Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the enthalpy change for the reaction 2Na + Cl2 → 2NaCl?
A.
-411 kJ
B.
-240 kJ
C.
0 kJ
D.
411 kJ
Show solution
Solution
The enthalpy change for the formation of NaCl from its elements is -411 kJ.
Correct Answer:
A
— -411 kJ
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Q. What is the enthalpy change for the reaction at constant pressure?
A.
ΔH = ΔU + PΔV
B.
ΔH = ΔU - PΔV
C.
ΔH = ΔU + VΔP
D.
ΔH = ΔU - VΔP
Show solution
Solution
At constant pressure, the enthalpy change is given by ΔH = ΔU + PΔV.
Correct Answer:
A
— ΔH = ΔU + PΔV
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Q. What is the enthalpy change for the reaction N2(g) + 3H2(g) → 2NH3(g) at standard conditions?
A.
-92.4 kJ
B.
-45.9 kJ
C.
0 kJ
D.
0.5 kJ
Show solution
Solution
The standard enthalpy change for the formation of ammonia is -92.4 kJ.
Correct Answer:
A
— -92.4 kJ
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Q. What is the enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(g)?
A.
It is positive.
B.
It is negative.
C.
It is zero.
D.
It is dependent on temperature.
Show solution
Solution
The formation of water from hydrogen and oxygen is an exothermic reaction, thus the enthalpy change is negative.
Correct Answer:
B
— It is negative.
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Q. What is the enthalpy change for the reaction: 2H2(g) + O2(g) → 2H2O(l)?
A.
-571.6 kJ
B.
-285.8 kJ
C.
0 kJ
D.
285.8 kJ
Show solution
Solution
The enthalpy change for the formation of 2 moles of water is -571.6 kJ.
Correct Answer:
A
— -571.6 kJ
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Q. What is the enthalpy change for the reaction: C(s) + O2(g) -> CO2(g)?
A.
-393.5 kJ/mol
B.
-241.8 kJ/mol
C.
0 kJ/mol
D.
285.8 kJ/mol
Show solution
Solution
The enthalpy change for the formation of CO2 from carbon and oxygen is -393.5 kJ/mol.
Correct Answer:
A
— -393.5 kJ/mol
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Q. What is the enthalpy change for the reaction: C(s) + O2(g) → CO2(g)?
A.
-393.5 kJ/mol
B.
-241.8 kJ/mol
C.
0 kJ/mol
D.
285.8 kJ/mol
Show solution
Solution
The enthalpy change for the formation of CO2 from its elements is -393.5 kJ/mol.
Correct Answer:
A
— -393.5 kJ/mol
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Q. What is the enthalpy change for the reaction: CaCO3(s) → CaO(s) + CO2(g)?
A.
It is an endothermic reaction.
B.
It is an exothermic reaction.
C.
It has no enthalpy change.
D.
It is spontaneous at all temperatures.
Show solution
Solution
The decomposition of calcium carbonate is an endothermic reaction, requiring heat input.
Correct Answer:
A
— It is an endothermic reaction.
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Q. What is the enthalpy change for the reaction: H2(g) + 1/2 O2(g) → H2O(l)?
A.
-285.8 kJ/mol
B.
0 kJ/mol
C.
-241.8 kJ/mol
D.
-572 kJ/mol
Show solution
Solution
The standard enthalpy change for the formation of water from its elements is -241.8 kJ/mol.
Correct Answer:
C
— -241.8 kJ/mol
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Q. What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g)?
A.
It is always positive.
B.
It is always negative.
C.
It can be either positive or negative depending on conditions.
D.
It is zero.
Show solution
Solution
The formation of ammonia from nitrogen and hydrogen is an exothermic reaction, thus the enthalpy change is negative.
Correct Answer:
B
— It is always negative.
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Q. What is the enthalpy change when 1 mole of NaCl is dissolved in water?
A.
-3.87 kJ
B.
0 kJ
C.
+3.87 kJ
D.
-7.0 kJ
Show solution
Solution
The enthalpy change when 1 mole of NaCl is dissolved in water is approximately -3.87 kJ.
