JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the critical mass in nuclear fission?
A.
Mass required for a chain reaction
B.
Mass of a single nucleus
C.
Mass of the entire reactor
D.
Mass of fuel rods
Show solution
Solution
Critical mass is the minimum mass of fissile material needed to maintain a sustained nuclear chain reaction.
Correct Answer:
A
— Mass required for a chain reaction
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Q. What is the critical mass in nuclear physics?
A.
Mass required for a stable nucleus
B.
Mass required to sustain a nuclear chain reaction
C.
Mass of a neutron
D.
Mass of a proton
Show solution
Solution
Critical mass is the minimum mass of fissile material needed to maintain a nuclear chain reaction.
Correct Answer:
B
— Mass required to sustain a nuclear chain reaction
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Q. What is the critical point in a phase diagram?
A.
The point where solid and liquid coexist
B.
The point where liquid and gas coexist
C.
The point beyond which gas cannot be liquefied
D.
The point of maximum pressure
Show solution
Solution
The critical point is where the liquid and gas phases become indistinguishable.
Correct Answer:
C
— The point beyond which gas cannot be liquefied
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Q. What is the critical point of f(x) = x^3 - 3x^2 + 4?
Show solution
Solution
Setting f'(x) = 3x^2 - 6x = 0 gives x(x - 2) = 0, so critical points are x = 0 and x = 2.
Correct Answer:
B
— 2
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Q. What is the critical point of f(x) = x^3 - 6x^2 + 9x?
Show solution
Solution
Setting f'(x) = 0 gives critical points at x = 1, 2, and 3.
Correct Answer:
C
— 2
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Q. What is the critical temperature for a superconductor?
A.
The temperature at which it becomes a perfect conductor
B.
The temperature at which it loses all resistance
C.
The temperature at which it becomes a perfect insulator
D.
The temperature at which it becomes a normal conductor
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Solution
The critical temperature is the temperature below which a material exhibits superconductivity, losing all electrical resistance.
Correct Answer:
B
— The temperature at which it loses all resistance
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Q. What is the critical temperature of a gas?
A.
The temperature above which a gas cannot be liquefied
B.
The temperature at which a gas condenses
C.
The temperature at which a gas expands
D.
The temperature at which a gas is at its maximum density
Show solution
Solution
The critical temperature is the temperature above which a gas cannot be liquefied, regardless of the pressure applied.
Correct Answer:
A
— The temperature above which a gas cannot be liquefied
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Q. What is the critical temperature of a substance?
A.
The temperature at which a substance boils
B.
The temperature above which a gas cannot be liquefied
C.
The temperature at which a substance freezes
D.
The temperature at which a substance condenses
Show solution
Solution
The critical temperature is the temperature above which a gas cannot be liquefied.
Correct Answer:
B
— The temperature above which a gas cannot be liquefied
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Q. What is the cross product of the vectors (1, 0, 0) and (0, 1, 0)?
A.
(0, 0, 1)
B.
(1, 1, 0)
C.
(0, 0, 0)
D.
(1, 0, 0)
Show solution
Solution
Cross product = (1, 0, 0) × (0, 1, 0) = (0, 0, 1).
Correct Answer:
A
— (0, 0, 1)
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Q. What is the cross product of the vectors (1, 2, 3) and (4, 5, 6)?
A.
(-3, 6, -3)
B.
(-3, 6, 3)
C.
(3, -6, 3)
D.
(3, 6, -3)
Show solution
Solution
Cross product = |i j k| |1 2 3| |4 5 6| = (-3, 6, -3).
Correct Answer:
A
— (-3, 6, -3)
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Q. What is the cross product of u = (1, 2, 3) and v = (4, 5, 6)?
A.
(-3, 6, -3)
B.
(0, 0, 0)
C.
(3, -6, 3)
D.
(1, 2, 3)
Show solution
Solution
u × v = |i j k| |1 2 3| |4 5 6| = (-3, 6, -3)
Correct Answer:
A
— (-3, 6, -3)
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Q. What is the cross product of vectors (1, 2, 3) and (4, 5, 6)?
A.
(-3, 6, -3)
B.
(0, 0, 0)
C.
(3, -6, 3)
D.
(1, 2, 3)
Show solution
Solution
Cross product = |i j k| |1 2 3| |4 5 6| = (-3, 6, -3)
Correct Answer:
A
— (-3, 6, -3)
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Q. What is the cross product of vectors A = (1, 2, 3) and B = (4, 5, 6)?
A.
(-3, 6, -3)
B.
(0, 0, 0)
C.
(3, -6, 3)
D.
(1, -2, 1)
Show solution
Solution
Cross product A × B = |i j k| |1 2 3| |4 5 6| = (-3, 6, -3).
Correct Answer:
A
— (-3, 6, -3)
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Q. What is the current flowing through a 10 ohm resistor connected to a 20V battery?
A.
2 A
B.
1 A
C.
0.5 A
D.
0.2 A
Show solution
Solution
Using Ohm's law, I = V/R = 20V / 10 ohms = 2 A.
