General Aptitude

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General Aptitude

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General Aptitude MCQ & Objective Questions

General Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your problem-solving skills but also boosts your confidence during exams. Practicing MCQs and objective questions helps you familiarize yourself with the exam format, identify important questions, and improve your overall performance in exam preparation.

What You Will Practise Here

Numerical Ability: Basic arithmetic, percentages, and ratios.
Logical Reasoning: Patterns, sequences, and analogies.
Data Interpretation: Reading charts, graphs, and tables.
Verbal Ability: Synonyms, antonyms, and comprehension.
Quantitative Aptitude: Algebra, geometry, and measurements.
Time and Work: Problems related to efficiency and time management.
Profit and Loss: Understanding financial transactions and calculations.

Exam Relevance

General Aptitude is a significant part of the curriculum for CBSE, State Boards, NEET, JEE, and various other competitive exams. Questions often focus on logical reasoning and quantitative skills, with patterns that include multiple-choice questions, fill-in-the-blanks, and problem-solving scenarios. Familiarity with these formats will help you tackle the exams with ease.

Common Mistakes Students Make

Misinterpreting questions due to lack of careful reading.
Overlooking units in numerical problems, leading to incorrect answers.
Rushing through calculations, resulting in simple arithmetic errors.
Neglecting to practice time management during mock tests.
Confusing similar concepts in logical reasoning sections.

FAQs

Question: What are General Aptitude MCQ questions?
Answer: General Aptitude MCQ questions are multiple-choice questions designed to test your reasoning, numerical, and analytical skills relevant to various exams.

Question: How can I improve my performance in General Aptitude objective questions?
Answer: Regular practice of important General Aptitude questions for exams, along with reviewing your mistakes, can significantly enhance your performance.

Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence for your upcoming exams. Every question you tackle brings you one step closer to success!

Arithmetic Aptitude Data Interpretation

Q. A shopkeeper sells a shirt for $300 after giving a discount of 25% on the marked price. What was the marked price?

A. $350
B. $400
C. $450
D. $500

Solution

Let Marked Price = x. Selling Price = x - 25% of x = 0.75x. 0.75x = 300. x = 300/0.75 = 400.

Correct Answer: B — $400

Q. A shopkeeper sells a toy for $60, making a profit of 20%. What was the cost price?

A. $50
B. $55
C. $45
D. $60

Solution

Let Cost Price = x. Selling Price = x + 20% of x = 1.2x. 1.2x = 60. x = 60/1.2 = 50.

Correct Answer: A — $50

Q. A shopkeeper sells an article for $120, making a profit of 20%. What was the cost price of the article?

A. $100
B. $110
C. $90
D. $80

Solution

Let the cost price be x. Then, selling price = x + 20% of x = 1.2x. Given selling price = $120, we have 1.2x = 120. Therefore, x = 120 / 1.2 = $100.

Correct Answer: A — $100

Q. A shopkeeper sells an article for $240 after allowing a discount of 20%. What is the marked price?

A. $300
B. $250
C. $280
D. $320

Solution

Let the marked price be x. Then, 240 = x - 0.2x => 240 = 0.8x => x = 240/0.8 = $300.

Correct Answer: A — $300

Q. A shopkeeper sells an article for $240 after allowing a discount of 20%. What was the marked price?

A. $300
B. $280
C. $250
D. $320

Solution

Let the marked price be x. Then, 240 = x - 0.2x => 240 = 0.8x => x = 240/0.8 = $300.

Correct Answer: A — $300

Q. A shopkeeper sells an item for $240 after a profit of 20%. What was the cost price?

A. $200
B. $220
C. $180
D. $240

Solution

Let Cost Price = x. Selling Price = x + 20% of x = 1.2x. Therefore, 1.2x = 240. x = 240/1.2 = 200.

Correct Answer: A — $200

Q. A solution contains 10% salt. If 200 ml of the solution is taken, how much salt is in it?

A. 10 g
B. 20 g
C. 15 g
D. 25 g

Solution

Salt in the solution = 10% of 200 ml = 0.1 * 200 = 20 g.

Correct Answer: A — 10 g

Q. A solution contains 15% salt. If you have 80 liters of this solution, how much salt is present?

A. 10 liters
B. 12 liters
C. 15 liters
D. 18 liters

Solution

Salt = 15% of 80 liters = 0.15 * 80 = 12 liters.

Correct Answer: C — 15 liters

Q. A solution contains 25% salt. If 20 liters of the solution is taken out and replaced with water, what is the concentration of salt in the new solution?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Removing 20 liters of 25% salt solution removes 5 liters of salt. The remaining solution has 15 liters of salt in 80 liters total, so the concentration remains 25%.

Correct Answer: B — 25%

Q. A solution contains 40% salt. If you have 60 liters of this solution, how much salt is present?

A. 20 liters
B. 24 liters
C. 30 liters
D. 36 liters

Solution

Salt = 40% of 60 liters = 0.4 * 60 = 24 liters.

Correct Answer: B — 24 liters

Q. A solution is made by mixing 60 liters of a 20% salt solution with 40 liters of a 30% salt solution. What is the percentage of salt in the resulting mixture?

A. 24%
B. 26%
C. 28%
D. 30%

Solution

Salt in 60 liters of 20% solution = 12 liters. Salt in 40 liters of 30% solution = 12 liters. Total salt = 24 liters in 100 liters of mixture. Percentage = (24/100) * 100 = 24%.

Correct Answer: B — 26%

Q. A solution is made by mixing 60 liters of a 20% salt solution with 40 liters of a 30% salt solution. What is the percentage of salt in the new mixture?