Correct Answer:
A
— -3.87 kJ
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Q. What is the enthalpy change when 1 mole of water vapor condenses to liquid water?
A.
It is positive.
B.
It is negative.
C.
It is zero.
D.
It is dependent on pressure.
Show solution
Solution
The condensation of water vapor to liquid water releases heat, making the enthalpy change negative.
Correct Answer:
B
— It is negative.
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Q. What is the entropy change for a reversible isothermal expansion of an ideal gas?
A.
nR ln(Vf/Vi)
B.
0
C.
nR(Tf - Ti)
D.
nC ln(Vf/Vi)
Show solution
Solution
The entropy change for a reversible isothermal expansion of an ideal gas is ΔS = nR ln(Vf/Vi).
Correct Answer:
A
— nR ln(Vf/Vi)
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Q. What is the entropy change for a reversible isothermal process?
A.
Zero
B.
nR ln(Vf/Vi)
C.
nR(Tf - Ti)
D.
nR ln(Tf/Ti)
Show solution
Solution
The entropy change for a reversible isothermal process is ΔS = nR ln(Vf/Vi).
Correct Answer:
B
— nR ln(Vf/Vi)
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Q. What is the entropy change for a reversible process?
A.
Always positive
B.
Always negative
C.
Can be zero
D.
Depends on the path taken
Show solution
Solution
For a reversible process, the entropy change can be zero if the process is isothermal and reversible.
Correct Answer:
C
— Can be zero
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Q. What is the entropy change for a system that undergoes a phase transition at constant temperature?
A.
ΔS = 0
B.
ΔS = Q/T
C.
ΔS = T/Q
D.
ΔS = Q + T
Show solution
Solution
During a phase transition at constant temperature, the change in entropy is given by ΔS = Q/T, where Q is the heat absorbed or released.
Correct Answer:
B
— ΔS = Q/T
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Q. What is the entropy change for an ideal gas during an isothermal expansion?
A.
Zero
B.
nR ln(Vf/Vi)
C.
nC_v ln(Tf/Ti)
D.
nC_p ln(Tf/Ti)
Show solution
Solution
The entropy change for an ideal gas during an isothermal expansion is ΔS = nR ln(Vf/Vi).
Correct Answer:
B
— nR ln(Vf/Vi)
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Q. What is the entropy change for the isothermal expansion of an ideal gas from volume V1 to V2 at temperature T?
A.
R ln(V2/V1)
B.
R (V2 - V1)/T
C.
0
D.
R (V1/V2)
Show solution
Solution
The entropy change for an isothermal expansion is given by ΔS = nR ln(V2/V1). For 1 mole, ΔS = R ln(V2/V1).
Correct Answer:
A
— R ln(V2/V1)
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Q. What is the entropy change for the mixing of two ideal gases at constant temperature?
A.
0
B.
R ln(2)
C.
R ln(V1/V2)
D.
R ln(V1*V2)
Show solution
Solution
The entropy change for the mixing of two ideal gases at constant temperature is ΔS = nR ln(2) for equal moles of each gas.
Correct Answer:
B
— R ln(2)
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Q. What is the entropy change when 1 mole of an ideal gas is heated at constant volume from temperature T1 to T2?
A.
R ln(T2/T1)
B.
R (T2 - T1)
C.
0
D.
R (T1/T2)
Show solution
Solution
The change in entropy at constant volume is given by ΔS = nC_v ln(T2/T1). For 1 mole, ΔS = R ln(T2/T1).
Correct Answer:
A
— R ln(T2/T1)
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Q. What is the entropy change when 1 mole of an ideal gas is heated at constant volume?
A.
0
B.
R ln(T2/T1)
C.
R (T2 - T1)
D.
R (T1/T2)
Show solution
Solution
The change in entropy when heating an ideal gas at constant volume is given by ΔS = nC_v ln(T2/T1). For 1 mole, it simplifies to ΔS = R ln(T2/T1).
Correct Answer:
B
— R ln(T2/T1)
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Q. What is the entropy change when 1 mole of ice at 0°C is converted to water at 0°C?
A.
0 J/K
B.
R ln(2)
C.
R
D.
