JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the electric field at a point midway between two equal and opposite charges?
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on distance
Show solution
Solution
The electric fields due to both charges cancel each other out at the midpoint, resulting in zero electric field.
Correct Answer:
A
— Zero
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Q. What is the electric field at a point on the axis of a dipole at a distance d from the center of the dipole?
A.
0
B.
p/(4πε₀d²)
C.
p/(2πε₀d²)
D.
p/(4πε₀d³)
Show solution
Solution
The electric field along the axis of a dipole at a distance d is given by E = (1/(4πε₀)) * (2p/d³), where p is the dipole moment.
Correct Answer:
D
— p/(4πε₀d³)
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Q. What is the electric field at a point outside a uniformly charged sphere of radius R and total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a point outside a uniformly charged sphere, the electric field behaves as if all the charge were concentrated at the center, so E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric field due to a point charge at a distance r?
A.
k * q / r^2
B.
k * q / r
C.
k * q * r
D.
k * q * r^2
Show solution
Solution
The electric field E due to a point charge q at a distance r is given by E = k * q / r^2, where k is Coulomb's constant.
Correct Answer:
A
— k * q / r^2
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Q. What is the electric field due to a point charge of +10μC at a distance of 0.2m?
A.
22500 N/C
B.
45000 N/C
C.
50000 N/C
D.
75000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (0.2 m)² = 225000 N/C.
Correct Answer:
C
— 50000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 0.1m?
A.
9000 N/C
B.
900 N/C
C.
90 N/C
D.
9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (0.1)^2 = 9000 N/C.
Correct Answer:
A
— 9000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 1m?
A.
9 × 10^9 N/C
B.
1 × 10^6 N/C
C.
9 × 10^6 N/C
D.
1 × 10^9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (1)^2 = 9 × 10^6 N/C.
Correct Answer:
C
— 9 × 10^6 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.1m?
A.
36000 N/C
B.
40000 N/C
C.
44000 N/C
D.
48000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)² = 36000 N/C.
Correct Answer:
B
— 40000 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.2m?
A.
4500 N/C
B.
9000 N/C
C.
18000 N/C
D.
36000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (4 × 10^-6) / (0.2)^2 = 9000 N/C.
Correct Answer:
B
— 9000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1 m?
A.
4500 N/C
B.
5000 N/C
C.
5500 N/C
D.
6000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 4500 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1m?
A.
4500 N/C
B.
5000 N/C
C.
45000 N/C
D.
50000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 45000 N/C.
Correct Answer:
C
— 45000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.2m?
A.
11250 N/C
B.
4500 N/C
C.
2250 N/C
D.
5625 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.2)^2 = 11250 N/C.
Correct Answer:
A
— 11250 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.3m? (2000)
A.
1500 N/C
B.
5000 N/C
C.
1000 N/C
D.
2000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.3)^2 = 5000 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a uniformly charged infinite plane sheet with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
2σ/ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet is E = σ/2ε₀ on both sides, thus total E = σ/ε₀.
Correct Answer:
C
— 2σ/ε₀
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Q. What is the electric field due to a uniformly charged infinite plane sheet?
A.
0
B.
σ/2ε₀
C.
σ/ε₀
D.
σ/4ε₀
Show solution
Solution
According to Gauss's law, the electric field due to an infinite plane sheet with surface charge density σ is E = σ/2ε₀, directed away from the sheet.
Correct Answer:
B
— σ/2ε₀
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Q. What is the electric field due to a uniformly charged line of charge with linear charge density λ at a distance r from the line?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
2λ/(πε₀r)
D.
λ/(ε₀r)
Show solution
Solution
Using Gauss's law, the electric field due to a uniformly charged line of charge is E = λ/(2πε₀r).
Correct Answer:
A
— λ/(2πε₀r)
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Q. What is the electric field due to an infinite plane sheet of charge with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
σ/4ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet of charge is given by E = σ/2ε₀, directed away from the sheet if the charge is positive.
Correct Answer:
A
— σ/2ε₀
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Q. What is the electric field inside a charged conductor in electrostatic equilibrium?
A.
Zero
B.
Constant
C.
Varies with distance
D.
Depends on charge density
Show solution
Solution
Inside a charged conductor in electrostatic equilibrium, the electric field is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged hollow sphere?
A.
Zero
B.
Uniform and equal to the surface field
C.
Varies linearly with distance from the center
D.
Depends on the charge outside the sphere
Show solution
Solution
According to Gauss's law, the electric field inside a uniformly charged hollow sphere is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged spherical shell?
A.
Zero
B.
Uniform
C.
Varies linearly
D.
Depends on the charge outside
Show solution
Solution
The electric field inside a uniformly charged spherical shell is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field outside a uniformly charged sphere of radius R with total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a uniformly charged sphere, outside the sphere, the electric field behaves as if all the charge were concentrated at the center, E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric flux through a closed surface surrounding a charge of -3Q?
A.
-3Q/ε₀
B.
3Q/ε₀
C.
0
D.
-6Q/ε₀
Show solution
Solution
According to Gauss's law, the electric flux through a closed surface is Φ = Q_enc/ε₀. Here, Q_enc = -3Q, so Φ = -3Q/ε₀.
Correct Answer:
A
— -3Q/ε₀
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Q. What is the electric flux through a closed surface surrounding a charge Q?
A.
0
B.
Q/ε₀
C.
Q/2ε₀
D.
Q/4ε₀
Show solution
Solution
According to Gauss's law, the electric flux Φ through a closed surface is given by Φ = Q/ε₀.
Correct Answer:
B
— Q/ε₀
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Q. What is the electric flux through a closed surface that encloses no charge?
A.
0
B.
Q/ε₀
C.
Q
D.
4πQ/ε₀
Show solution
Solution
According to Gauss's law, if there is no charge enclosed, the electric flux through the surface is zero.
Correct Answer:
A
— 0
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Q. What is the electric potential at a distance of 3 m from a charge of 10 μC?
A.
3000 V
B.
9000 V
C.
6000 V
D.
1000 V
Show solution
Solution
V = k * q / r = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (3 m) = 30000 V / 3 = 9000 V.
Correct Answer:
B
— 9000 V
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Q. What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
A.
4500 V
B.
1800 V
C.
2000 V
D.
None of the above
Show solution
Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Correct Answer:
B
— 1800 V
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Q. What is the electric potential at a point 0.3m away from a charge of +4μC?
A.
12000 V
B.
3000 V
C.
6000 V
D.
9000 V
Show solution
Solution
V = k * q / r = (9 × 10^9) * (4 × 10^-6) / 0.3 = 12000 V.
Correct Answer:
A
— 12000 V
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Q. What is the electric potential at a point due to a point charge?
A.
kQ/r
B.
Q/(4πε₀r²)
C.
kQ/(4πε₀r)
D.
Q/(4πr²)
Show solution
Solution
The electric potential V at a distance r from a point charge Q is given by V = kQ/r, where k is Coulomb's constant.
Correct Answer:
A
— kQ/r
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Q. What is the electric potential at a point due to a positive point charge?
A.
Zero
B.
Positive
C.
Negative
D.
Depends on distance
Show solution
Solution
The electric potential due to a positive point charge is positive and decreases with distance from the charge.
Correct Answer:
B
— Positive
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Q. What is the electric potential at a point in space where the electric field is zero?
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
Show solution
Solution
The electric potential can be positive or negative; it is not necessarily zero when the electric field is zero.
Correct Answer:
B
— Positive
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