Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. How many grams of KCl are needed to prepare 0.5 moles of KCl?

A. 37.5 g
B. 45 g
C. 50 g
D. 60 g

Solution

The molar mass of KCl is approximately 74.5 g/mol. Therefore, 0.5 moles of KCl will weigh 0.5 x 74.5 g = 37.25 g.

Correct Answer: B — 45 g

Q. How many grams of KCl are needed to prepare 250 mL of a 0.5 M solution? (2023) 2023

A. 7.45 g
B. 12.5 g
C. 9.25 g
D. 5.25 g

Solution

Molar mass of KCl = 74.55 g/mol. Grams = Molarity * Volume (L) * Molar mass = 0.5 M * 0.25 L * 74.55 g/mol = 9.31 g.

Correct Answer: A — 7.45 g

Q. How many grams of KCl are needed to prepare 250 mL of a 2 M solution? (2023)

A. 37.25 g
B. 50 g
C. 75 g
D. 25 g

Solution

Molar mass of KCl = 74.55 g/mol. Grams = moles × molar mass = 0.5 moles × 74.55 g/mol = 37.25 g.

Correct Answer: A — 37.25 g

Q. How many grams of KCl are needed to prepare 250 mL of a 2 M solution? (Molar mass of KCl = 74.5 g/mol) (2023)

A. 37.25 g
B. 74.5 g
C. 18.625 g
D. 9.25 g

Solution

Grams = moles × molar mass = (2 moles/L × 0.25 L) × 74.5 g/mol = 37.25 g.

Correct Answer: A — 37.25 g

Q. How many grams of KCl can be produced from the reaction of 10 g of K with excess Cl2?

A. 74.5 g
B. 37.25 g
C. 148.5 g
D. 18.5 g

Solution

10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.

Correct Answer: A — 74.5 g

Q. How many grams of NaOH are needed to neutralize 1 mole of HCl?

A. 40 g
B. 36.5 g
C. 58.5 g
D. 23 g

Solution

The reaction between NaOH and HCl is 1:1. The molar mass of NaOH is 40 g/mol, so 1 mole of NaOH is needed, which weighs 40 g.

Correct Answer: C — 58.5 g

Q. How many grams of NaOH are needed to prepare 0.5 moles of NaOH solution?

A. 20 g
B. 40 g
C. 10 g
D. 30 g

Solution

The molar mass of NaOH is 40 g/mol. Therefore, to prepare 0.5 moles, you need 0.5 x 40 g = 20 g.

Correct Answer: B — 40 g

Q. How many grams of NaOH are needed to prepare 0.5 moles of NaOH solution? (Molar mass of NaOH = 40 g/mol)

A. 20 g
B. 40 g
C. 10 g
D. 30 g

Solution

To find the mass, use the formula: mass = moles × molar mass. Thus, 0.5 moles × 40 g/mol = 20 g.

Correct Answer: A — 20 g

Q. How many grams of protein are in a food item that provides 160 calories from protein? (Protein = 4 cal/g) (2022)

A. 30
B. 40
C. 50
D. 20

Solution

Grams of protein = 160 calories / 4 cal/g = 40 grams.

Correct Answer: B — 40

Q. How many grams of protein are recommended daily for an average adult?

A. 30 grams
B. 50 grams
C. 70 grams
D. 100 grams

Solution

The Recommended Dietary Allowance (RDA) for protein is about 50 grams for an average adult.

Correct Answer: B — 50 grams

Q. How many grams of solute are needed to prepare 0.5 L of a 1 M NaCl solution? (Molar mass of NaCl = 58.5 g/mol)

A. 29.25 g
B. 58.5 g
C. 14.625 g
D. 0.5 g

Solution

Mass of solute = moles × molar mass = 1 mol × 58.5 g/mol = 58.5 g. For 0.5 L, it is 0.5 mol × 58.5 g/mol = 29.25 g.

Correct Answer: A — 29.25 g

Q. How many grams of solute are needed to prepare 2 L of a 1 M solution? (Molar mass = 58.5 g/mol)

A. 58.5 g
B. 117 g
C. 29.25 g
D. 145 g

Solution

Grams of solute = moles x molar mass = 2 moles x 58.5 g/mol = 117 g.

Correct Answer: B — 117 g

Q. How many integers between 1 and 100 are multiples of 5?

A. 20
B. 19
C. 21
D. 22

Solution

Multiples of 5 from 1 to 100 are 5, 10, ..., 100. There are 20 multiples.

Correct Answer: A — 20

Q. How many isomers does C4H10 have?

A. 1
B. 2
C. 3
D. 4

Solution

C4H10 has 2 structural isomers: n-butane and isobutane.

