Organic Chemistry deals with the structure, properties, reactions, and synthesis of carbon-containing compounds , forming a core part of school-level chemistry, undergraduate curricula, and competitive examinations . This category is designed for Class 11–12 students, undergraduate learners, and competitive exam aspirants , with strong emphasis on conceptual clarity, reaction mechanisms, and application-based learning .
In this section, you will study:
Basic principles of organic chemistry – hybridization, bonding, and structure
Classification and nomenclature of organic compounds
Isomerism – structural and stereoisomerism
Reaction mechanisms – substitution, addition, elimination, and rearrangement
Hydrocarbons – alkanes, alkenes, alkynes, and aromatic compounds
Functional groups and their chemistry – alcohols, aldehydes, ketones, acids, amines, etc.
Named reactions and reagents essential for exams
Biomolecules and polymers (introductory to UG level)
Spectroscopic methods for structure determination (introductory)
NCERT- and UG-aligned explanations , supported by reaction schemes, mechanisms, examples, MCQs, and PYQs
The content is structured to build step-by-step understanding , enhance mechanistic thinking , and help students predict reaction outcomes and solve complex problems .
Master Organic Chemistry to develop strong analytical and reasoning skills , essential for school exams, undergraduate studies, and competitive examinations .
Q. Which of the following is the correct stereochemical descriptor for 2-butene with the double bond in the trans configuration?
A.
cis-2-butene
B.
trans-2-butene
C.
1-butene
D.
butyne
Show solution
Solution
The correct descriptor for 2-butene with the double bond in the trans configuration is trans-2-butene.
Correct Answer:
B
— trans-2-butene
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Q. Which of the following is the correct structure for 1-heptyne?
A.
CH3-CH2-CH2-CH2-CH2-C≡C-H
B.
CH3-CH2-CH2-C≡C-CH3
C.
CH3-C≡C-CH2-CH2-CH2-CH3
D.
None of the above
Show solution
Solution
1-heptyne has a triple bond between the first and second carbons, represented as CH3-CH2-CH2-CH2-CH2-C≡C-H.
Correct Answer:
A
— CH3-CH2-CH2-CH2-CH2-C≡C-H
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Q. Which of the following is the correct structure for 1-hexene?
A.
CH2=CH-CH2-CH2-CH2-CH3
B.
CH3-CH2-CH2-CH=CH-CH3
C.
CH3-CH=CH-CH2-CH2-CH3
D.
CH3-CH2-CH=CH-CH2-CH3
Show solution
Solution
1-hexene has a double bond between the first and second carbon atoms, represented as CH2=CH-CH2-CH2-CH2-CH3.
Correct Answer:
A
— CH2=CH-CH2-CH2-CH2-CH3
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Q. Which of the following is the correct structure for 3-methyl-1-butyne?
A.
CH3-CH2-C≡C-CH3
B.
CH3-C≡C-CH2-CH3
C.
CH3-CH-C≡C-CH3
D.
CH3-CH2-CH-C≡C-H
Show solution
Solution
3-methyl-1-butyne has a triple bond at the first carbon and a methyl group on the third carbon.
Correct Answer:
B
— CH3-C≡C-CH2-CH3
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Q. Which of the following is the correct structure for 3-pentanone?
A.
CH3COCH2CH2CH3
B.
CH3CH2COCH2CH3
C.
CH3CH2CH2COCH3
D.
CH3COCH3
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Solution
3-Pentanone has the structure CH3CH2COCH2CH3, with the carbonyl group on the third carbon.
Correct Answer:
B
— CH3CH2COCH2CH3
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Q. Which of the following is the functional group of amines?
A.
-OH
B.
-NH2
C.
-COOH
D.
-C=O
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Solution
Amines contain the amino group (-NH2) as their functional group.
Correct Answer:
B
— -NH2
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Q. Which of the following ligands is considered a bidentate ligand according to Werner's theory?
A.
NH3
B.
EDTA
C.
Cl-
D.
H2O
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Solution
EDTA is a bidentate ligand because it can form two bonds with a metal ion, while NH3, Cl-, and H2O are monodentate ligands.
Correct Answer:
B
— EDTA
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Q. Which of the following ligands would be classified as a bidentate ligand according to Werner's theory?
A.
NH3
B.
EDTA
C.
Cl-
D.
H2O
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Solution
EDTA is a bidentate ligand because it can form two bonds with a metal ion.
