When a charged capacitor is short-circuited, the charge flows through the circuit, and the charge on the capacitor becomes zero.

Energy = 0.5 × C × V² = 0.5 × 6 × 10^-6 × 12² = 0.432 mJ.

Using the formula Q = CV, the charge Q = 5μF * 10V = 50μC.

When the voltage is increased to 10 V, the charge on the capacitor increases because charge (Q) is directly proportional to voltage (V) for a given capacitance.

When connected in parallel, charge redistributes, and the final voltage across both capacitors will be V/2.

The time constant τ of an RC circuit is given by τ = R * C.

When a capacitor is short-circuited, the stored energy is dissipated as heat in the circuit.

Short-circuiting a capacitor allows charge to flow off, resulting in the charge becoming zero.

In a DC circuit, the current through a capacitor decreases to zero as it becomes fully charged.

In an AC circuit, the current through a capacitor leads the voltage by 90 degrees.

When a charged capacitor is short-circuited, the stored energy is released as heat due to the current flow.

When a capacitor is fully discharged and connected to a voltage source, the initial current is maximum as it starts charging.

Charge (Q) on a capacitor is given by Q = C * V. Here, Q = 4μF * 12V = 48μC.

The energy (U) stored in a capacitor is given by the formula U = 1/2 CV^2.

The charge (Q) on a capacitor is given by Q = CV when connected to a voltage source V.

The charge (Q) stored in a capacitor is given by the formula Q = C * V.

Height = (2 × Surface Tension) / (Density × g × Radius) = (2 × 0.072 N/m) / (1000 kg/m³ × 9.81 m/s² × 0.0005 m) = 0.0144 m.

Speed = Initial speed + (Acceleration × Time) = 0 + (2 m/s² × 5 s) = 10 m/s.

Acceleration a = (final velocity - initial velocity) / time = (20 m/s - 0) / 5 s = 4 m/s².

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200000 J = 2000 J

Kinetic Energy (KE) = 0.5 × mass (m) × velocity² (v²). KE = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J

Acceleration = (final speed - initial speed) / time = (25 m/s - 0) / 5 s = 5 m/s².

Distance = ut + (1/2)at². Here, u = 0, a = (25-0)/10 = 2.5 m/s². Distance = 0 + (1/2)(2.5)(10²) = 125 m.

Acceleration = (Final Speed - Initial Speed) / Time = (20 m/s - 0) / 10 s = 2 m/s².

Fuel needed = (Distance / 100 km) × Fuel consumption = (250 km / 100) × 8 liters = 20 liters.

Average Speed = Total Distance / Total Time = 240 km / 3 h = 80 km/h.

Speed = Distance/Time = 150 km / 3 h = 50 km/h.

Speed = Distance / Time = 240 km / 3 hours = 80 km/h.

Average Force = Work / Distance = 2000 J / 50 m = 40 N