Mathematics (School)

My Learning Cart

Mathematics (School)

Download Q&A

Mathematics (School) MCQ & Objective Questions

Mathematics is a crucial subject in school education, forming the foundation for various competitive exams. Mastering Mathematics (School) not only enhances problem-solving skills but also boosts confidence during exams. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and understand concepts clearly.

What You Will Practise Here

Number Systems and their properties
Algebraic Expressions and Equations
Geometry: Angles, Triangles, and Circles
Statistics and Probability concepts
Mensuration: Area, Volume, and Surface Area
Trigonometry basics and applications
Functions and Graphs

Exam Relevance

Mathematics (School) is a significant part of the curriculum for CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect a variety of question patterns, including direct application of formulas, conceptual understanding, and problem-solving scenarios. Familiarity with MCQs in this subject can greatly enhance performance in both board and competitive examinations.

Common Mistakes Students Make

Misinterpreting the question, leading to incorrect answers.
Overlooking the importance of units in measurement-related problems.
Confusing similar formulas, especially in Geometry and Algebra.
Neglecting to check calculations, resulting in simple arithmetic errors.
Failing to understand the underlying concepts, which affects problem-solving ability.

FAQs

Question: How can I improve my speed in solving Mathematics (School) MCQs?
Answer: Regular practice with timed quizzes and mock tests can significantly enhance your speed and accuracy.

Question: Are there any specific topics I should focus on for competitive exams?
Answer: Focus on Algebra, Geometry, and Statistics, as these areas frequently appear in competitive exams.

Start your journey towards mastering Mathematics (School) today! Solve practice MCQs to test your understanding and prepare effectively for your exams. Remember, consistent practice leads to success!

Algebra (Secondary) Arithmetic (Primary) Geometry Statistics & Probability Trigonometry

Q. If the diameter of a circle is 12 cm, what is the area of the circle?

A. 36π cm²
B. 144π cm²
C. 72π cm²
D. 24π cm²

Solution

The radius r is half of the diameter, so r = 12/2 = 6 cm. The area A = πr² = π(6)² = 36π cm².

Correct Answer: C — 72π cm²

Q. If the diameter of a circle is 14 cm, what is the area of the circle?

A. 154 cm²
B. 196 cm²
C. 100 cm²
D. 120 cm²

Solution

The radius r = diameter/2 = 14/2 = 7 cm. The area A = πr² = π(7)² = 49π ≈ 154 cm².

Correct Answer: B — 196 cm²

Q. If the diameter of a circle is 14 cm, what is the circumference of the circle?

A. 22 cm
B. 28 cm
C. 44 cm
D. 14 cm

Solution

The circumference C of a circle is given by C = πd. Here, d = 14 cm, so C = π * 14 ≈ 43.98 cm, which rounds to 44 cm.

Correct Answer: B — 28 cm

Q. If the diameter of a circle is 14 cm, what is the circumference?

A. 44 cm
B. 28 cm
C. 22 cm
D. 14 cm

Solution

The circumference C of a circle is given by C = πd. Thus, C = π(14) ≈ 44 cm.

Correct Answer: A — 44 cm

Q. If the diameter of a circle is 14 cm, what is the circumference? (Use π = 22/7)

A. 44 cm
B. 28 cm
C. 22 cm
D. 14 cm

Solution

Circumference = πd = (22/7) * 14 = 44 cm.

Correct Answer: A — 44 cm

Q. If the diameter of a circle is 14 cm, what is the radius?

A. 7 cm
B. 14 cm
C. 21 cm
D. 28 cm

Solution

The radius is half of the diameter. Therefore, the radius is 14/2 = 7 cm.

Correct Answer: A — 7 cm

Q. If the diameter of a circle is 20 cm, what is the radius?

A. 5 cm
B. 10 cm
C. 15 cm
D. 20 cm

Solution

Radius = diameter/2 = 20/2 = 10 cm.

Correct Answer: B — 10 cm

Q. If the first term of a geometric progression is 3 and the common ratio is 2, what is the 4th term?

A. 24
B. 12
C. 48
D. 36

Solution

The nth term of a geometric progression is given by a_n = a * r^(n-1). Here, a = 3, r = 2, and n = 4. So, a_4 = 3 * 2^(4-1) = 3 * 2^3 = 3 * 8 = 24.

