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Q. What is the equilibrium constant expression for the reaction: aA + bB ⇌ cC + dD?

A. K = [C]^c [D]^d / [A]^a [B]^b
B. K = [A]^a [B]^b / [C]^c [D]^d
C. K = [C]^c [D]^d
D. K = [A]^a [B]^b

Solution

The equilibrium constant K is defined as the ratio of the concentration of products to the concentration of reactants, each raised to the power of their coefficients in the balanced equation.

Correct Answer: A — K = [C]^c [D]^d / [A]^a [B]^b

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Q. What is the equivalent of 1 liter in cubic meters?

A. 0.001 m³
B. 0.01 m³
C. 0.1 m³
D. 1 m³

Solution

1 liter is equal to 0.001 cubic meters.

Correct Answer: A — 0.001 m³

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Q. What is the equivalent resistance of a 10Ω and a 5Ω resistor connected in parallel?

A. 3.33Ω
B. 7.5Ω
C. 15Ω
D. 5Ω

Solution

R_eq = 1/(1/10 + 1/5) = 3.33Ω.

Correct Answer: A — 3.33Ω

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Q. What is the equivalent resistance of a 6Ω and a 3Ω resistor connected in parallel?

A. 2Ω
B. 4Ω
C. 1.5Ω
D. 9Ω

Solution

R_eq = 1/(1/6 + 1/3) = 2Ω.

Correct Answer: B — 4Ω

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Q. What is the equivalent resistance of a circuit with a 10 ohm and a 5 ohm resistor in series?

A. 15 ohms
B. 5 ohms
C. 10 ohms
D. 20 ohms

Solution

For resistors in series, R_eq = R1 + R2 = 10 ohms + 5 ohms = 15 ohms.

Correct Answer: A — 15 ohms

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Q. What is the equivalent resistance of a circuit with two 10Ω resistors in series and one 5Ω resistor in parallel with them?

A. 5Ω
B. 10Ω
C. 15Ω
D. 20Ω

Solution

R_series = 10Ω + 10Ω = 20Ω. R_parallel = 1/(1/20 + 1/5) = 4Ω. Therefore, R_eq = 4Ω.

Correct Answer: C — 15Ω

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Q. What is the equivalent resistance of a circuit with two resistors R1 = 10Ω and R2 = 10Ω in parallel?

A. 5Ω
B. 10Ω
C. 20Ω
D. 15Ω

Solution

The equivalent resistance in parallel is given by 1/R_total = 1/R1 + 1/R2 = 1/10 + 1/10 = 1/5. Therefore, R_total = 5Ω.

Correct Answer: A — 5Ω

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Q. What is the equivalent resistance of three resistors of 2 ohms, 3 ohms, and 6 ohms connected in series?

A. 1 ohm
B. 3 ohms
C. 11 ohms
D. 12 ohms

Solution

In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11 ohms.

Correct Answer: C — 11 ohms

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Q. What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 5Ω connected in parallel?

A. 1Ω
B. 2Ω
C. 0.83Ω
D. 10Ω

Solution

1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus Req = 1.2Ω.

Correct Answer: C — 0.83Ω

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Q. What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?

A. 11Ω
B. 10Ω
C. 9Ω
D. 12Ω

Solution

In series, R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11Ω.

Correct Answer: A — 11Ω

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Q. What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in parallel?

A. 1Ω
B. 2Ω
C. 3Ω
D. 4Ω

Solution

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω.

Correct Answer: A — 1Ω

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Q. What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω connected in parallel?

A. 1Ω
B. 2Ω
C. 0.83Ω
D. 10Ω

Solution

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus R_eq = 1.2Ω.

Correct Answer: C — 0.83Ω

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Q. What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 6Ω connected in parallel?

A. 1Ω
B. 2Ω
C. 3Ω
D. 4Ω

Solution

1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, Req = 1Ω.

Correct Answer: B — 2Ω

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Q. What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?

A. 11Ω
B. 6Ω
C. 3Ω
D. 2Ω

Solution

In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2Ω + 3Ω + 6Ω = 11Ω.

Correct Answer: A — 11Ω

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Q. What is the equivalent resistance of three resistors, R1, R2, and R3, connected in series?

A. R1 + R2 + R3
B. 1/(1/R1 + 1/R2 + 1/R3)
C. R1 * R2 * R3
D. R1 - R2 - R3

Solution

In a series connection, the total or equivalent resistance is the sum of the individual resistances.

