The energy stored in a capacitor is given by the formula E = 0.5 * C * V^2. Here, E = 0.5 * 5 * 10^-6 F * (10 V)^2 = 0.5 * 5 * 10^-6 * 100 = 0.25 mJ.

A capacitor stores energy in the form of an electric field between its plates.

The height of the water column in a capillary tube is determined by both surface tension and the density of the liquid.

The water surface inside the capillary tube is concave due to the adhesive forces between water and the tube material being stronger than the cohesive forces among water molecules.

Using the capillary rise formula, h = (2γcosθ)/(ρgr), where γ is surface tension, θ is contact angle, ρ is density, g is acceleration due to gravity, and r is radius.

The height of the liquid column in a capillary tube is determined by both surface tension and the density of the liquid, as described by the capillary rise formula.

The rise of water in a capillary tube is due to both surface tension (which pulls the liquid up) and adhesion (the attraction between water molecules and the tube's surface).

The water will rise in the capillary tube due to capillary action, which is a result of surface tension.

Using the formula h = 2γ/(ρgr), h = 2 × 0.072 N/m / (1000 kg/m³ × 9.81 m/s² × 0.0005 m) = 0.2 m.

Using the equation of motion: s = ut + (1/2)at². Here, u = 0, a = 2 m/s², t = 5 s. So, s = 0 + (1/2)(2)(5²) = 25 m.

Using the formula s = ut + (1/2)at²; s = 0 + (1/2)(2)(10²) = 100 m.

Using the formula v = u + at, where u = 0, a = 2 m/s², and t = 5 s, we get v = 0 + 2 * 5 = 10 m/s.

Using F = ma, F = 1000 kg * 2 m/s² = 2000 N.

Acceleration = (Final Speed - Initial Speed)/Time = (100 km/h × (1000 m/3600 s))/10 s = 5 m/s²

Using the formula d = ut + 0.5at², where u = 0, a = (20 m/s) / 10 s = 2 m/s², we get d = 0 + 0.5 * 2 * (10)² = 100 m.

Acceleration is calculated using the formula a = (final velocity - initial velocity) / time. Here, a = (20 m/s - 0 m/s) / 5 s = 4 m/s².

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2 - u^2) = 1/2 * 1000 kg * (20 m/s)^2 = 200,000 J

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200,000 J.

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 1000 kg × (20 m/s)² = 0.5 × 1000 × 400 = 200000 J.

Acceleration (a) = (final velocity - initial velocity) / time = (30 m/s - 0) / 10 s = 3 m/s².

Using the formula d = ut + 0.5at², where u = 0, a = (30 m/s) / 10 s = 3 m/s², we get d = 0 + 0.5 * 3 * (10)² = 150 m.

Work done = Change in Kinetic Energy = 0.5 × mass × (final speed² - initial speed²) = 0.5 × 800 kg × (30 m/s)² = 360,000 J.

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, initial velocity = 0, final velocity = 20 m/s, time = 10 s. Acceleration = (final velocity - initial velocity) / time = 2 m/s². Distance = 0 + 0.5 * 2 * 10² = 100 m.

Distance (s) = ut + (1/2)at^2. Here, a = (v-u)/t = (25-0)/10 = 2.5 m/s². So, s = 0 + (1/2)*2.5*10^2 = 125 m.

Using the formula s = ut + (1/2)at². Here, u = 0, a = (25-0)/10 = 2.5 m/s². s = 0 + (1/2)(2.5)(10²) = 125 m.

Speed = Distance / Time = 120 km / 2 hours = 60 km/h.

Speed = Distance / Time = 150 km / 3 h = 50 km/h.