Correct Answer:
B
— EDTA
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Q. Which of the following methods can be used to prepare primary amines?
A.
Reduction of nitriles
B.
Hydrolysis of amides
C.
Alkylation of ammonia
D.
All of the above
Show solution
Solution
Primary amines can be prepared by the reduction of nitriles, hydrolysis of amides, and alkylation of ammonia.
Correct Answer:
D
— All of the above
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Q. Which of the following molecules has sp2 hybridization?
A.
C2H2
B.
C2H4
C.
CH4
D.
C2H6
Show solution
Solution
In C2H4 (ethylene), each carbon atom is sp2 hybridized, forming three sigma bonds and one pi bond, resulting in a planar structure.
Correct Answer:
B
— C2H4
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Q. Which of the following orbitals can hold a maximum of 6 electrons?
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Solution
The p orbital can hold a maximum of 6 electrons (2 per each of the 3 p orbitals).
Correct Answer:
B
— p
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Q. Which of the following polymers is known for its high tensile strength and is commonly used in fibers?
A.
Polyethylene
B.
Nylon
C.
Polystyrene
D.
Polyvinyl chloride
Show solution
Solution
Nylon is a synthetic polymer known for its high tensile strength and is widely used in textiles and fibers.
Correct Answer:
B
— Nylon
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Q. Which of the following polymers is known for its high thermal stability and is often used in engineering applications?
A.
Polyethylene
B.
Polystyrene
C.
Polyimide
D.
Polyvinyl chloride
Show solution
Solution
Polyimide is known for its high thermal stability and is used in applications such as aerospace and electronics.
Correct Answer:
C
— Polyimide
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Q. Which of the following reactions can alkenes undergo?
A.
Esterification
B.
Hydrogenation
C.
Dehydration
D.
All of the above
Show solution
Solution
Alkenes can undergo hydrogenation, dehydration, and esterification, making all of the above reactions applicable.
Correct Answer:
D
— All of the above
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Q. Which of the following reactions involves a Friedel-Crafts acylation?
A.
Benzene + CH3Cl
B.
Benzene + CH3COCl
C.
Benzene + HNO3
D.
Benzene + H2SO4
Show solution
Solution
Friedel-Crafts acylation involves the reaction of benzene with an acyl chloride (like CH3COCl) in the presence of a Lewis acid.
Correct Answer:
B
— Benzene + CH3COCl
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Q. Which of the following reactions is an example of an SN1 mechanism?
A.
Tertiary alkyl halide with water
B.
Primary alkyl halide with NaOH
C.
Secondary alkyl halide with KCN
D.
Tertiary alkyl halide with NaOEt
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Solution
The reaction of a tertiary alkyl halide with water is an SN1 mechanism due to the formation of a stable carbocation.
Correct Answer:
A
— Tertiary alkyl halide with water
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Q. Which of the following reactions is an example of electrophilic aromatic substitution?
A.
Hydrogenation of benzene
B.
Nitration of benzene
C.
Oxidation of toluene
D.
Reduction of nitrobenzene
Show solution
Solution
Nitration of benzene is an example of electrophilic aromatic substitution, where a nitro group replaces a hydrogen atom on the benzene ring.
Correct Answer:
B
— Nitration of benzene
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Q. Which of the following reactions is an example of Friedel-Crafts acylation?
A.
Benzene + CH3Cl in AlCl3
B.
Benzene + CH3COCl in AlCl3
C.
Benzene + HNO3 in H2SO4
D.
Benzene + Br2 in FeBr3
Show solution
Solution
Benzene + CH3COCl in AlCl3 is an example of Friedel-Crafts acylation, where an acyl group is introduced to the aromatic ring.
Correct Answer:
B
— Benzene + CH3COCl in AlCl3
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Q. Which of the following solutions would have the highest boiling point?
A.
0.1 m NaCl
B.
0.1 m KCl
C.
0.1 m CaCl2
D.
0.1 m glucose
Show solution
Solution
0.1 m CaCl2 produces three particles (Ca2+ and 2 Cl-), leading to the highest boiling point elevation among the options.
Correct Answer:
C
— 0.1 m CaCl2
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Q. Which of the following statements about electrophilic aromatic substitution is true?
A.
The aromatic ring acts as a nucleophile.
B.
The electrophile is generated in situ.
C.
