JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. What is the arithmetic mean of the first five prime numbers?
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Solution
Mean = (2 + 3 + 5 + 7 + 11) / 5 = 28 / 5 = 5.6.
Correct Answer:
B
— 6
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Q. What is the atomic number of the element with the symbol 'Na'?
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Solution
Sodium (Na) has an atomic number of 11.
Correct Answer:
A
— 11
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Q. What is the average kinetic energy of a gas molecule at temperature T?
A.
(3/2)kT
B.
(1/2)kT
C.
(3/2)RT
D.
(1/2)RT
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Solution
The average kinetic energy of a gas molecule is given by the formula KE_avg = (3/2)kT, where k is the Boltzmann constant.
Correct Answer:
A
— (3/2)kT
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Q. What is the average kinetic energy of one mole of an ideal gas at temperature T?
A.
(3/2)RT
B.
(5/2)RT
C.
(1/2)RT
D.
(2/3)RT
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Solution
The average kinetic energy of one mole of an ideal gas is given by the formula KE = (3/2)RT, where R is the gas constant and T is the temperature in Kelvin.
Correct Answer:
A
— (3/2)RT
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Q. What is the average power consumed in an AC circuit with a power factor of 0.8 and an RMS voltage of 100 V with a current of 5 A?
A.
200 W
B.
400 W
C.
300 W
D.
500 W
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Solution
Average power (P) is given by P = V_rms * I_rms * PF. Therefore, P = 100 V * 5 A * 0.8 = 400 W.
Correct Answer:
C
— 300 W
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Q. What is the average power consumed in an AC circuit with a power factor of 0.8 and a maximum power of 100 W?
A.
80 W
B.
100 W
C.
120 W
D.
160 W
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Solution
Average power (P_avg) is given by P_avg = P_max × power factor. Therefore, P_avg = 100 W × 0.8 = 80 W.
Correct Answer:
A
— 80 W
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Q. What is the axis of symmetry for the parabola defined by the equation y^2 = -12x?
A.
x = 0
B.
y = 0
C.
y = -6
D.
x = -6
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Solution
The axis of symmetry for a parabola in the form y^2 = 4px is the x-axis, which is x = 0.
Correct Answer:
A
— x = 0
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Q. What is the axis of symmetry for the parabola given by the equation y = -2x^2 + 4x + 1?
A.
x = 1
B.
y = 1
C.
x = 2
D.
y = 2
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Solution
The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = -2, b = 4, so x = -4/(2*-2) = 1.
Correct Answer:
A
— x = 1
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Q. What is the axis of symmetry for the parabola given by the equation y = 3x^2 + 6x + 2?
A.
x = -1
B.
y = -1
C.
x = 1
D.
y = 1
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Solution
The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = 3 and b = 6, so x = -6/(2*3) = -1.
Correct Answer:
A
— x = -1
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Q. What is the band gap energy of a typical semiconductor?
A.
0 eV
B.
1-3 eV
C.
5 eV
D.
10 eV
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Solution
Typical semiconductors have a band gap energy in the range of 1-3 eV.
Correct Answer:
B
— 1-3 eV
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Q. What is the band gap energy of a typical silicon semiconductor?
A.
0.1 eV
B.
1.1 eV
C.
2.0 eV
D.
3.5 eV
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Solution
Silicon has a band gap energy of approximately 1.1 eV, which is suitable for many electronic applications.
Correct Answer:
B
— 1.1 eV
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Q. What is the band gap energy of silicon at room temperature?
A.
0.1 eV
B.
1.1 eV
C.
2.0 eV
D.
3.5 eV
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Solution
The band gap energy of silicon at room temperature is approximately 1.1 eV.
Correct Answer:
B
— 1.1 eV
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Q. What is the bandwidth of a signal that has a frequency range from 300 Hz to 3 kHz?
A.
2.7 kHz
B.
3.3 kHz
C.
2.4 kHz
D.
3.0 kHz
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Solution
Bandwidth = f_max - f_min = 3000 Hz - 300 Hz = 2700 Hz or 2.7 kHz.
Correct Answer:
A
— 2.7 kHz
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Q. What is the bandwidth of a signal that occupies a frequency range from 1 kHz to 3 kHz?
A.
1 kHz
B.
2 kHz
C.
3 kHz
D.
4 kHz
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Solution
Bandwidth = f_max - f_min = 3 kHz - 1 kHz = 2 kHz.
Correct Answer:
B
— 2 kHz
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Q. What is the bandwidth of a signal that occupies a frequency range from 300 Hz to 3 kHz?
A.
2.7 kHz
B.
3.3 kHz
C.
2.4 kHz
D.
3.0 kHz
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Solution
Bandwidth = f_max - f_min = 3000 Hz - 300 Hz = 2700 Hz = 2.7 kHz.
Correct Answer:
A
— 2.7 kHz
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Q. What is the basic building block of proteins?
A.
Nucleotides
B.
Fatty acids
C.
Amino acids
D.