Correct Answer: A — 24

Q. If the first term of a geometric progression is 5 and the common ratio is 3, what is the 3rd term?

A. 15
B. 45
C. 135
D. 9

Solution

The nth term of a geometric progression is given by a_n = a * r^(n-1). Here, a = 5, r = 3, and n = 3. So, a_3 = 5 * 3^(3-1) = 5 * 3^2 = 5 * 9 = 45.

Correct Answer: C — 135

Q. If the first term of a geometric sequence is 3 and the common ratio is 2, what is the 4th term?

A. 24
B. 12
C. 6
D. 3

Solution

The nth term of a geometric sequence is a * r^(n-1). Here, a = 3, r = 2, n = 4. So, 3 * 2^(4-1) = 3 * 8 = 24.

Correct Answer: A — 24

Q. If the first term of an arithmetic progression is 4 and the common difference is 5, what is the 10th term?

A. 49
B. 54
C. 50
D. 45

Solution

The nth term of an AP is given by a_n = a + (n-1)d. Here, a = 4, d = 5, and n = 10. So, a_10 = 4 + (10-1)5 = 4 + 45 = 49.

Correct Answer: B — 54

Q. If the lengths of the sides of a triangle are 3 cm, 4 cm, and 5 cm, what is its perimeter?

A. 12 cm
B. 15 cm
C. 10 cm
D. 8 cm

Solution

Perimeter = 3 + 4 + 5 = 12 cm.

Correct Answer: A — 12 cm

Q. If the lengths of the sides of a triangle are 5 cm, 12 cm, and 13 cm, what type of triangle is it?

A. Acute
B. Obtuse
C. Right
D. Equilateral

Solution

Since 5² + 12² = 13², it is a right triangle.

Correct Answer: C — Right

Q. If the lengths of the sides of a triangle are 7 cm, 24 cm, and 25 cm, what is its area?

A. 84 cm²
B. 168 cm²
C. 42 cm²
D. 56 cm²

Solution

Using Heron's formula, s = (7 + 24 + 25)/2 = 28. Area = √(s(s-a)(s-b)(s-c)) = √(28(28-7)(28-24)(28-25)) = √(28*21*4*3) = 84 cm².

Correct Answer: A — 84 cm²

Q. If the lengths of the sides of a triangle are 7 cm, 24 cm, and 25 cm, what is the perimeter?

A. 56 cm
B. 50 cm
C. 45 cm
D. 30 cm

Solution

Perimeter = 7 + 24 + 25 = 56 cm.

Correct Answer: B — 50 cm

Q. If the lengths of the sides of a triangle are 7 cm, 24 cm, and 25 cm, what is the perimeter of the triangle?

A. 56 cm
B. 50 cm
C. 45 cm
D. 30 cm

Solution

Perimeter = 7 + 24 + 25 = 56 cm.

Correct Answer: B — 50 cm

Q. If the lengths of the sides of a triangle are in the ratio 3:4:5 and the perimeter is 60 cm, what is the length of the longest side?

A. 20 cm
B. 15 cm
C. 25 cm
D. 30 cm

Solution

Let the sides be 3x, 4x, 5x. Then, 3x + 4x + 5x = 60. Therefore, 12x = 60, x = 5. Longest side = 5x = 25 cm.

Correct Answer: A — 20 cm

Q. If the lengths of the sides of triangle ABC are 3 cm, 4 cm, and 5 cm, what type of triangle is it?

A. Equilateral
B. Isosceles
C. Scalene
D. Right

Solution

Triangle ABC is a right triangle because it satisfies the Pythagorean theorem: 3² + 4² = 5².

Correct Answer: D — Right

Q. If the lengths of the sides of triangle ABC are 7 cm, 24 cm, and 25 cm, is it a right triangle?

A. Yes
B. No
C. Only if angle A is 90 degrees
D. Only if angle B is 90 degrees

Solution

Yes, because 7² + 24² = 49 + 576 = 625 = 25², satisfying the Pythagorean theorem.

Correct Answer: A — Yes

Q. If the lengths of the sides of triangle ABC are in the ratio 3:4:5, what type of triangle is it?

A. Acute
B. Obtuse
C. Right
D. Equilateral

Solution

A triangle with sides in the ratio 3:4:5 is a right triangle, as it satisfies the Pythagorean theorem.