Correct Answer: A — R1 + R2 + R3

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Q. What is the equivalent resistance of two resistors of 10 ohms and 20 ohms connected in series?

A. 30 ohms
B. 20 ohms
C. 10 ohms
D. 5 ohms

Solution

In series, the equivalent resistance R_eq = R1 + R2 = 10 ohms + 20 ohms = 30 ohms.

Correct Answer: A — 30 ohms

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Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω connected in parallel?

A. 3Ω
B. 4Ω
C. 6Ω
D. 8Ω

Solution

Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/12 = 1/3. Therefore, R_eq = 3Ω.

Correct Answer: C — 6Ω

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Q. What is the equivalent resistance of two resistors of 5 ohms and 10 ohms connected in parallel?

A. 3.33 ohms
B. 15 ohms
C. 5 ohms
D. 7.5 ohms

Solution

Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2, we find R_eq = 1 / (1/5 + 1/10) = 3.33 ohms.

Correct Answer: A — 3.33 ohms

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Q. What is the equivalent resistance of two resistors of 5Ω and 10Ω connected in parallel?

A. 3.33Ω
B. 5Ω
C. 7.5Ω
D. 15Ω

Solution

1/Req = 1/R1 + 1/R2 = 1/5 + 1/10 = 2/10 + 1/10 = 3/10. Therefore, Req = 10/3 = 3.33Ω.

Correct Answer: A — 3.33Ω

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Q. What is the equivalent resistance of two resistors, 6 ohms and 3 ohms, connected in series?

A. 2 ohms
B. 3 ohms
C. 9 ohms
D. 18 ohms

Solution

In series, the equivalent resistance is the sum: R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.

Correct Answer: C — 9 ohms

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Q. What is the equivalent resistance of two resistors, 6Ω and 3Ω, connected in series?

A. 2Ω
B. 3Ω
C. 9Ω
D. 18Ω

Solution

In series, the equivalent resistance (R_eq) is the sum of the resistances: R_eq = 6Ω + 3Ω = 9Ω.

Correct Answer: C — 9Ω

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Q. What is the equivalent weight of H2SO4 if its molar mass is 98 g/mol?

A. 49 g
B. 98 g
C. 196 g
D. 24.5 g

Solution

Equivalent weight = molar mass / number of equivalents = 98 g/mol / 2 = 49 g.

Correct Answer: A — 49 g

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Q. What is the escape velocity for a satellite to leave Earth's gravitational field?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

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Q. What is the escape velocity for a satellite to leave the Earth's gravitational field?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

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Q. What is the escape velocity for a satellite to leave the Earth's gravitational influence?

A. 11.2 km/s
B. 7.9 km/s
C. 9.8 km/s
D. 15.0 km/s

Solution

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Correct Answer: A — 11.2 km/s

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Q. What is the escape velocity from the surface of a planet with a radius of 3R and mass 4M?

A. √(8GM/R)
B. √(6GM/R)
C. √(4GM/R)
D. √(10GM/R)

Solution

Escape velocity v = √(2GM/R); here, v = √(2 * 4GM / 3R) = √(8GM/3R).

Correct Answer: A — √(8GM/R)

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Q. What is the escape velocity from the surface of a planet with a radius of 4R and mass 2M?

A. 2√(GM/R)
B. √(8GM/R)
C. √(2GM/R)
D. 4√(GM/R)

Solution

Escape velocity v = √(2GM/R) = √(2 * 2M / 4R) = √(8GM/4R) = √(8GM/R)

Correct Answer: B — √(8GM/R)

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Q. What is the escape velocity from the surface of a planet with mass M and radius R?

A. √(2GM/R)
B. √(GM/R)
C. √(2R/G)
D. √(G/R)

Solution

Escape velocity is given by v = √(2GM/R).

Correct Answer: A — √(2GM/R)

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Q. What is the escape velocity from the surface of the Earth?

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 15 km/s

Solution

The escape velocity from the surface of the Earth is approximately 11.2 km/s.

Correct Answer: B — 11.2 km/s

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Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s^2, R = 6.4 x 10^6 m)

A. 7.9 km/s
B. 11.2 km/s
C. 9.8 km/s
D. 5.0 km/s

Solution

Escape velocity (v) = sqrt(2gR) = sqrt(2 * 9.8 * 6.4 x 10^6) ≈ 11.2 km/s.

Correct Answer: B — 11.2 km/s

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