Monosaccharides
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Solution
Proteins are made up of amino acids, which are their basic building blocks.
Correct Answer:
C
— Amino acids
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Q. What is the basic structural unit of proteins?
A.
Nucleotide
B.
Monosaccharide
C.
Amino acid
D.
Fatty acid
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Solution
Proteins are made up of long chains of amino acids.
Correct Answer:
C
— Amino acid
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Q. What is the basic unit of nucleic acids?
A.
Amino acid
B.
Nucleotide
C.
Monosaccharide
D.
Fatty acid
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Solution
The basic unit of nucleic acids, such as DNA and RNA, is the nucleotide.
Correct Answer:
B
— Nucleotide
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Q. What is the basic unit of proteins?
A.
Nucleotide
B.
Monosaccharide
C.
Amino acid
D.
Fatty acid
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Solution
Proteins are made up of amino acids, which are their basic building blocks.
Correct Answer:
C
— Amino acid
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Q. What is the binding energy of a nucleus?
A.
Energy required to remove a nucleon
B.
Energy released during nuclear fusion
C.
Energy required to split the nucleus
D.
Energy required to form the nucleus from its constituents
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Solution
The binding energy of a nucleus is the energy required to form the nucleus from its constituent protons and neutrons.
Correct Answer:
D
— Energy required to form the nucleus from its constituents
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Q. What is the binding energy per nucleon for a stable nucleus?
A.
Less than 1 MeV
B.
About 8 MeV
C.
More than 10 MeV
D.
Zero
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Solution
Stable nuclei typically have a binding energy per nucleon around 8 MeV.
Correct Answer:
B
— About 8 MeV
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Q. What is the boiling point elevation of a solution containing 1 mol of NaCl in 1 kg of water? (K_b for water = 0.512 °C kg/mol)
A.
0.512 °C
B.
1.024 °C
C.
1.536 °C
D.
2.048 °C
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Solution
Boiling point elevation = i * K_b * m = 2 * 0.512 * 1 = 1.024 °C (i = 2 for NaCl)
Correct Answer:
B
— 1.024 °C
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Q. What is the boiling point of a liquid?
A.
The temperature at which vapor pressure equals atmospheric pressure
B.
The temperature at which a liquid freezes
C.
The temperature at which a liquid evaporates
D.
The temperature at which a liquid condenses
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Solution
The boiling point is defined as the temperature at which the vapor pressure of a liquid equals the atmospheric pressure.
Correct Answer:
A
— The temperature at which vapor pressure equals atmospheric pressure
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Q. What is the boiling point of a solution containing 0.5 mol of KCl in 1 kg of water? (K_b for water = 0.512 °C kg/mol)
A.
1.024 °C
B.
0.512 °C
C.
1.536 °C
D.
2.048 °C
Show solution
Solution
Boiling point elevation = i * K_b * m = 2 * 0.512 * 0.5 = 0.512 °C; Boiling point = 100 + 0.512 = 100.512 °C
Correct Answer:
C
— 1.536 °C
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Q. What is the boiling point trend among alcohols, ethers, and alkanes?
A.
Alcohols > Ethers > Alkanes
B.
Ethers > Alcohols > Alkanes
C.
Alkanes > Ethers > Alcohols
D.
All have the same boiling point
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Solution
Alcohols have higher boiling points than ethers and alkanes due to hydrogen bonding.
Correct Answer:
A
— Alcohols > Ethers > Alkanes
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Q. What is the bond angle around the carbon atoms in an alkyne?
A.
120 degrees
B.
180 degrees
C.
109.5 degrees
D.
90 degrees
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Solution
The bond angle around the carbon atoms in an alkyne is approximately 180 degrees due to linear geometry.
Correct Answer:
B
— 180 degrees
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Q. What is the bond angle in a methane (CH4) molecule?
A.
90 degrees
B.
109.5 degrees
C.
120 degrees
D.
180 degrees
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Solution
In methane, the bond angle is approximately 109.5 degrees due to its tetrahedral geometry.
Correct Answer:
B
— 109.5 degrees
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Q. What is the bond angle in a tetrahedral molecule?
A.
90 degrees
B.
120 degrees
C.
109.5 degrees
D.
180 degrees
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Solution
In a tetrahedral geometry, the bond angles are approximately 109.5 degrees.
Correct Answer:
C
— 109.5 degrees
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Q. What is the bond angle in a trigonal planar molecule?
A.
120 degrees
B.
109.5 degrees
C.
180 degrees
D.
90 degrees
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Solution
In a trigonal planar geometry, the bond angles are 120 degrees.
Correct Answer:
A
— 120 degrees
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Q. What is the bond angle in a water molecule (H2O) according to VSEPR theory?
A.
120 degrees
B.
109.5 degrees
C.
104.5 degrees
D.
90 degrees
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Solution
The bond angle in H2O is approximately 104.5 degrees due to the two lone pairs on oxygen.
Correct Answer:
C
— 104.5 degrees
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