Undergraduate MCQ & Objective Questions
The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention
Exam Relevance
Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.
Common Mistakes Students Make
Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests
FAQs
Question: What are some effective strategies for solving undergraduate MCQ questions?Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.
Question: How can I improve my speed in answering objective questions?Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.
Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. A 10 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?
A.
80 J
B.
40 J
C.
20 J
D.
160 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 10 kg × (4 m/s)² = 80 J
Correct Answer:
A
— 80 J
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Q. A 10 kg object is moving with a velocity of 4 m/s. What is its total mechanical energy if it is at a height of 5 m? (2020)
A.
120 J
B.
140 J
C.
100 J
D.
80 J
Show solution
Solution
Total Mechanical Energy = Kinetic Energy + Potential Energy = (1/2 * 10 kg * (4 m/s)²) + (10 kg * 9.8 m/s² * 5 m) = 80 J + 490 J = 570 J
Correct Answer:
B
— 140 J
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Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 10 kg object is thrown upwards with a velocity of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
A.
11.5 m
B.
22.5 m
C.
15.0 m
D.
7.5 m
Show solution
Solution
Using energy conservation: KE_initial = PE_max; 0.5 * m * v² = mgh; h = v² / (2g) = (15 m/s)² / (2 * 9.8 m/s²) = 11.5 m.
Correct Answer:
A
— 11.5 m
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Q. A 10 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²) (2020)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Using the formula h = v² / (2g), h = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer:
B
— 30 m
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Q. A 10 kg object is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2023)
A.
20 m
B.
40 m
C.
30 m
D.
10 m
Show solution
Solution
Using the formula h = (v²)/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer:
B
— 40 m
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Q. A 10 N force is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?
A.
20 J
B.
40 J
C.
30 J
D.
10 J
Show solution
Solution
Work done (W) = F × d × cos(θ) = 10 N × 4 m × cos(60°) = 10 × 4 × 0.5 = 20 J.
Correct Answer:
C
— 30 J
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Q. A 10 N force is applied to move an object 3 m. What is the work done if the force is applied at an angle of 60 degrees to the direction of motion?
A.
15 J
B.
30 J
C.
25 J
D.
20 J
Show solution
Solution
Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J
Correct Answer:
A
— 15 J
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Q. A 10 Ω resistor is connected to a 20 V battery. What is the current flowing through the resistor?
A.
2 A
B.
0.5 A
C.
5 A
D.
10 A
Show solution
Solution
Using Ohm's law, V = IR, where V = 20 V and R = 10 Ω. Therefore, I = V/R = 20/10 = 2 A.
Correct Answer:
A
— 2 A
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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)
A.
20 W
B.
40 W
C.
10 W
D.
2 W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer:
B
— 40 W
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Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
Show solution
Solution
Using the heat transfer equation, we can find the final temperature to be 50°C.
Correct Answer:
C
— 50°C
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Q. A 100 W bulb is connected to a 220 V supply. What is the current flowing through the bulb?
A.
0.45 A
B.
1.0 A
C.
2.2 A
D.
2.5 A
Show solution
Solution
Using the formula P = VI, where P = 100 W and V = 220 V, the current I = P/V = 100/220 ≈ 0.45 A.
Correct Answer:
A
— 0.45 A
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Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)
A.
500 Wh
B.
1000 Wh
C.
200 Wh
D.
250 Wh
Show solution
Solution
Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.
Correct Answer:
A
— 500 Wh
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Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?
A.
112,500 J
B.
75,000 J
C.
50,000 J
D.
25,000 J
Show solution
Solution
Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.
Correct Answer:
A
— 112,500 J
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Q. A 1000 kg car is moving at a speed of 20 m/s. What is its momentum? (2000)
A.
2000 kg m/s
B.
10000 kg m/s
C.
5000 kg m/s
D.
4000 kg m/s
Show solution
Solution
Momentum (p) is calculated using the formula p = m * v. Here, p = 1000 kg * 20 m/s = 20000 kg m/s.
Correct Answer:
B
— 10000 kg m/s
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Q. A 1000 kg car is moving at a speed of 36 km/h. What is its kinetic energy? (1 km/h = 1/3.6 m/s) (2000)
A.
500 J
B.
1000 J
C.
2000 J
D.
5000 J
Show solution
Solution
First convert speed: 36 km/h = 10 m/s. KE = 0.5 × m × v² = 0.5 × 1000 kg × (10 m/s)² = 0.5 × 1000 × 100 = 50000 J.
Correct Answer:
C
— 2000 J
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Q. A 1000 W electric motor runs for 2 hours. How much work does it do? (2023)
A.
720,000 J
B.
1,000,000 J
C.
2,000,000 J
D.
1,440,000 J
Show solution
Solution
Work = Power × Time = 1000 W × (2 × 3600 s) = 7,200,000 J.
Correct Answer:
D
— 1,440,000 J
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Q. A 1000 W heater is used to heat water. How much heat is supplied in 10 minutes? (2020)
A.
600 kJ
B.
300 kJ
C.
100 kJ
D.
150 kJ
Show solution
Solution
Heat (Q) = Power (P) * Time (t) = 1000 W * 600 s = 600 kJ.
Correct Answer:
A
— 600 kJ
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Q. A 100W bulb operates at 220V. What is the resistance of the bulb? (2021)
A.
484Ω
B.
220Ω
C.
110Ω
D.
100Ω
Show solution
Solution
Using P = V^2/R, we rearrange to find R = V^2/P = (220V)^2 / 100W = 484Ω.
Correct Answer:
A
— 484Ω
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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
Show solution
Solution
Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.
Correct Answer:
C
— 3 m/s
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Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)
A.
36 kg·m/s
B.
12 kg·m/s
C.
9 kg·m/s
D.
24 kg·m/s
Show solution
Solution
Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.
Correct Answer:
A
— 36 kg·m/s
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Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 12V battery is connected across a 4Ω resistor. What is the current flowing through the resistor? (2020)
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer:
A
— 2A
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Q. A 12V battery is connected to a resistor of 4Ω. What is the current flowing through the circuit? (2022)
Show solution
Solution
Using Ohm's law, I = V/R = 12V / 4Ω = 3A.
Correct Answer:
A
— 2A
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Q. A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)
A.
30 N
B.
60 N
C.
51.96 N
D.
15 N
Show solution
Solution
Horizontal component = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.
Correct Answer:
C
— 51.96 N
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Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)
A.
15 N
B.
30 N
C.
45 N
D.
150 N
Show solution
Solution
Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.
Correct Answer:
B
— 30 N
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