Correct Answer:
A
— 2 A
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Q. What is the current flowing through a 15Ω resistor connected to a 45V battery?
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Solution
Using Ohm's law, I = V/R = 45V / 15Ω = 3A.
Correct Answer:
C
— 3A
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Q. What is the current through a 10 ohm resistor connected across a 20V battery?
A.
0.5 A
B.
2 A
C.
1 A
D.
5 A
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Solution
Using Ohm's law, I = V/R, we have I = 20V / 10 ohms = 2 A.
Correct Answer:
B
— 2 A
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Q. What is the current through a 10 ohm resistor connected to a 20V battery?
A.
2 A
B.
0.5 A
C.
20 A
D.
10 A
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Solution
Using Ohm's law, I = V/R, we have I = 20V / 10 ohms = 2 A.
Correct Answer:
A
— 2 A
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Q. What is the current through a 10Ω resistor connected to a 50V power supply?
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Solution
Using Ohm's law, I = V/R = 50V/10Ω = 5A.
Correct Answer:
A
— 5A
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Q. What is the current through a 12Ω resistor connected to a 24V source?
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Solution
Using Ohm's law, I = V/R = 24V/12Ω = 2A.
Correct Answer:
B
— 2A
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Q. What is the current through a 12Ω resistor connected to a 36V battery?
Show solution
Solution
Using Ohm's Law, I = V / R = 36V / 12Ω = 3A.
Correct Answer:
C
— 3A
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Q. What is the damping ratio for critically damped oscillation?
A.
Less than 1
B.
Equal to 1
C.
Greater than 1
D.
Zero
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Solution
A critically damped system has a damping ratio equal to 1, which allows it to return to equilibrium without oscillating.
Correct Answer:
B
— Equal to 1
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Q. What is the de Broglie wavelength of an electron moving with a velocity of 1.5 x 10^6 m/s? (mass of electron = 9.11 x 10^-31 kg)
A.
4.86 x 10^-10 m
B.
2.42 x 10^-10 m
C.
1.33 x 10^-10 m
D.
6.63 x 10^-10 m
Show solution
Solution
The de Broglie wavelength λ = h/p = h/(mv). Using h = 6.63 x 10^-34 J.s, we find λ = 6.63 x 10^-34 / (9.11 x 10^-31 * 1.5 x 10^6) = 2.42 x 10^-10 m.
Correct Answer:
B
— 2.42 x 10^-10 m
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Q. What is the decibel level of a sound that is 10 times more intense than the reference level?
A.
10 dB
B.
20 dB
C.
30 dB
D.
40 dB
Show solution
Solution
Every increase of 10 dB represents a tenfold increase in intensity, so 10 times more intense is 20 dB.
Correct Answer:
B
— 20 dB
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Q. What is the definition of Young's modulus?
A.
The ratio of tensile stress to tensile strain
B.
The ratio of compressive stress to compressive strain
C.
The ratio of shear stress to shear strain
D.
The ratio of bulk stress to bulk strain
Show solution
Solution
Young's modulus is defined as the ratio of tensile stress to tensile strain, which measures the stiffness of a solid material.
Correct Answer:
A
— The ratio of tensile stress to tensile strain
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Q. What is the derivative of f(x) = 3x^2 + 5x - 7?
A.
3x + 5
B.
6x + 5
C.
6x - 5
D.
3x^2 + 5
Show solution
Solution
The derivative f'(x) = d/dx(3x^2 + 5x - 7) = 6x + 5.
Correct Answer:
B
— 6x + 5
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Q. What is the derivative of f(x) = 3x^3 - 5x + 2?
A.
9x^2 - 5
B.
3x^2 - 5
C.
9x^2 + 5
D.
3x^2 + 5
Show solution
Solution
f'(x) = 9x^2 - 5.
Correct Answer:
A
— 9x^2 - 5
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Q. What is the derivative of f(x) = 5x^4 - 3x + 2?
A.
20x^3 - 3
B.
20x^3 + 3
C.
15x^3 - 3
D.
5x^3 - 3
Show solution
Solution
The derivative f'(x) = d/dx(5x^4 - 3x + 2) = 20x^3 - 3.
Correct Answer:
A
— 20x^3 - 3
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Q. What is the derivative of f(x) = e^x?
A.
e^x
B.
x*e^x
C.
1
D.
0
Show solution
Solution
The derivative of e^x is e^x.
Correct Answer:
A
— e^x
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Q. What is the derivative of f(x) = ln(x^2 + 1) at x = 0?
A.
0
B.
1
C.
2
D.
undefined
Show solution
Solution
f'(x) = (2x)/(x^2 + 1), thus f'(0) = 0.
Correct Answer:
A
— 0
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Q. What is the derivative of f(x) = ln(x^2 + 1) at x = 1?
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Solution
f'(x) = (2x)/(x^2 + 1). At x = 1, f'(1) = (2*1)/(1^2 + 1) = 1.
Correct Answer:
B
— 1
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