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Q. If a force of 10 N is applied to a mass of 2 kg, what will be the acceleration of the mass? (2019)

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a force of 10 N is applied to an object and it moves 3 m in the direction of the force, what is the work done? (2021)

A. 30 J
B. 20 J
C. 10 J
D. 15 J

Solution

Work done W = F * d = 10 N * 3 m = 30 J.

Correct Answer: A — 30 J

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Q. If a force of 10 N is applied to an object of mass 2 kg, what is its acceleration?

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a force of 10 N is applied to move an object 3 m in the direction of the force, what is the work done?

A. 30 J
B. 10 J
C. 3 J
D. 0 J

Solution

Work done = Force * Distance = 10 N * 3 m = 30 J.

Correct Answer: A — 30 J

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Q. If a force of 10 N is applied to move an object 5 m in the direction of the force, what is the work done?

A. 50 J
B. 30 J
C. 20 J
D. 10 J

Solution

Work Done (W) = Force * Distance = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

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Q. If a force of 10 N is applied to move an object 5 m, what is the work done?

A. 50 J
B. 25 J
C. 10 J
D. 5 J

Solution

Work Done (W) = Force * Distance = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

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Q. If a force of 10 N moves an object 5 m in the direction of the force, what is the work done? (2020)

A. 50 J
B. 10 J
C. 5 J
D. 25 J

Solution

Work Done (W) = Force (F) * Distance (d) = 10 N * 5 m = 50 J

Correct Answer: A — 50 J

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Q. If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?

A. 6 Nm
B. 10 Nm
C. 12 Nm
D. 15 Nm

Solution

Torque = Force × Distance × sin(θ) = 12 N × 1 m × sin(30°) = 12 N × 1 m × 0.5 = 6 Nm.

Correct Answer: A — 6 Nm

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Q. If a force of 12 N is applied at an angle of 30 degrees to the horizontal while moving an object 3 m, what is the work done by the force?

A. 18 J
B. 24 J
C. 30 J
D. 36 J

Solution

Work done = F × d × cos(θ) = 12 N × 3 m × cos(30°) = 12 N × 3 m × (√3/2) = 18 J.

Correct Answer: B — 24 J

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Q. If a force of 12 N is applied to a 4 kg object, what is the resulting acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 12 N / 4 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. If a force of 15 N acts on an object and moves it 4 m in the direction of the force, what is the work done?

A. 30 J
B. 60 J
C. 75 J
D. 90 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: B — 60 J

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Q. If a force of 15 N is applied at a distance of 0.4 m from the pivot, what is the torque?

A. 6 Nm
B. 12 Nm
C. 15 Nm
D. 20 Nm

Solution

Torque = Force × Distance = 15 N × 0.4 m = 6 Nm.

Correct Answer: B — 12 Nm

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Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1.5 m, what is the torque about the pivot?

A. 3.75 Nm
B. 7.5 Nm
C. 11.25 Nm
D. 12.99 Nm

Solution

Torque (τ) = F × r × sin(θ) = 15 N × 1.5 m × sin(30°) = 15 × 1.5 × 0.5 = 11.25 Nm.

Correct Answer: B — 7.5 Nm

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Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1 m, what is the torque about the pivot?

A. 7.5 Nm
B. 15 Nm
C. 12.99 Nm
D. 10 Nm

Solution

Torque (τ) = F × r × sin(θ) = 15 N × 1 m × sin(30°) = 15 N × 1 m × 0.5 = 7.5 Nm.

Correct Answer: C — 12.99 Nm

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Q. If a force of 15 N is applied at an angle of 60 degrees to the horizontal while moving an object 4 m, what is the work done by the force?

A. 30 J
B. 60 J
C. 120 J
D. 180 J

Solution

Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 120 J

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Q. If a force of 15 N is applied at an angle of 60° to the horizontal and moves an object 4 m, what is the work done? (2021)

A. 30 J
B. 60 J
C. 45 J
D. 20 J

Solution

Work done (W) = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 45 J

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Q. If a force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m, what is the work done by the force?

A. 30 J
B. 60 J
C. 120 J
D. 180 J

Solution

Work done = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 120 J

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Q. If a force of 15 N is applied to a 3 kg object, what is the net force acting on the object if it is already moving with a velocity of 5 m/s? (2022)

A. 15 N
B. 3 N
C. 0 N
D. 18 N

Solution

The net force is still 15 N as it does not depend on the velocity of the object.

Correct Answer: A — 15 N

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Q. If a force of 15 N is applied to a 3 kg object, what is the object's acceleration? (2023)

A. 3 m/s²
B. 5 m/s²
C. 7 m/s²
D. 10 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the acceleration of the mass? (2023)

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: B — 4 m/s²

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if it is also experiencing a frictional force of 5 N?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

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Q. If a force of 15 N is applied to a mass of 3 kg, what is the net force acting on the mass if there is a frictional force of 5 N opposing the motion?

A. 10 N
B. 15 N
C. 20 N
D. 5 N

Solution

Net force = applied force - frictional force = 15 N - 5 N = 10 N.

Correct Answer: A — 10 N

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Q. If a force of 15 N is applied to move an object 3 m in the direction of the force, what is the work done?

A. 45 J
B. 30 J
C. 15 J
D. 60 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J.

Correct Answer: A — 45 J

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Q. If a force of 15 N is applied to move an object 3 m, what is the work done? (2023)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work Done (W) = Force * Distance = 15 N * 3 m = 45 J

Correct Answer: A — 45 J

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Q. If a force of 15 N is applied to move an object 4 m in the direction of the force, what is the work done?

A. 30 J
B. 60 J
C. 45 J
D. 75 J

Solution

Work done = Force × Distance = 15 N × 4 m = 60 J.

Correct Answer: B — 60 J

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Q. If a force of 15 N moves an object 3 m in the direction of the force, what is the work done? (2022)

A. 45 J
B. 30 J
C. 60 J
D. 15 J

Solution

Work done = Force × Distance = 15 N × 3 m = 45 J

Correct Answer: A — 45 J

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Q. If a force of 20 N moves an object 5 m in the direction of the force, what is the work done?

A. 100 J
B. 50 J
C. 20 J
D. 200 J

Solution

Work = Force * Distance = 20 N * 5 m = 100 J.

Correct Answer: A — 100 J

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Q. If a force of 30 N is applied to a mass of 10 kg, what is the net force acting on the mass if there is a frictional force of 10 N opposing the motion?

A. 20 N
B. 30 N
C. 40 N
D. 10 N

Solution

Net force = applied force - frictional force = 30 N - 10 N = 20 N.

Correct Answer: A — 20 N

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Q. If a force of 5 N acts on an object and moves it 4 m in the direction of the force, what is the work done?

A. 10 J
B. 15 J
C. 20 J
D. 25 J

Solution

Work done = Force × Distance = 5 N × 4 m = 20 J.

Correct Answer: C — 20 J

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Q. If a force of 5 N is applied at an angle of 60 degrees to the horizontal while moving an object 3 m, what is the work done by the force?

A. 7.5 J
B. 15 J
C. 12.99 J
D. 10 J

Solution

Work done = Force × Distance × cos(θ) = 5 N × 3 m × cos(60°) = 5 N × 3 m × 0.5 = 7.5 J.

Correct Answer: C — 12.99 J

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Major Competitive Exams

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