Positive value
Show solution
Solution
The phase change from ice to water at 0°C involves an increase in disorder, thus resulting in a positive change in entropy.
Correct Answer:
D
— Positive value
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Q. What is the entropy change when 2 moles of an ideal gas are compressed isothermally from volume V2 to V1?
A.
-R ln(V1/V2)
B.
R ln(V1/V2)
C.
0
D.
R (V2 - V1)
Show solution
Solution
The change in entropy for an isothermal compression is ΔS = nR ln(V1/V2). For 2 moles, ΔS = 2R ln(V1/V2), which is negative since V1 < V2.
Correct Answer:
A
— -R ln(V1/V2)
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Q. What is the equation for the displacement of a damped harmonic oscillator?
A.
x(t) = A e^(-bt) cos(ωt)
B.
x(t) = A e^(bt) cos(ωt)
C.
x(t) = A cos(ωt)
D.
x(t) = A e^(-bt) sin(ωt)
Show solution
Solution
The displacement of a damped harmonic oscillator is given by x(t) = A e^(-bt) cos(ωt), where b is the damping coefficient.
Correct Answer:
A
— x(t) = A e^(-bt) cos(ωt)
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Q. What is the equation of a circle with center at (-1, 2) and radius 4?
A.
(x + 1)² + (y - 2)² = 16
B.
(x - 1)² + (y + 2)² = 16
C.
(x + 1)² + (y + 2)² = 16
D.
(x - 1)² + (y - 2)² = 16
Show solution
Solution
Using the standard form, the equation is (x + 1)² + (y - 2)² = 4² = 16.
Correct Answer:
A
— (x + 1)² + (y - 2)² = 16
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Q. What is the equation of a circle with center at (2, -3) and radius 5?
A.
(x - 2)² + (y + 3)² = 25
B.
(x + 2)² + (y - 3)² = 25
C.
(x - 2)² + (y - 3)² = 25
D.
(x + 2)² + (y + 3)² = 25
Show solution
Solution
The standard form of a circle's equation is (x - h)² + (y - k)² = r², where (h, k) is the center and r is the radius.
Correct Answer:
A
— (x - 2)² + (y + 3)² = 25
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Q. What is the equation of a circle with center at (h, k) and radius r?
A.
(x - h)^2 + (y - k)^2 = r^2
B.
(x + h)^2 + (y + k)^2 = r^2
C.
(x - h)^2 - (y - k)^2 = r^2
D.
(x + h)^2 - (y + k)^2 = r^2
Show solution
Solution
The equation of a circle with center at (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2.
Correct Answer:
A
— (x - h)^2 + (y - k)^2 = r^2
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Q. What is the equation of an ellipse with foci at (±c, 0) and vertices at (±a, 0)?
A.
x^2/a^2 + y^2/b^2 = 1
B.
y^2/a^2 + x^2/b^2 = 1
C.
x^2/b^2 + y^2/a^2 = 1
D.
y^2/b^2 + x^2/a^2 = 1
Show solution
Solution
The standard form of the equation of an ellipse with horizontal major axis is x^2/a^2 + y^2/b^2 = 1.
Correct Answer:
A
— x^2/a^2 + y^2/b^2 = 1
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Q. What is the equation of motion for a damped harmonic oscillator?
A.
m d²x/dt² + b dx/dt + kx = 0
B.
m d²x/dt² + kx = 0
C.
m d²x/dt² + b dx/dt = 0
D.
m d²x/dt² + b dx/dt + kx = F(t)
Show solution
Solution
The equation of motion for a damped harmonic oscillator is m d²x/dt² + b dx/dt + kx = 0.
Correct Answer:
A
— m d²x/dt² + b dx/dt + kx = 0
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Q. What is the equation of motion for a simple harmonic oscillator with amplitude A and angular frequency ω?
A.
x(t) = A cos(ωt)
B.
x(t) = A sin(ωt)
C.
x(t) = A e^(ωt)
D.
x(t) = A ωt
Show solution
Solution
The equation of motion for SHM is x(t) = A cos(ωt) or x(t) = A sin(ωt).
Correct Answer:
A
— x(t) = A cos(ωt)
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