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Q. If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?

A. 30 J
B. 60 J
C. 120 J
D. 180 J

Solution

Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 120 J

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Q. If a force of 15 N is applied to a 3 kg object, what is the net force acting on the object if it is already moving with a velocity of 5 m/s? (2022)

A. 15 N
B. 3 N
C. 0 N
D. 18 N

Solution

The net force is still 15 N as it does not depend on the velocity of the object.

Correct Answer: A — 15 N

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Q. If a force of 15 N is applied to a 3 kg object, what is the object's acceleration? (2023)

A. 3 m/s²
B. 5 m/s²
C. 7 m/s²
D. 10 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the acceleration of the mass? (2023)

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 4 m/s²

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if it is also experiencing a frictional force of 5 N?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if there is a frictional force of 5 N opposing the motion?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

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Q. If a force of 15 N is applied to move an object 3 m in the direction of the force, what is the work done?

A. 45 J
B. 30 J
C. 15 J
D. 60 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J.

Correct Answer: A — 45 J

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Q. If a force of 15 N is applied to move an object 3 m, what is the work done? (2023)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work Done (W) = Force * Distance = 15 N * 3 m = 45 J

Correct Answer: A — 45 J

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Q. If a force of 15 N is applied to move an object 4 m in the direction of the force, what is the work done?

A. 30 J
B. 60 J
C. 45 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: B — 60 J

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Q. If a force of 15 N moves an object 3 m in the direction of the force, what is the work done? (2022)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J

Correct Answer: A — 45 J

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Q. If a force of 20 N moves an object 5 m in the direction of the force, what is the work done?

A. 100 J
B. 50 J
C. 20 J
D. 200 J

Solution

Work = Force * Distance = 20 N * 5 m = 100 J.

Correct Answer: A — 100 J

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Q. If a force of 30 N is applied to a mass of 10 kg, what is the net force acting on the mass if there is a frictional force of 10 N opposing the motion?

A. 20 N
B. 30 N
C. 40 N
D. 10 N

Solution

Net force = applied force - frictional force = 30 N - 10 N = 20 N.

Correct Answer: A — 20 N

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Q. If a force of 5 N acts on an object and moves it 4 m in the direction of the force, what is the work done?

A. 10 J
B. 15 J
C. 20 J
D. 25 J

Solution

Work done = Force × Distance = 5 N × 4 m = 20 J.

Correct Answer: C — 20 J

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Q. If a force of 5 N is applied at an angle of 60 degrees to the horizontal while moving an object 3 m, what is the work done by the force?

A. 7.5 J
B. 15 J
C. 12.99 J
D. 10 J

Solution

Work done = Force × Distance × cos(θ) = 5 N × 3 m × cos(60°) = 5 N × 3 m × 0.5 = 7.5 J.

Correct Answer: C — 12.99 J

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Q. If a force of 5 N is applied at an angle of 60 degrees to the horizontal while moving an object 4 m, what is the work done by the force?

A. 10 J
B. 20 J
C. 5 J
D. 15 J

Solution

Work done = Force × Distance × cos(θ) = 5 N × 4 m × cos(60°) = 5 N × 4 m × 0.5 = 10 J.

Correct Answer: A — 10 J

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Q. If a force of 50 N is applied to a 25 kg object, what is the acceleration of the object? (2022)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. If a force of 50 N is applied to a 25 kg object, what is the resulting acceleration? (2022)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration = Force / Mass = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. If a force of 50 N is applied to a 25 kg object, what will be its acceleration? (2022)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration = Force / Mass = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. If a force of 50 N is applied to move an object 4 m in the direction of the force, what is the work done?

A. 100 J
B. 200 J
C. 150 J
D. 250 J

Solution

Work done W = F × d = 50 N × 4 m = 200 J.

Correct Answer: B — 200 J

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Q. If a forced oscillator is driven at a frequency much lower than its natural frequency, what happens to the amplitude?

A. Increases significantly
B. Decreases
C. Remains constant
D. Fluctuates

Solution

At frequencies much lower than the natural frequency, the amplitude of the forced oscillator increases significantly.

Correct Answer: B — Decreases

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Q. If a forest ecosystem has 200 trees and each tree produces 50 kg of oxygen per year, how much oxygen does the forest produce annually?

A. 5000 kg
B. 10000 kg
C. 15000 kg
D. 20000 kg

Solution

200 trees * 50 kg/tree = 10000 kg of oxygen.

Correct Answer: B — 10000 kg

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Q. If a function f is defined as f(x) = 3x + 2, what is the value of f(4)?

A. 14
B. 12
C. 10
D. 8

Solution

To find f(4), substitute x with 4: f(4) = 3(4) + 2 = 12 + 2 = 14.

Correct Answer: A — 14

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Q. If a function f(x) is defined as f(x) = 2x + 3, what is the slope of its graph?

A. 0
B. 2
C. 3
D. Undefined

Solution

In the linear function f(x) = mx + b, 'm' represents the slope, which is 2 in this case.

Correct Answer: B — 2

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Q. If a function f(x) is defined as f(x) = 2x + 3, what is the slope of the graph of this function?

A. 0
B. 2
C. 3
D. Undefined

Solution

In the linear function f(x) = 2x + 3, the coefficient of x (which is 2) represents the slope of the graph.

Correct Answer: B — 2

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Q. If a function f(x) is defined as f(x) = 2x + 3, what is the slope of the graph?

A. 0
B. 1
C. 2
D. 3

Solution

In the linear function f(x) = mx + b, 'm' represents the slope. Here, the slope is 2.

Correct Answer: C — 2

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Q. If a function f(x) is defined as f(x) = 2x + 3, what is the value of f(0)?

A. 0
B. 2
C. 3
D. 5

Solution

Substituting x = 0 into the function gives f(0) = 2(0) + 3 = 3.

Correct Answer: C — 3

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Q. If a function f(x) is defined as f(x) = 2x + 5, what is the slope of the graph?

A. 0
B. 2
C. 5
D. Undefined

Solution

In the linear function f(x) = mx + b, 'm' represents the slope. Here, m = 2.

Correct Answer: B — 2

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Q. If a function f(x) is defined as f(x) = 3x + 2, what is the value of f(4)?

A. 14
B. 12
C. 10
D. 8

Solution

To find f(4), substitute x with 4: f(4) = 3(4) + 2 = 12 + 2 = 14.

Correct Answer: A — 14

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Q. If a function f(x) is defined as f(x) = 3x - 5, what is the slope of the graph of this function?

A. 3
B. -5
C. 0
D. Undefined

Solution

In the linear function f(x) = mx + b, m represents the slope. Here, m = 3, so the slope is 3.

Correct Answer: A — 3

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Q. If a function f(x) is defined as f(x) = 3x - 5, what is the slope of the graph?

A. 3
B. -5
C. 0
D. Undefined

Solution

In the linear function f(x) = mx + b, 'm' represents the slope, which is 3 in this case.

Correct Answer: A — 3

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Major Competitive Exams

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