JEE Main Preparation Resources for Competitive Exams

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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. What is the direction of the magnetic field produced by a current-carrying wire using the right-hand rule?

A. Towards the wire
B. Away from the wire
C. Clockwise
D. Counterclockwise

Solution

Using the right-hand rule, the magnetic field direction is counterclockwise around the wire.

Correct Answer: D — Counterclockwise

Q. What is the direction of the magnetic field produced by a current-carrying wire according to the right-hand rule?

A. Towards the wire
B. Away from the wire
C. Perpendicular to the wire in the direction of current
D. Perpendicular to the wire in the opposite direction of current

Solution

According to the right-hand rule, if you point your thumb in the direction of the current, your fingers curl in the direction of the magnetic field.

Correct Answer: C — Perpendicular to the wire in the direction of current

Q. What is the directrix of the parabola given by the equation y^2 = 8x?

A. x = -2
B. x = 2
C. y = -4
D. y = 4

Solution

The standard form of a parabola is (y - k)^2 = 4p(x - h). Here, p = 2, so the directrix is x = -2.

Correct Answer: A — x = -2

Q. What is the directrix of the parabola y^2 = 8x?

A. x = -2
B. x = 2
C. y = -4
D. y = 4

Solution

For the parabola y^2 = 4px, here 4p = 8, so p = 2. The directrix is x = -p = -2.

Correct Answer: A — x = -2

Q. What is the distance between the centers of two circles with equations (x - 1)² + (y - 2)² = 9 and (x + 3)² + (y + 4)² = 16?

A. 5
B. 10
C. 8
D. 6

Solution

The distance between centers (1, 2) and (-3, -4) is calculated using the distance formula.

Correct Answer: D — 6

Q. What is the distance between the foci of the ellipse given by the equation 4x^2 + 9y^2 = 36?

A. 6
B. 4
C. 8
D. 2

Solution

The distance between the foci is 6, calculated using the formula 2c where c = √(a^2 - b^2).

Correct Answer: A — 6

Q. What is the distance between the foci of the ellipse x^2/25 + y^2/16 = 1?

A. 7
B. 8
C. 9
D. 10

Solution

The distance between the foci is given by 2c, where c = √(a^2 - b^2) = √(25 - 16) = 3, so the total distance is 2c = 6.

Correct Answer: A — 7

Q. What is the distance between the points (1, 2) and (4, 6)?

A. 5
B. 3
C. 4
D. 6

Solution

Distance = √[(4-1)² + (6-2)²] = √[9 + 16] = √25 = 5.

Correct Answer: A — 5

Q. What is the distance between the points (3, 4) and (7, 1)?

A. 5
B. 4
C. 3
D. 6

Solution

Distance = √[(7-3)² + (1-4)²] = √[16 + 9] = √25 = 5.

Correct Answer: A — 5

Q. What is the distance between the points P(1, 2, 3) and Q(4, 5, 6)?

A. 3√3
B. 3√2
C. 3
D. √3

Solution

Distance = √((4-1)² + (5-2)² + (6-3)²) = √(9 + 9 + 9) = 3√3.

Correct Answer: A — 3√3

Q. What is the distance from the point (1, 2) to the line 3x + 4y - 10 = 0?

A. 1
B. 2
C. 3
D. 4

Solution

Distance = |3(1) + 4(2) - 10| / √(3² + 4²) = |3 + 8 - 10| / 5 = 1.

Correct Answer: B — 2

Q. What is the distance from the point (3, 4) to the line 2x + 3y - 6 = 0?

A. 1
B. 2
C. 3
D. 4

Solution

Distance = |2(3) + 3(4) - 6| / √(2² + 3²) = |6 + 12 - 6| / √13 = 12/√13.

Correct Answer: A — 1

Q. What is the domain of the function f(x) = 1/(x - 2)?

A. x ≠ 2
B. x > 2
C. x < 2
D. All real numbers

Solution

The function is undefined at x = 2, so the domain is all real numbers except 2.

Correct Answer: A — x ≠ 2

Q. What is the domain of the function f(x) = 1/(x-3)?

A. x ≠ 3
B. x > 3
C. x < 3
D. All real numbers

Solution

The function is undefined at x = 3, so the domain is x ≠ 3.

Correct Answer: A — x ≠ 3

Q. What is the domain of the function f(x) = sqrt(x - 1)?

A. x >= 1
B. x > 1
C. x <= 1
D. x < 1

Solution

The expression under the square root must be non-negative, so x - 1 >= 0, hence x >= 1.

