Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the electric field at a point midway between two equal and opposite charges?
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on distance
Show solution
Solution
The electric fields due to both charges cancel each other out at the midpoint, resulting in zero electric field.
Correct Answer:
A
— Zero
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Q. What is the electric field at a point on the axis of a dipole at a distance d from the center of the dipole?
A.
0
B.
p/(4πε₀d²)
C.
p/(2πε₀d²)
D.
p/(4πε₀d³)
Show solution
Solution
The electric field along the axis of a dipole at a distance d is given by E = (1/(4πε₀)) * (2p/d³), where p is the dipole moment.
Correct Answer:
D
— p/(4πε₀d³)
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Q. What is the electric field at a point outside a uniformly charged sphere of radius R and total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a point outside a uniformly charged sphere, the electric field behaves as if all the charge were concentrated at the center, so E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric field due to a point charge at a distance r?
A.
k * q / r^2
B.
k * q / r
C.
k * q * r
D.
k * q * r^2
Show solution
Solution
The electric field E due to a point charge q at a distance r is given by E = k * q / r^2, where k is Coulomb's constant.
Correct Answer:
A
— k * q / r^2
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Q. What is the electric field due to a point charge of +10μC at a distance of 0.2m?
A.
22500 N/C
B.
45000 N/C
C.
50000 N/C
D.
75000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (0.2 m)² = 225000 N/C.
Correct Answer:
C
— 50000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 0.1m?
A.
9000 N/C
B.
900 N/C
C.
90 N/C
D.
9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (0.1)^2 = 9000 N/C.
Correct Answer:
A
— 9000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 1m?
A.
9 × 10^9 N/C
B.
1 × 10^6 N/C
C.
9 × 10^6 N/C
D.
1 × 10^9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (1)^2 = 9 × 10^6 N/C.
Correct Answer:
C
— 9 × 10^6 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.1m?
A.
36000 N/C
B.
40000 N/C
C.
44000 N/C
D.
48000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)² = 36000 N/C.
Correct Answer:
B
— 40000 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.2m?
A.
4500 N/C
B.
9000 N/C
C.
18000 N/C
D.
36000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (4 × 10^-6) / (0.2)^2 = 9000 N/C.
Correct Answer:
B
— 9000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1 m?
A.
4500 N/C
B.
5000 N/C
C.
5500 N/C
D.
6000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 4500 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1m?
A.
4500 N/C
B.
5000 N/C
C.
45000 N/C
D.
50000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 45000 N/C.
Correct Answer:
C
— 45000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.2m?
A.
11250 N/C
B.
4500 N/C
C.
2250 N/C
D.
5625 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.2)^2 = 11250 N/C.
Correct Answer:
A
— 11250 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.3m? (2000)
A.
1500 N/C
B.
5000 N/C
C.
1000 N/C
D.
2000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.3)^2 = 5000 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a uniformly charged infinite plane sheet with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
2σ/ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet is E = σ/2ε₀ on both sides, thus total E = σ/ε₀.
Correct Answer:
C
— 2σ/ε₀
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Q. What is the electric field due to a uniformly charged infinite plane sheet?
A.
0
B.
σ/2ε₀
C.
σ/ε₀
D.
σ/4ε₀
Show solution
Solution
According to Gauss's law, the electric field due to an infinite plane sheet with surface charge density σ is E = σ/2ε₀, directed away from the sheet.
Correct Answer:
B
— σ/2ε₀
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Q. What is the electric field due to a uniformly charged line of charge with linear charge density λ at a distance r from the line?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
2λ/(πε₀r)
D.
λ/(ε₀r)
Show solution
Solution
Using Gauss's law, the electric field due to a uniformly charged line of charge is E = λ/(2πε₀r).
Correct Answer:
A
— λ/(2πε₀r)
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Q. What is the electric field due to an infinite plane sheet of charge with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
σ/4ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet of charge is given by E = σ/2ε₀, directed away from the sheet if the charge is positive.
Correct Answer:
A
— σ/2ε₀
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Q. What is the electric field inside a charged conductor in electrostatic equilibrium?
A.
Zero
B.
Constant
C.
Varies with distance
D.
Depends on charge density
Show solution
Solution
Inside a charged conductor in electrostatic equilibrium, the electric field is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged hollow sphere?
A.
Zero
B.
Uniform and equal to the surface field
C.
Varies linearly with distance from the center
D.
Depends on the charge outside the sphere
Show solution
Solution
According to Gauss's law, the electric field inside a uniformly charged hollow sphere is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged spherical shell?
A.
Zero
B.
Uniform
C.
Varies linearly
D.
Depends on the charge outside
Show solution
Solution
The electric field inside a uniformly charged spherical shell is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field outside a uniformly charged sphere of radius R with total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a uniformly charged sphere, outside the sphere, the electric field behaves as if all the charge were concentrated at the center, E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric flux through a closed surface surrounding a charge of -3Q?
A.
-3Q/ε₀
B.
3Q/ε₀
C.
0
D.
-6Q/ε₀
Show solution
Solution
According to Gauss's law, the electric flux through a closed surface is Φ = Q_enc/ε₀. Here, Q_enc = -3Q, so Φ = -3Q/ε₀.
Correct Answer:
A
— -3Q/ε₀
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Q. What is the electric flux through a closed surface surrounding a charge Q?
A.
0
B.
Q/ε₀
C.
Q/2ε₀
D.
Q/4ε₀
Show solution
Solution
According to Gauss's law, the electric flux Φ through a closed surface is given by Φ = Q/ε₀.
Correct Answer:
B
— Q/ε₀
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Q. What is the electric flux through a closed surface that encloses no charge?
A.
0
B.
Q/ε₀
C.
Q
D.
4πQ/ε₀
Show solution
Solution
According to Gauss's law, if there is no charge enclosed, the electric flux through the surface is zero.
Correct Answer:
A
— 0
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Q. What is the electric potential at a distance of 3 m from a charge of 10 μC?
A.
3000 V
B.
9000 V
C.
6000 V
D.
1000 V
Show solution
Solution
V = k * q / r = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (3 m) = 30000 V / 3 = 9000 V.
Correct Answer:
B
— 9000 V
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Q. What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
A.
4500 V
B.
1800 V
C.
2000 V
D.
None of the above
Show solution
Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Correct Answer:
B
— 1800 V
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Q. What is the electric potential at a point 0.3m away from a charge of +4μC?
A.
12000 V
B.
3000 V
C.
6000 V
D.
9000 V
Show solution
Solution
V = k * q / r = (9 × 10^9) * (4 × 10^-6) / 0.3 = 12000 V.
Correct Answer:
A
— 12000 V
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Q. What is the electric potential at a point due to a point charge?
A.
kQ/r
B.
Q/(4πε₀r²)
C.
kQ/(4πε₀r)
D.
Q/(4πr²)
Show solution
Solution
The electric potential V at a distance r from a point charge Q is given by V = kQ/r, where k is Coulomb's constant.
Correct Answer:
A
— kQ/r
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Q. What is the electric potential at a point due to a positive point charge?
A.
Zero
B.
Positive
C.
Negative
D.
Depends on distance
Show solution
Solution
The electric potential due to a positive point charge is positive and decreases with distance from the charge.
Correct Answer:
B
— Positive
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Q. What is the electric potential at a point in space where the electric field is zero?
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
Show solution
Solution
The electric potential can be positive or negative; it is not necessarily zero when the electric field is zero.
Correct Answer:
B
— Positive
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