Correct Answer: B — 2

Q. How many isomers does C5H12 have?

A. 2
B. 3
C. 4
D. 5

Solution

C5H12 has 3 structural isomers: pentane, isopentane, and neopentane.

Correct Answer: C — 4

Q. How many liters of a 0.5 M NaOH solution are needed to obtain 1 mole of NaOH? (2023)

A. 1 L
B. 2 L
C. 0.5 L
D. 0.25 L

Solution

Volume = moles / molarity = 1 mole / 0.5 M = 2 L.

Correct Answer: A — 1 L

Q. How many liters of a 0.5 M solution contain 2 moles of solute? (2023)

A. 2 L
B. 4 L
C. 1 L
D. 0.5 L

Solution

Volume = moles / molarity = 2 moles / 0.5 M = 4 L

Correct Answer: B — 4 L

Q. How many liters of a 3 M solution can be made from 6 moles of solute? (2023)

A. 1 L
B. 2 L
C. 3 L
D. 4 L

Solution

Volume = moles / molarity = 6 moles / 3 M = 2 L.

Correct Answer: B — 2 L

Q. How many member countries are there in the World Health Organization (WHO)?

A. 194
B. 200
C. 150
D. 180

Solution

As of now, there are 194 member countries in the WHO.

Correct Answer: A — 194

Q. How many members are nominated by the President of India to the Rajya Sabha? (2023)

A. 10
B. 12
C. 14
D. 15

Solution

The President of India nominates 12 members to the Rajya Sabha from among persons having special knowledge or practical experience in fields such as literature, science, art, and social service.

Correct Answer: B — 12

Q. How many members are nominated by the President to the Rajya Sabha? (2019)

A. 10
B. 12
C. 14
D. 15

Solution

The President of India nominates 12 members to the Rajya Sabha from among persons having special knowledge or practical experience in literature, science, art, and social service.

Correct Answer: B — 12

Q. How many members are nominated to the Rajya Sabha by the President of India? (2021)

A. 10
B. 12
C. 14
D. 15

Solution

The President of India nominates 12 members to the Rajya Sabha.

Correct Answer: B — 12

Q. How many members are there in the Lok Sabha?

A. 545
B. 550
C. 500
D. 600

Solution

The Lok Sabha can have a maximum of 552 members, but currently, it has 545 members as per Article 81 of the Constitution.

Correct Answer: A — 545

Q. How many members are there in the Rajya Sabha?

A. 250
B. 245
C. 240
D. 200

Solution

The Rajya Sabha can have a maximum of 250 members, out of which 238 are elected and 12 are nominated.

Correct Answer: B — 245

Q. How many members can the Governor nominate to the State Legislative Council?

A. 5
B. 10
C. 15
D. 20

Solution

The Governor can nominate 10 members to the State Legislative Council.

Correct Answer: B — 10

Q. How many members can the President of India nominate to the Rajya Sabha? (2022)

A. 10
B. 12
C. 14
D. 15

Solution

The President of India can nominate 12 members to the Rajya Sabha from among persons having special knowledge or practical experience in fields such as literature, science, art, and social service.

Correct Answer: B — 12

Q. How many millimeters are there in a meter?

A. 10
B. 100
C. 1000
D. 10000

Solution

There are 1000 millimeters in a meter.

Correct Answer: C — 1000

Q. How many molecules are in 0.1 moles of oxygen gas (O2)? (2021)

A. 6.022 x 10^22
B. 6.022 x 10^23
C. 1.2044 x 10^23
D. 3.011 x 10^23

Solution

Number of molecules = moles x Avogadro's number = 0.1 moles x 6.022 x 10^23 molecules/mole = 6.022 x 10^22 molecules.

Correct Answer: A — 6.022 x 10^22

Q. How many molecules are in 0.25 moles of oxygen gas (O2)? (2022)

A. 3.011 x 10^23
B. 6.022 x 10^22
C. 1.2044 x 10^23
D. 1.5055 x 10^23

Solution

Number of molecules = moles x Avogadro's number = 0.25 moles x 6.022 x 10^23 molecules/mole = 1.5055 x 10^23 molecules.

Correct Answer: B — 6.022 x 10^22

Q. How many molecules are present in 2 moles of water (H2O)?

A. 6.022 x 10^23
B. 1.2044 x 10^24
C. 3.011 x 10^23
D. 12.044 x 10^24

Solution

Number of molecules = moles x Avogadro's number = 2 moles x 6.022 x 10^23 molecules/mole = 1.2044 x 10^24 molecules.

Correct Answer: B — 1.2044 x 10^24

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