, thus minimizing surface energy.
Correct Answer:
C
— Sphere
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Q. If a liquid droplet is perfectly spherical, what can be said about the forces acting on it?
-
A.
Net force is zero
-
B.
Net force is upward
-
C.
Net force is downward
-
D.
Net force is horizontal
Solution
In a perfectly spherical droplet, the cohesive forces are balanced, resulting in a net force of zero.
Correct Answer:
A
— Net force is zero
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Q. If a liquid has a high surface tension, what can be inferred about its molecular interactions?
-
A.
Weak intermolecular forces
-
B.
Strong intermolecular forces
-
C.
No intermolecular forces
-
D.
Only gravitational forces
Solution
A high surface tension indicates strong intermolecular forces, as these forces are responsible for the cohesive behavior of the liquid.
Correct Answer:
B
— Strong intermolecular forces
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Q. If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?
-
A.
0.05 J
-
B.
0.1 J
-
C.
0.2 J
-
D.
0.5 J
Solution
Work done = Surface Tension × Change in Area = 0.05 N/m × 1 m² = 0.05 J.
Correct Answer:
A
— 0.05 J
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Q. If a loan of $5000 is taken at a simple interest rate of 6% per annum, how much interest will be paid after 4 years?
-
A.
$1200
-
B.
$1000
-
C.
$800
-
D.
$600
Solution
Using the simple interest formula, SI = (Principal * Rate * Time) / 100 = (5000 * 6 * 4) / 100 = $1200.
Correct Answer:
B
— $1000
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Q. If a location is at 120 degrees West longitude, what is its time zone relative to GMT? (2023)
-
A.
GMT-8
-
B.
GMT-7
-
C.
GMT-6
-
D.
GMT-5
Solution
120 degrees West corresponds to GMT-8, as each 15 degrees represents one hour.
Correct Answer:
A
— GMT-8
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Q. If a location is at 15°W longitude, what is the time difference from UTC? (2023)
-
A.
1 hour
-
B.
2 hours
-
C.
3 hours
-
D.
4 hours
Solution
At 15°W, the time is 15° / 15° = 1 hour behind UTC. Therefore, the time difference is 1 hour.
Correct Answer:
B
— 2 hours
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Q. If a lock has 4 digits, how many different combinations can be formed if digits can be repeated?
-
A.
10000
-
B.
9000
-
C.
8000
-
D.
7000
Solution
Each digit can be any of the 10 digits (0-9). Therefore, the total combinations = 10^4 = 10000.
Correct Answer:
A
— 10000
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Q. If a lock has 4 digits, how many different combinations can be formed using the digits 0-9?
-
A.
10000
-
B.
9000
-
C.
1000
-
D.
5000
Solution
Each digit can be any of the 10 digits (0-9), so the total combinations = 10^4 = 10000.
Correct Answer:
A
— 10000
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Q. If a lock requires 3 different digits from 0 to 9, how many different combinations can be formed?
-
A.
720
-
B.
1000
-
C.
900
-
D.
120
Solution
The number of ways to choose 3 different digits from 10 is 10P3 = 720.
Correct Answer:
A
— 720
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Q. If a lock requires 3 digits, how many different combinations can be formed using the digits 0-9?
-
A.
1000
-
B.
900
-
C.
100
-
D.
10
Solution
Each digit can be any of the 10 digits, so the total combinations are 10^3 = 1000.
Correct Answer:
A
— 1000
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Q. If a lock requires a 3-digit code using the digits 0-9, how many different codes can be formed if digits cannot be repeated?
-
A.
720
-
B.
1000
-
C.
900
-
D.
800
Solution
The first digit has 10 options, the second has 9, and the third has 8. Total = 10 * 9 * 8 = 720.
Correct Answer:
A
— 720
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Q. If a long straight conductor carries a current I, what is the magnetic field at a distance r from the wire?
-
A.
μ₀I/(2πr)
-
B.
μ₀I/(4πr²)
-
C.
μ₀I/(2r)
-
D.
μ₀I/(πr²)
Solution
According to Ampere's Law, the magnetic field B at a distance r from a long straight conductor carrying current I is given by B = μ₀I/(2πr).
Correct Answer:
A
— μ₀I/(2πr)
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Q. If a long straight conductor carries a current I, what is the magnetic field B at a distance r from the wire?
-
A.
B = μ₀I/(2πr)
-
B.
B = μ₀I/(4πr²)
-
C.