Both ortho and para products are formed equally.
D.
The reaction requires a strong base.
Show solution
Solution
In electrophilic aromatic substitution, the aromatic ring acts as a nucleophile, attacking the electrophile to form a sigma complex.
Correct Answer:
A
— The aromatic ring acts as a nucleophile.
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Q. Which of the following statements about enantiomers is true?
A.
They have identical physical properties.
B.
They rotate plane-polarized light in opposite directions.
C.
They can be separated by simple distillation.
D.
They have the same molecular formula but different connectivity.
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Solution
Enantiomers are non-superimposable mirror images and rotate plane-polarized light in opposite directions.
Correct Answer:
B
— They rotate plane-polarized light in opposite directions.
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Q. Which of the following statements about hybridization is true?
A.
Hybrid orbitals are always degenerate.
B.
Hybridization involves mixing of atomic orbitals.
C.
Hybridization does not affect molecular geometry.
D.
Hybrid orbitals are used only in covalent bonding.
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Solution
Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals that can form covalent bonds.
Correct Answer:
B
— Hybridization involves mixing of atomic orbitals.
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Q. Which of the following statements about reaction mechanisms is true?
A.
All reactions proceed through a single elementary step.
B.
Catalysts are consumed in the reaction.
C.
The rate-determining step is the slowest step in a mechanism.
D.
Intermediates are always stable.
Show solution
Solution
The rate-determining step is indeed the slowest step in a reaction mechanism, which controls the overall rate of the reaction.
Correct Answer:
C
— The rate-determining step is the slowest step in a mechanism.
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Q. Which of the following statements about real gases is true?
A.
Real gases have perfectly elastic collisions.
B.
Real gases have no intermolecular forces.
C.
Real gases occupy no volume.
D.
Real gases can condense into liquids.
Show solution
Solution
Real gases can condense into liquids under certain conditions, unlike ideal gases which are assumed to have no volume and no intermolecular forces.
Correct Answer:
D
— Real gases can condense into liquids.
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Q. Which of the following statements about stereochemistry is true for E2 reactions?
A.
They require a strong nucleophile
B.
They can lead to both E and Z isomers
C.
They require anti-periplanar geometry
D.
They always produce a racemic mixture
Show solution
Solution
E2 reactions require the leaving group and the hydrogen to be anti-periplanar for the elimination to occur.
Correct Answer:
C
— They require anti-periplanar geometry
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Q. Which of the following statements about stereochemistry is true for the reaction of 2-bromobutane with NaOH?
A.
Only R isomer is formed
B.
Only S isomer is formed
C.
Both R and S isomers are formed
D.
No stereoisomers are formed
Show solution
Solution
The reaction can lead to both R and S isomers due to the nature of the nucleophilic substitution mechanism.
Correct Answer:
C
— Both R and S isomers are formed
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Q. Which of the following statements about stereoisomers is true?
A.
They have the same molecular formula.
B.
They have different connectivity of atoms.
C.
They cannot be interconverted without breaking bonds.
D.
They have different physical properties.
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Solution
Stereoisomers have the same connectivity but differ in the spatial arrangement of atoms, and they cannot be interconverted without breaking bonds.
Correct Answer:
C
— They cannot be interconverted without breaking bonds.
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Q. Which of the following statements about the E1 elimination mechanism is true?
A.
It involves a concerted mechanism.
B.
It forms a carbocation intermediate.
C.
It is favored by strong bases.
D.
It occurs in a single step.
Show solution
Solution
E1 elimination involves the formation of a carbocation intermediate, making it a two-step process.
Correct Answer:
B
— It forms a carbocation intermediate.
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Q. Which of the following statements about the E2 elimination mechanism is true?
A.
It involves a carbocation intermediate.
B.
It requires a strong base.
C.
It is a unimolecular process.
D.
It occurs in a stepwise manner.
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Solution
E2 elimination requires a strong base to abstract a proton while the leaving group departs, and it occurs in a single concerted step.
Correct Answer:
B
— It requires a strong base.
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Q. Which of the following statements about the quantum model of the atom is true?
A.
Electrons are in fixed orbits
B.
Electrons have defined paths
C.
Electrons exist in probability clouds
D.
Electrons are stationary
Show solution
Solution
In the quantum model, electrons exist in probability clouds rather than fixed orbits.
Correct Answer:
C
— Electrons exist in probability clouds
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