Defence Exams MCQ & Objective Questions
Defence Exams play a crucial role in shaping the future of aspiring candidates in India. These exams not only assess knowledge but also test the ability to apply concepts in real-world scenarios. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and enhances their understanding of key topics.
What You Will Practise Here
Fundamentals of Defence Studies
Key Historical Events and Their Impact
Important Defence Policies and Strategies
Current Affairs Related to National Security
Basic Concepts of Military Operations
Understanding Defence Technologies
Analysing Defence Budget and Expenditure
Exam Relevance
The topics covered in Defence Exams are highly relevant across various educational boards, including CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect questions that focus on historical events, current affairs, and fundamental concepts related to defence. Common question patterns include multiple-choice questions that assess both theoretical knowledge and practical application.
Common Mistakes Students Make
Overlooking current affairs, which are often integrated into exam questions.
Confusing similar historical events or dates, leading to incorrect answers.
Neglecting the importance of definitions and key terms in objective questions.
Relying solely on rote memorization instead of understanding concepts.
FAQs
Question: What types of questions can I expect in Defence Exams?Answer: You can expect a mix of MCQs covering historical events, current affairs, and fundamental concepts related to defence.
Question: How can I improve my performance in Defence Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Start your journey towards success by solving practice MCQs today! Testing your understanding will not only boost your confidence but also prepare you for the important Defence Exams ahead.
Q. Calculate the median of the following set: 1, 2, 3, 4, 5, 6, 7, 8. (2020)
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Solution
Arranging the numbers: 1, 2, 3, 4, 5, 6, 7, 8. The median is the average of the 4th and 5th numbers: (4 + 5) / 2 = 4.5.
Correct Answer:
B
— 4.5
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Q. Calculate the median of the following set: 22, 19, 25, 30, 28, 24.
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Solution
Arrange the numbers: 19, 22, 24, 25, 28, 30. The median is the average of the 3rd and 4th values: (24 + 25) / 2 = 24.5.
Correct Answer:
A
— 24
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Q. Calculate the variance for the following data: 2, 4, 4, 4, 5, 5, 7, 9. (2019)
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Solution
Mean = 5. Variance = [(2-5)² + (4-5)² + (4-5)² + (4-5)² + (5-5)² + (5-5)² + (7-5)² + (9-5)²] / 8 = 4.
Correct Answer:
B
— 5
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Q. Calculate the variance for the following data: 3, 7, 7, 19. (2022)
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Solution
Mean = (3 + 7 + 7 + 19) / 4 = 9. Variance = [(3-9)² + (7-9)² + (7-9)² + (19-9)²] / 4 = 25.
Correct Answer:
B
— 25
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Q. Calculate the variance for the following data: 5, 7, 9, 11. (2022)
A.
2.5
B.
3.5
C.
4.0
D.
5.0
Show solution
Solution
Mean = (5 + 7 + 9 + 11) / 4 = 8. Variance = [(5-8)² + (7-8)² + (9-8)² + (11-8)²] / 4 = 3.5.
Correct Answer:
B
— 3.5
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Q. Calculate the variance of the following numbers: 1, 2, 3, 4, 5. (2022)
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Solution
Mean = (1 + 2 + 3 + 4 + 5) / 5 = 3. Variance = [(1-3)² + (2-3)² + (3-3)² + (4-3)² + (5-3)²] / 5 = 2.
Correct Answer:
B
— 1.5
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Q. Consider the data set: 4, 4, 4, 5, 6, 6, 7, 8. What is the mode?
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Solution
The mode is 4, as it appears 3 times, more than any other number.
Correct Answer:
A
— 4
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Q. Consider the data set: 5, 6, 7, 8, 8, 9, 9, 10. What is the mode?
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Solution
The mode is 8 and 9, but since we need to select one, we can choose 8 as it appears first.
Correct Answer:
C
— 8
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Q. Consider the following data set: 10, 20, 20, 30, 40, 30, 30. What is the mode?
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Solution
The mode is 30, as it appears three times, which is more than any other number.
Correct Answer:
C
— 30
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Q. Consider the following data set: 5, 6, 6, 7, 8, 8, 8, 9. What is the mode?
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Solution
The number 8 appears 3 times, which is more than any other number, making it the mode.
Correct Answer:
D
— 8
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Q. Consider the following numbers: 1, 2, 2, 3, 4, 4, 4, 5. What is the mode?
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Solution
The mode is 4, which appears most frequently (three times).
Correct Answer:
D
— 4
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Q. Determine the angle between the lines y = 2x + 1 and y = -1/2x + 3. (2021)
A.
90 degrees
B.
45 degrees
C.
60 degrees
D.
30 degrees
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Solution
The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan⁻¹(|(m1 - m2) / (1 + m1*m2)|) = tan⁻¹(5/3), which is approximately 90 degrees.
Correct Answer:
A
— 90 degrees
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Q. Determine the coefficient of x^5 in the expansion of (3x - 4)^7.
A.
252
B.
336
C.
672
D.
840
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Solution
The coefficient of x^5 in (3x - 4)^7 is C(7, 5) * (3)^5 * (-4)^2 = 21 * 243 * 16 = 68016.
Correct Answer:
A
— 252
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Q. Determine the continuity of the function f(x) = { x^2, x < 1; 2, x = 1; x + 1, x > 1 } at x = 1.
A.
Continuous
B.
Not continuous
C.
Depends on the limit
D.
Only left continuous
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Solution
The left limit as x approaches 1 is 1, the right limit is 2, and f(1) = 2. Since the left and right limits do not match, f(x) is not continuous at x = 1.