B = μ₀I/(2r)
-
D.
B = μ₀I/(πr²)
Solution
According to Ampere's Law, the magnetic field B around a long straight conductor is given by B = μ₀I/(2πr).
Correct Answer:
A
— B = μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the direction of the magnetic field at a point located directly above the wire?
-
A.
Towards the wire
-
B.
Away from the wire
-
C.
Clockwise around the wire
-
D.
Counterclockwise around the wire
Solution
Using the right-hand rule, the magnetic field at a point directly above the wire is directed counterclockwise around the wire.
Correct Answer:
D
— Counterclockwise around the wire
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Q. If a long straight wire carries a current I, what is the magnetic field at a distance r from the wire according to the Biot-Savart Law?
-
A.
μ₀I/(2πr)
-
B.
μ₀I/(4πr^2)
-
C.
μ₀I/(2r)
-
D.
μ₀I/(4πr)
Solution
The magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer:
A
— μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the magnetic field at a distance r from the wire according to Ampere's Law?
-
A.
μ₀I/(2πr)
-
B.
μ₀I/(4πr²)
-
C.
I/(2πr)
-
D.
μ₀I/(r)
Solution
Using Ampere's Law, the magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer:
A
— μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the magnetic field B at a distance r from the wire?
-
A.
B = μ₀I/(2πr)
-
B.
B = μ₀I/(4πr^2)
-
C.
B = μ₀I/(2r)
-
D.
B = μ₀I/(πr^2)
Solution
The magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer:
A
— B = μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the magnetic field B at a distance r from the wire according to the Biot-Savart Law?
-
A.
B = (μ₀I)/(2πr)
-
B.
B = (μ₀I)/(4πr²)
-
C.
B = (μ₀I)/(r)
-
D.
B = (μ₀I)/(2r)
Solution
The magnetic field B at a distance r from a long straight wire carrying current I is given by B = (μ₀I)/(2πr).
Correct Answer:
A
— B = (μ₀I)/(2πr)
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Q. If a machine does 200 J of work in 10 seconds, what is its power? (2022)
-
A.
20 W
-
B.
10 W
-
C.
30 W
-
D.
40 W
Solution
Power (P) = Work / Time = 200 J / 10 s = 20 W
Correct Answer:
A
— 20 W
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Q. If a machine does 200 J of work in 5 seconds, what is its power output?
-
A.
20 W
-
B.
40 W
-
C.
50 W
-
D.
60 W
Solution
Power = Work / Time = 200 J / 5 s = 40 W.
Correct Answer:
B
— 40 W
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Q. If a machine does 200 J of work in 5 seconds, what is its power? (2022)
-
A.
40 W
-
B.
50 W
-
C.
20 W
-
D.
30 W
Solution
Power (P) = Work Done (W) / Time (t) = 200 J / 5 s = 40 W
Correct Answer:
B
— 50 W
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Q. If a machine does 2000 J of work in 5 seconds, what is its power output?
-
A.
200 W
-
B.
400 W
-
C.
500 W
-
D.
600 W
Solution
Power = Work / Time = 2000 J / 5 s = 400 W.
Correct Answer:
B
— 400 W
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Q. If a machine does 2000 J of work in 5 seconds, what is its power? (2022)
-
A.
400 W
-
B.
200 W
-
C.
100 W
-
D.
500 W
Solution
Power (P) = Work Done / Time = 2000 J / 5 s = 400 W
Correct Answer:
A
— 400 W
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Q. If a machine does 3000 J of work in 10 seconds, what is its power output?
-
A.
300 W
-
B.
150 W
-
C.
600 W
-
D.
1000 W
Solution
Power (P) = Work (W) / Time (t) = 3000 J / 10 s = 300 W.
Correct Answer:
A
— 300 W
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Q. If a machine does 500 J of work in 10 seconds, what is its power output?
-
A.
50 W
-
B.
100 W
-
C.
200 W
-
D.
500 W
Solution
Power is calculated using the formula P = W/t. Here, W = 500 J and t = 10 s. Thus, P = 500 J / 10 s = 50 W.
Correct Answer:
B
— 100 W
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Q. If a machine does 500 J of work in 10 seconds, what is its power?
-
A.
50 W
-
B.
100 W
-
C.
200 W
-
D.
500 W
Solution
Power = Work / Time = 500 J / 10 s = 50 W.
Correct Answer:
A
— 50 W
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