Correct Answer: A — x >= 1

Q. What is the Doppler effect?

A. Change in frequency due to motion
B. Change in amplitude due to distance
C. Change in speed due to temperature
D. Change in wavelength due to pressure

Solution

The Doppler effect refers to the change in frequency of a wave in relation to an observer moving relative to the wave source.

Correct Answer: A — Change in frequency due to motion

Q. What is the dot product of vectors (1, 2) and (3, 4)?

A. 11
B. 10
C. 12
D. 7

Solution

Dot product = 1*3 + 2*4 = 3 + 8 = 11

Correct Answer: A — 11

Q. What is the dot product of vectors A = (2, 3, 4) and B = (1, 0, -1)?

A. -2
B. 5
C. 10
D. 11

Solution

A . B = 2*1 + 3*0 + 4*(-1) = 2 + 0 - 4 = -2.

Correct Answer: B — 5

Q. What is the eccentricity of a hyperbola defined by the equation x^2/a^2 - y^2/b^2 = 1?

A. 1
B. √2
C. √(1 + b^2/a^2)
D. √(1 - b^2/a^2)

Solution

The eccentricity e of a hyperbola is given by e = √(1 + b^2/a^2).

Correct Answer: C — √(1 + b^2/a^2)

Q. What is the effect called when two sound waves of slightly different frequencies interfere?

A. Doppler effect
B. Beats
C. Resonance
D. Echo

Solution

The phenomenon of two sound waves of slightly different frequencies interfering is called beats.

Correct Answer: B — Beats

Q. What is the effect of -NO2 group on the stability of benzene derivatives?

A. Stabilizing
B. Destabilizing
C. No effect
D. Enhancing acidity

Solution

-NO2 is a strong electron-withdrawing group and destabilizes benzene derivatives.

Correct Answer: B — Destabilizing

Q. What is the effect of a -CF3 group on the stability of a benzene ring?

A. Stabilizing
B. Destabilizing
C. No effect
D. Depends on substituents

Solution

-CF3 is a strong electron-withdrawing group, which destabilizes the benzene ring.

Correct Answer: B — Destabilizing

Q. What is the effect of a -CH3 group on the stability of a carbocation?

A. Destabilizes
B. No effect
C. Stabilizes
D. Increases acidity

Solution

The -CH3 group is an electron-donating group and stabilizes the carbocation through hyperconjugation.

Correct Answer: C — Stabilizes

Q. What is the effect of a -COOH group on the stability of a benzene ring?

A. Stabilizing
B. Destabilizing
C. No effect
D. Depends on substituents

Solution

The -COOH group is a strong electron-withdrawing group, thus it destabilizes the benzene ring.

Correct Answer: B — Destabilizing

Q. What is the effect of a -I group on the acidity of a carboxylic acid?

A. Increases acidity
B. Decreases acidity
C. No effect
D. Only affects basicity

Solution

A -I group increases the acidity of a carboxylic acid by stabilizing the negative charge on the conjugate base.

Correct Answer: A — Increases acidity

Q. What is the effect of a -I group on the acidity of carboxylic acids?

A. Increases acidity
B. Decreases acidity
C. No effect
D. Depends on the solvent

Solution

A -I group increases the acidity of carboxylic acids by stabilizing the negative charge on the conjugate base.

Correct Answer: A — Increases acidity

Q. What is the effect of a -NO2 group on the stability of a benzene ring?

A. Stabilizing
B. Destabilizing
C. No effect
D. Enhances reactivity

Solution

The -NO2 group is a strong electron-withdrawing group, which destabilizes the benzene ring.

Correct Answer: B — Destabilizing

Q. What is the effect of a catalyst on the equilibrium constant of a reaction?

A. Increases the constant
B. Decreases the constant
C. No effect on the constant
D. Depends on the reaction

Solution

A catalyst does not affect the equilibrium constant; it only speeds up the rate at which equilibrium is reached.

Correct Answer: C — No effect on the constant

Q. What is the effect of a catalyst on the equilibrium position of a reversible reaction?

A. Shifts the equilibrium to the right
B. Shifts the equilibrium to the left
C. No effect on equilibrium position
D. Increases the equilibrium constant

Solution

A catalyst does not affect the position of equilibrium; it only speeds up the rate at which equilibrium is reached.

Correct Answer: C — No effect on equilibrium position

Q. What is the effect of a dielectric material on the electric field between the plates of a parallel plate capacitor?

A. Increases the electric field
B. Decreases the electric field
C. Has no effect
D. Reverses the electric field direction

Solution

Inserting a dielectric material between the plates of a capacitor decreases the electric field due to polarization.

Correct Answer: B — Decreases the electric field

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