Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. What is the common oxidation state of Chromium in chromates?
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Solution
Chromium commonly exhibits a +6 oxidation state in chromates (CrO4^2-).
Correct Answer:
D
— +6
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Q. What is the common oxidation state of chromium in Cr2O7^2-?
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Solution
In Cr2O7^2-, chromium has a common oxidation state of +6.
Correct Answer:
C
— +6
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Q. What is the common oxidation state of Chromium in its compounds?
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Solution
Chromium commonly exhibits a +6 oxidation state in compounds such as chromium trioxide (CrO3).
Correct Answer:
C
— +6
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Q. What is the common oxidation state of Group 17 elements?
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Solution
Group 17 elements, also known as halogens, commonly exhibit an oxidation state of -1.
Correct Answer:
A
— -1
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Q. What is the common oxidation state of nitrogen in ammonia (NH3)?
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Solution
In ammonia, nitrogen has an oxidation state of -3.
Correct Answer:
A
— -3
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Q. What is the common oxidation state of the p-block elements in group 13?
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Solution
The common oxidation state of group 13 elements, such as Aluminum, is +3.
Correct Answer:
C
— +3
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Q. What is the common oxidation state of transition metals in their compounds?
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Solution
Transition metals commonly exhibit a +2 oxidation state due to the loss of two 4s electrons.
Correct Answer:
B
— +2
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Q. What is the common ratio of the geometric series 4, 12, 36, ...?
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Solution
The common ratio r = 12/4 = 3.
Correct Answer:
A
— 3
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Q. What is the composition of functions f(g(x)) if f(x) = x + 1 and g(x) = 2x?
A.
2x + 1
B.
2x - 1
C.
x + 2
D.
x + 1
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Solution
f(g(x)) = f(2x) = 2x + 1.
Correct Answer:
A
— 2x + 1
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Q. What is the concentration in g/L of a solution containing 0.5 moles of KCl in 1.5 L of solution? (Molar mass of KCl = 74.5 g/mol)
A.
24.83 g/L
B.
49.67 g/L
C.
37.25 g/L
D.
50 g/L
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Solution
Mass of KCl = 0.5 moles × 74.5 g/mol = 37.25 g. Concentration = 37.25 g / 1.5 L = 24.83 g/L.
Correct Answer:
B
— 49.67 g/L
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Q. What is the concentration in molality of a solution made by dissolving 5 moles of solute in 3 kg of solvent?
A.
1.67 m
B.
2 m
C.
1.5 m
D.
2.5 m
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Solution
Molality (m) = moles of solute / kg of solvent = 5 moles / 3 kg = 1.67 m.
Correct Answer:
B
— 2 m
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Q. What is the concentration in molarity of a solution that contains 0.5 moles of solute in 1.5 liters of solution?
A.
0.33 M
B.
0.5 M
C.
0.75 M
D.
1 M
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Solution
Molarity (M) = moles of solute / liters of solution = 0.5 moles / 1.5 L = 0.33 M.
Correct Answer:
C
— 0.75 M
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Q. What is the concentration in ppm of a solution containing 1 gram of solute in 1 liter of solution?
A.
1000 ppm
B.
100 ppm
C.
10 ppm
D.
1 ppm
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Solution
PPM = (mass of solute in grams / volume of solution in liters) * 10^6 = (1 g / 1 L) * 10^6 = 1000 ppm.
Correct Answer:
A
— 1000 ppm
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Q. What is the concentration of a solution if 10 grams of NaCl is dissolved in 500 mL of water? (Molar mass of NaCl = 58.5 g/mol)
A.
0.34 M
B.
0.17 M
C.
0.50 M
D.
0.25 M
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Solution
Molarity (M) = moles of solute / liters of solution = (10 g / 58.5 g/mol) / 0.5 L = 0.34 M.
Correct Answer:
A
— 0.34 M
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Q. What is the concentration of H+ ions in a solution with a pH of 3?
A.
0.001 M
B.
0.01 M
C.
0.1 M
D.
1 M
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Solution
[H+] = 10^(-pH) = 10^(-3) = 0.001 M
Correct Answer:
A
— 0.001 M
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Q. What is the condition for a system to be critically damped?
A.
Damping coefficient equals zero
B.
Damping coefficient is less than the natural frequency
C.
Damping coefficient equals the square root of the product of mass and spring constant
D.
Damping coefficient is greater than the natural frequency
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Solution
A system is critically damped when the damping coefficient equals the square root of the product of mass and spring constant.
Correct Answer:
C
— Damping coefficient equals the square root of the product of mass and spring constant
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Q. What is the condition for a Wheatstone bridge to be balanced?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R2 = R3 * R4
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Solution
The condition for a Wheatstone bridge to be balanced is R1/R2 = R3/R4.