Correct Answer: C — Right

Q. If the lengths of the sides of triangle PQR are 7 cm, 24 cm, and 25 cm, what is the perimeter of triangle PQR?

A. 50 cm
B. 56 cm
C. 25 cm
D. 24 cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides. Therefore, perimeter = 7 + 24 + 25 = 56 cm.

Correct Answer: A — 50 cm

Q. If the lengths of the sides of triangle PQR are in the ratio 3:4:5, what type of triangle is it?

A. Acute
B. Obtuse
C. Right
D. Equilateral

Solution

A triangle with sides in the ratio 3:4:5 is a right triangle, as it satisfies the Pythagorean theorem.

Correct Answer: C — Right

Q. If the lengths of the sides of triangle XYZ are 8 cm, 15 cm, and 17 cm, is it a right triangle?

A. Yes
B. No
C. It cannot be determined
D. Only if angle X is 90 degrees

Solution

Yes, because 8^2 + 15^2 = 64 + 225 = 289 = 17^2, satisfying the Pythagorean theorem.

Correct Answer: A — Yes

Q. If the lengths of two sides of a triangle are 5 cm and 12 cm, and the included angle is 90 degrees, what is the area?

A. 30 cm²
B. 60 cm²
C. 24 cm²
D. 20 cm²

Solution

Area = 1/2 * side1 * side2 = 1/2 * 5 * 12 = 30 cm².

Correct Answer: A — 30 cm²

Q. If the lengths of two sides of a triangle are 5 cm and 12 cm, what is the maximum possible length of the third side?

A. 16 cm
B. 17 cm
C. 18 cm
D. 19 cm

Solution

According to the triangle inequality theorem, the length of the third side must be less than the sum of the other two sides. Therefore, the maximum length is 5 + 12 = 17 cm.

Correct Answer: B — 17 cm

Q. If the lengths of two sides of a triangle are 5 cm and 12 cm, what is the range of possible lengths for the third side?

A. 1 cm to 17 cm
B. 6 cm to 16 cm
C. 7 cm to 12 cm
D. 5 cm to 12 cm

Solution

The length of the third side must be greater than the difference of the other two sides and less than their sum: |5 - 12| < third side < 5 + 12, which gives 7 cm < third side < 17 cm.

Correct Answer: B — 6 cm to 16 cm

Q. If the lengths of two sides of a triangle are 5 cm and 7 cm, what is the range of possible lengths for the third side?

A. 2 cm to 12 cm
B. 3 cm to 11 cm
C. 4 cm to 10 cm
D. 5 cm to 9 cm

Solution

The length of the third side must be greater than the difference of the other two sides and less than their sum: |5 - 7| < third side < 5 + 7, which gives 2 < third side < 12.

Correct Answer: B — 3 cm to 11 cm

Q. If the lengths of two sides of a triangle are 6 cm and 8 cm, what is the range of possible lengths for the third side?

A. 2 cm to 14 cm
B. 2 cm to 10 cm
C. 2 cm to 12 cm
D. 2 cm to 8 cm

Solution

The length of the third side must be greater than the difference of the other two sides and less than their sum: |6 - 8| < third side < 6 + 8, which gives 2 cm < third side < 14 cm.

Correct Answer: B — 2 cm to 10 cm

Q. If the lengths of two sides of a triangle are 8 cm and 15 cm, and the included angle is 60 degrees, what is the area?

A. 60 cm²
B. 80 cm²
C. 90 cm²
D. 100 cm²

Solution

Area = 1/2 * a * b * sin(C) = 1/2 * 8 * 15 * sin(60) = 60 cm².

Correct Answer: A — 60 cm²

Q. If the lengths of two sides of a triangle are 8 cm and 6 cm, what is the range of possible lengths for the third side?

A. 2 cm to 14 cm
B. 2 cm to 10 cm
C. 4 cm to 14 cm
D. 4 cm to 10 cm

Solution

The length of the third side must be greater than the difference of the other two sides and less than their sum: |8 - 6| < third side < 8 + 6, which gives 2 < third side < 14.

Correct Answer: B — 2 cm to 10 cm

Showing 571 to 600 of 2594 (87 Pages)

School

College

Degree

Competitve

Skills

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely