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Q. If a 10 N force is applied at an angle of 60 degrees to the horizontal while moving an object 4 m, what is the work done? (2020)

A. 20 J
B. 40 J
C. 30 J
D. 50 J

Solution

Work done = Force × Distance × cos(θ) = 10 N × 4 m × cos(60°) = 10 N × 4 m × 0.5 = 20 J

Correct Answer: C — 30 J

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Q. If a 10 ohm resistor is connected to a 20V battery, what is the energy consumed in 5 seconds?

A. 20 J
B. 40 J
C. 10 J
D. 50 J

Solution

Power P = V^2 / R = 20^2 / 10 = 40 W. Energy = Power * time = 40 W * 5 s = 200 J.

Correct Answer: B — 40 J

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Q. If a 10 ohm resistor is connected to a 30V battery, what is the energy consumed in 5 seconds?

A. 15 J
B. 30 J
C. 75 J
D. 150 J

Solution

Power P = V^2 / R = (30V)^2 / 10 ohms = 90 W. Energy = Power * Time = 90 W * 5 s = 450 J.

Correct Answer: C — 75 J

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Q. If a 10 ohm resistor is connected to a 5V battery, what is the current flowing through the resistor? (2020)

A. 0.5 A
B. 1 A
C. 2 A
D. 5 A

Solution

Using Ohm's law, I = V/R = 5V / 10Ω = 0.5 A.

Correct Answer: B — 1 A

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Q. If a 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds, what is the average power output of the car's engine?

A. 2000 W
B. 4000 W
C. 6000 W
D. 8000 W

Solution

First, calculate the work done: W = 0.5 * m * v^2 = 0.5 * 1000 kg * (20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.

Correct Answer: C — 6000 W

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Q. If a 1000 kg car is moving at a speed of 15 m/s, what is its kinetic energy?

A. 112,500 J
B. 225,000 J
C. 150,000 J
D. 75,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J

Correct Answer: B — 225,000 J

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Q. If a 1000 kg car is moving at a speed of 36 km/h, what is its kinetic energy? (2021)

A. 500 J
B. 1000 J
C. 2000 J
D. 3000 J

Solution

Convert speed to m/s: 36 km/h = 10 m/s. KE = 1/2 * m * v^2 = 1/2 * 1000 kg * (10 m/s)^2 = 50000 J.

Correct Answer: C — 2000 J

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Q. If a 1000 kg car is moving with a speed of 15 m/s, what is its kinetic energy?

A. 112,500 J
B. 225,000 J
C. 75,000 J
D. 150,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (15 m/s)² = 112,500 J

Correct Answer: B — 225,000 J

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Q. If a 1000 W heater is used for 3 hours, how much energy does it consume in kilowatt-hours?

A. 3 kWh
B. 2 kWh
C. 1 kWh
D. 0.5 kWh

Solution

Energy consumed in kilowatt-hours is calculated as E = P (kW) * t (h). Here, P = 1000 W = 1 kW and t = 3 hours. Thus, E = 1 kW * 3 h = 3 kWh.

Correct Answer: A — 3 kWh

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Q. If a 1000 W heater runs for 2 hours, how much energy does it consume?

A. 7200 J
B. 14400 J
C. 20000 J
D. 3600000 J

Solution

Energy = Power × Time = 1000 W × (2 × 3600 s) = 7200000 J.

Correct Answer: D — 3600000 J

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Q. If a 1000 W motor runs for 2 hours, how much work does it do? (2000)

A. 7200 J
B. 2000 J
C. 3600000 J
D. 100000 J

Solution

Work = Power × Time = 1000 W × (2 hours × 3600 s/hour) = 1000 W × 7200 s = 7200000 J

Correct Answer: C — 3600000 J

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Q. If a 100Ω resistor is connected in series with a 200Ω resistor, what is the total resistance? (2023)

A. 300Ω
B. 100Ω
C. 200Ω
D. 400Ω

Solution

In series, R_total = R1 + R2 = 100Ω + 200Ω = 300Ω.

Correct Answer: A — 300Ω

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Q. If a 10Ω resistor carries a current of 2A, what is the voltage across the resistor? (2023)

A. 5V
B. 10V
C. 20V
D. 30V

Solution

Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.

Correct Answer: C — 20V

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Q. If a 10Ω resistor carries a current of 5A, what is the voltage across the resistor? (2023)

A. 10V
B. 20V
C. 30V
D. 50V

Solution

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Correct Answer: B — 20V

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Q. If a 10Ω resistor is connected across a 20V battery, what is the power dissipated in the resistor? (2023)

A. 20W
B. 40W
C. 10W
D. 5W

Solution

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40W.

Correct Answer: B — 40W

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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the equivalent resistance? (2022)

A. 3.33Ω
B. 5Ω
C. 7.5Ω
D. 15Ω

Solution

For parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.

Correct Answer: A — 3.33Ω

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Q. If a 10Ω resistor is connected in parallel with a 5Ω resistor, what is the total resistance? (2022)

A. 3.33Ω
B. 5Ω
C. 7.5Ω
D. 15Ω

Solution

For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/10 + 1/5 = 1/10 + 2/10 = 3/10. Therefore, R_eq = 10/3 = 3.33Ω.

Correct Answer: A — 3.33Ω

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Q. If a 10Ω resistor is connected to a 20V battery, what is the power consumed by the resistor? (2023)

A. 20W
B. 40W
C. 10W
D. 5W

Solution

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20V^2 / 10Ω = 40W.

Correct Answer: B — 40W

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Q. If a 10Ω resistor is connected to a 20V battery, what is the power dissipated by the resistor?

A. 20W
B. 40W
C. 100W
D. 200W

Solution

Power (P) can be calculated using P = V^2/R. Here, P = 20V^2 / 10Ω = 400 / 10 = 40W.

Correct Answer: B — 40W

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Q. If a 10Ω resistor is connected to a 20V source, what is the energy consumed in 5 seconds?

A. 20J
B. 40J
C. 50J
D. 100J

Solution

Power P = V^2 / R = 20V^2 / 10Ω = 40W. Energy = Power * time = 40W * 5s = 200J.

Correct Answer: B — 40J

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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is increasing

Solution

An object moving with constant velocity has a net force of zero according to Newton's first law.

Correct Answer: A — It is zero

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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. If a 12 V battery is connected to a circuit with a resistance of 4 ohms, what is the current flowing through the circuit?

A. 2 A
B. 3 A
C. 4 A
D. 5 A

Solution

Using Ohm's Law, I = V/R = 12 V / 4 ohm = 3 A.

Correct Answer: A — 2 A

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Q. If a 12 V battery is connected to a resistor of 4 ohms, what is the current flowing through the circuit?

A. 3 A
B. 4 A
C. 12 A
D. 0.33 A

Solution

Using Ohm's Law (I = V/R), I = 12 V / 4 Ω = 3 A.

Correct Answer: A — 3 A

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Q. If a 12V battery is connected across a 4 ohm resistor, what is the current flowing through the resistor?

A. 2 A
B. 3 A
C. 4 A
D. 6 A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3 A.

Correct Answer: A — 2 A

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Q. If a 12V battery is connected across a 4 ohm resistor, what is the power dissipated in the resistor?

A. 12 W
B. 24 W
C. 36 W
D. 48 W

Solution

Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 144 / 4 = 36 W.

Correct Answer: B — 24 W

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Q. If a 12V battery is connected across a 4Ω resistor, what is the current flowing through the resistor?

A. 3A
B. 2A
C. 4A
D. 1A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: B — 2A

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Q. If a 12V battery is connected to a 4 ohm resistor, what is the power dissipated by the resistor?

A. 12 W
B. 24 W
C. 36 W
D. 48 W

Solution

Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 36 W.

Correct Answer: B — 24 W

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Q. If a 1500 kg car is moving at a speed of 30 m/s, what is its kinetic energy?

A. 675,000 J
B. 450,000 J
C. 225,000 J
D. 900,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (30 m/s)² = 675,000 J

Correct Answer: B — 450,000 J

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Q. If a 15Ω resistor is connected in parallel with a 30Ω resistor, what is the equivalent resistance? (2021)

A. 10Ω
B. 7.5Ω
C. 5Ω
D. 12Ω

Solution

For resistors in parallel, 1/R_eq = 1/R1 + 1/R2 = 1/15 + 1/30 = 2/30 + 1/30 = 3/30. Therefore, R_eq = 30/3 = 10Ω.

Correct Answer: B — 7.5Ω

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Major Competitive Exams

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