Correct Answer:
B
— Not continuous
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Q. Determine the continuity of the function f(x) = { x^2, x < 1; 2x - 1, x ≥ 1 } at x = 1.
A.
Continuous
B.
Discontinuous
C.
Only left continuous
D.
Only right continuous
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Solution
At x = 1, f(1) = 2(1) - 1 = 1 and lim x→1- f(x) = 1, lim x→1+ f(x) = 1. Thus, f(x) is continuous at x = 1.
Correct Answer:
A
— Continuous
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Q. Determine the continuity of the function f(x) = |x| at x = 0. (2020)
A.
Continuous
B.
Not continuous
C.
Depends on the limit
D.
Only left continuous
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Solution
The function f(x) = |x| is continuous at x = 0 since both the left-hand limit and right-hand limit equal f(0) = 0.
Correct Answer:
A
— Continuous
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Q. Determine the critical points of the function f(x) = x^2 - 4x + 4. (2022)
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Solution
f'(x) = 2x - 4; Setting f'(x) = 0 gives x = 2 as the critical point.
Correct Answer:
C
— 2
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Q. Determine the derivative of f(x) = x^3 - 4x + 7. (2023)
A.
3x^2 - 4
B.
3x^2 + 4
C.
x^2 - 4
D.
3x^2 - 7
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Solution
Using the power rule, f'(x) = 3x^2 - 4.
Correct Answer:
A
— 3x^2 - 4
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Q. Determine the derivative of f(x) = x^5 - 3x^3 + 2x. (2023)
A.
5x^4 - 9x^2 + 2
B.
5x^4 - 9x + 2
C.
5x^4 - 3x^2 + 2
D.
5x^4 - 3x^3
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Solution
Using the power rule, f'(x) = 5x^4 - 9x^2 + 2.
Correct Answer:
A
— 5x^4 - 9x^2 + 2
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Q. Determine the distance between the points (-1, -1) and (2, 2).
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Solution
Using the distance formula: d = √[(2 - (-1))² + (2 - (-1))²] = √[(2 + 1)² + (2 + 1)²] = √[9 + 9] = √18 = 3√2 ≈ 4.24.
Correct Answer:
C
— 5
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Q. Determine the distance between the points (0, 0) and (0, 8).
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Solution
Using the distance formula: d = √[(0 - 0)² + (8 - 0)²] = √[0 + 64] = √64 = 8.
Correct Answer:
A
— 8
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Q. Determine the distance between the points (1, 2) and (4, 6). (2022)
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Solution
Using the distance formula: d = √[(4 - 1)² + (6 - 2)²] = √[9 + 16] = √25 = 5.
Correct Answer:
A
— 5
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Q. Determine the distance between the points (2, 3) and (2, -1).
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Solution
Using the distance formula: d = √[(2 - 2)² + (-1 - 3)²] = √[0 + 16] = √16 = 4.
Correct Answer:
A
— 4
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Q. Determine the distance from the point (1, 2) to the line 2x + 3y - 6 = 0. (2023)
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Solution
Using the formula for distance from a point to a line, the distance is |2(1) + 3(2) - 6| / sqrt(2^2 + 3^2) = 1.
Correct Answer:
B
— 2
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Q. Determine the local maxima and minima of f(x) = x^2 - 4x + 3.
A.
Maxima at x=2
B.
Minima at x=2
C.
Maxima at x=1
D.
Minima at x=1
Show solution
Solution
f'(x) = 2x - 4. Setting f'(x) = 0 gives x = 2. f''(x) = 2 > 0 indicates a local minimum at x = 2.
Correct Answer:
B
— Minima at x=2
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Q. Determine the local maxima and minima of f(x) = x^4 - 8x^2 + 16. (2023)
A.
Maxima at x = 0
B.
Minima at x = 2
C.
Maxima at x = 2
D.
Minima at x = 0
Show solution
Solution
f'(x) = 4x^3 - 16x. Setting f'(x) = 0 gives x = 0, ±2. f''(x) = 12x^2 - 16. Minima at x = 0.
Correct Answer:
D
— Minima at x = 0
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Q. Determine the local maxima of f(x) = -x^2 + 4x. (2022)
A.
(2, 4)
B.
(0, 0)
C.
(4, 0)
D.
(1, 1)
Show solution
Solution
f'(x) = -2x + 4. Setting f'(x) = 0 gives x = 2. f(2) = -2^2 + 4(2) = 4.
Correct Answer:
A
— (2, 4)
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Q. Determine the local maxima or minima of f(x) = -x^2 + 4x. (2019)
A.
Maxima at x=2
B.
Minima at x=2
C.
Maxima at x=4
D.
Minima at x=4
Show solution
Solution
f'(x) = -2x + 4. Setting f'(x) = 0 gives x = 2. Since f''(x) = -2 < 0, it is a maxima.
Correct Answer:
A
— Maxima at x=2
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Q. Determine the maximum value of f(x) = -2x^2 + 4x + 1. (2023)
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Solution
The vertex is at x = -4/(2*(-2)) = 1. The maximum value is f(1) = -2(1)^2 + 4(1) + 1 = 3.
Correct Answer:
C
— 3
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Q. Determine the maximum value of f(x) = -x^2 + 4x. (2020)
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Solution
f'(x) = -2x + 4. Setting f'(x) = 0 gives x = 2. f(2) = -2^2 + 4(2) = 8.
Correct Answer:
A
— 4
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