Correct Answer:
A
— R1/R2 = R3/R4
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Q. What is the condition for a Wheatstone bridge to be in a balanced state?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R4 = R2 * R3
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Solution
The condition for balance is R1/R2 = R3/R4.
Correct Answer:
A
— R1/R2 = R3/R4
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Q. What is the condition for a Wheatstone bridge to be in equilibrium?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R3 = R2 * R4
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Solution
In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.
Correct Answer:
A
— R1/R2 = R3/R4
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Q. What is the condition for an object to be in rotational equilibrium?
A.
Net force is zero
B.
Net torque is zero
C.
Both net force and net torque are zero
D.
None of the above
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Solution
For rotational equilibrium, the net torque acting on the object must be zero.
Correct Answer:
B
— Net torque is zero
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Q. What is the condition for constructive interference in a double-slit experiment?
A.
Path difference is an odd multiple of lambda/2
B.
Path difference is an even multiple of lambda
C.
Path difference is an odd multiple of lambda
D.
Path difference is zero
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Solution
Constructive interference occurs when the path difference between the two waves is an even multiple of the wavelength (nλ, where n is an integer).
Correct Answer:
B
— Path difference is an even multiple of lambda
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Q. What is the condition for constructive interference in a thin film?
A.
2t = (m + 1/2)λ
B.
2t = mλ
C.
t = mλ/2
D.
t = (m + 1/2)λ/2
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Solution
For constructive interference, the condition is 2t = mλ, where t is the thickness of the film and m is an integer.
Correct Answer:
B
— 2t = mλ
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Q. What is the condition for constructive interference in two waves?
A.
Path difference = (n + 1/2)λ
B.
Path difference = nλ
C.
Path difference = (n - 1/2)λ
D.
Path difference = 0
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Solution
Constructive interference occurs when the path difference is nλ, where n is an integer.
Correct Answer:
B
— Path difference = nλ
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Q. What is the condition for critical damping in a damped harmonic oscillator?
A.
Damping coefficient equals zero
B.
Damping coefficient equals mass times natural frequency
C.
Damping coefficient equals twice the mass times natural frequency
D.
Damping coefficient is less than mass times natural frequency
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Solution
Critical damping occurs when the damping coefficient equals twice the mass times the natural frequency of the system.
Correct Answer:
C
— Damping coefficient equals twice the mass times natural frequency
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Q. What is the condition for critical damping in a damped oscillator?
A.
Damping coefficient equals zero
B.
Damping coefficient equals mass times natural frequency
C.
Damping coefficient is less than mass times natural frequency
D.
Damping coefficient is greater than mass times natural frequency
Show solution
Solution
Critical damping occurs when the damping coefficient equals the mass times the natural frequency.
Correct Answer:
B
— Damping coefficient equals mass times natural frequency
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Q. What is the condition for light to be completely polarized by reflection?
A.
Angle of incidence equals angle of refraction
B.
Angle of incidence equals Brewster's angle
C.
Angle of incidence is 45 degrees
D.
Light must be monochromatic
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Solution
Light is completely polarized when it is reflected at Brewster's angle, which is given by θ_B = arctan(n2/n1).
Correct Answer:
B
— Angle of incidence equals Brewster's angle
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Q. What is the condition for light to be polarized by reflection?
A.
Angle of incidence equals angle of refraction
B.
Angle of incidence equals Brewster's angle
C.
Angle of incidence is 45 degrees
D.
Light must be monochromatic
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Solution
Light is polarized by reflection when the angle of incidence equals Brewster's angle.
Correct Answer:
B
— Angle of incidence equals Brewster's angle
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Q. What is the condition for rolling without slipping?
A.
v = Rω
B.
v = 2Rω
C.
v = 0
D.
v = R^2ω
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Solution
The condition for rolling without slipping is that the linear velocity v of the center of mass is equal to the product of the radius R and the angular velocity ω, i.e., v = Rω.
Correct Answer:
A
— v = Rω
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Q. What is the condition for the first minimum in single-slit diffraction?
A.
a = λ
B.
a = 2λ
C.
a = λ/2
D.
a = 3λ
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Solution
The first minimum occurs at a = λ, where 'a' is the slit width and 'λ' is the wavelength.
Correct Answer:
A
— a = λ
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Q. What is the condition for the lines 2x + 3y = 6 and 4x + 6y = 12 to be parallel?
A.
They have the same slope
B.
They intersect
C.
They are identical
D.
None of the above
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Solution
Both lines can be rewritten in slope-intercept form. The first line has slope -2/3 and the second line has the same slope, hence they are parallel.
Correct Answer:
A
— They have the same slope
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