A. 24%
B. 26%
C. 28%
D. 30%

Solution

Salt in 60 liters of 20% solution = 0.2 * 60 = 12 liters. Salt in 40 liters of 30% solution = 0.3 * 40 = 12 liters. Total salt = 12 + 12 = 24 liters. Total mixture = 60 + 40 = 100 liters. Percentage of salt = (24/100) * 100 = 24%.

Correct Answer: B — 26%

Q. A sphere has a diameter of 10 cm. What is its volume? (Use π = 3.14)

A. 523.33 cm³
B. 314 cm³
C. 157.08 cm³
D. 78.5 cm³

Solution

Volume = (4/3)πr³ = (4/3) * 3.14 * (5)³ = 523.33 cm³

Correct Answer: A — 523.33 cm³

Q. A sphere has a radius of 7 cm. What is the surface area of the sphere?

A. 154 cm²
B. 308 cm²
C. 616 cm²
D. 44 cm²

Solution

Surface Area = 4πr² = 4 * π * 7² = 4 * 3.14 * 49 = 615.44 cm².

Correct Answer: B — 308 cm²

Q. A sphere has a radius of 7 cm. What is the volume of the sphere?

A. 143.67 cm³
B. 154.00 cm³
C. 200.00 cm³
D. 180.00 cm³

Solution

Volume = (4/3)πr³ = (4/3) * 3.14 * 7³ = (4/3) * 3.14 * 343 = 1436.76 cm³.

Correct Answer: A — 143.67 cm³

Q. A square has a perimeter of 40 cm. What is its area?

A. 100 cm²
B. 200 cm²
C. 160 cm²
D. 80 cm²

Solution

Perimeter = 4 × side; side = 40 cm / 4 = 10 cm. Area = side² = 10 cm × 10 cm = 100 cm².

Correct Answer: A — 100 cm²

Q. A square has a perimeter of 40 m. What is its area?

A. 100 m²
B. 200 m²
C. 160 m²
D. 80 m²

Solution

Side = perimeter/4 = 40 m/4 = 10 m. Area = side² = (10 m)² = 100 m².

Correct Answer: A — 100 m²

Q. A square has a perimeter of 40 meters. What is the area of the square in square meters?

A. 100
B. 160
C. 200
D. 250

Solution

Perimeter = 4 × side; side = 40/4 = 10 meters. Area = side² = 10² = 100 square meters.

Correct Answer: A — 100

Q. A square has a side length of 8 meters. What is the area of the square in square meters?

A. 64
B. 72
C. 80
D. 88

Solution

Area = side² = 8² = 64 square meters.

Correct Answer: A — 64

Q. A square plot has a side length of 10 meters. What is the area of the plot?

A. 100
B. 80
C. 90
D. 70

Solution

Area = side × side = 10 × 10 = 100 square meters.

Correct Answer: A — 100

Q. A square plot has a side length of 12 meters. What is the area of the plot in square meters?

A. 120
B. 144
C. 150
D. 160

Solution

Area = side² = 12² = 144 square meters.

Correct Answer: B — 144

Q. A stock is bought for $500 and sold for $450. What is the loss percentage?

A. 10%
B. 15%
C. 20%
D. 25%

Solution

Loss = Cost Price - Selling Price = 500 - 450 = 50. Loss Percentage = (Loss / Cost Price) * 100 = (50 / 500) * 100 = 10%

Correct Answer: C — 20%

Q. A stock is bought for $80 and sold for $100. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit Percentage = [(Selling Price - Cost Price) / Cost Price] * 100 = [(100 - 80) / 80] * 100 = 25%.

Correct Answer: B — 25%

Q. A stock is sold at a loss of 10%. If the cost price is $300, what is the selling price?

A. $270
B. $300
C. $330
D. $150

Solution

Selling Price = Cost Price - (Loss% of Cost Price) = 300 - (10/100 * 300) = 300 - 30 = $270

Correct Answer: A — $270

Q. A stock is sold at a loss of 10%. If the cost price is $500, what is the selling price?

A. $450
B. $500
C. $550
D. $600

Solution

Selling Price = Cost Price - (Loss% of Cost Price) = 500 - (10/100 * 500) = 500 - 50 = $450

Correct Answer: A — $450

Q. A stock is sold at a loss of 10%. If the selling price is $90, what was the cost price?

A. $100
B. $110
C. $80
D. $90

Solution

Let Cost Price = x. Selling Price = x - 10% of x = 0.9x. Therefore, 0.9x = 90, x = 90 / 0.9 = $100

Correct Answer: A — $100

Q. A stock worth $150 is sold at a loss of 10%. What is the selling price?

A. $135
B. $140
C. $145
D. $150

Solution

Selling Price = Cost Price - (Loss% of Cost Price) = 150 - (10/100 * 150) = 150 - 15 = $135

Correct Answer: A — $135

Q. A stock's price decreased from $120 to $90. What is the percentage decrease?

A. 25%
B. 30%
C. 20%
D. 15%

Solution

Percentage Decrease = ((Old Price - New Price) / Old Price) * 100 = ((120 - 90) / 120) * 100 = 25%

Correct Answer: B — 30%

Q. A stock's price decreased from $200 to $150. What is the percentage decrease?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage Decrease = [(Old Price - New Price) / Old Price] * 100 = [(200 - 150) / 200] * 100 = 25%.

Correct Answer: B — 25%

Q. A stock's price decreased from $80 to $64. What is the percentage decrease?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Percentage Decrease = [(Old Price - New Price) / Old Price] * 100 = [(80 - 64) / 80] * 100 = 20%.

Correct Answer: C — 25%

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