For capacitors in parallel, the total capacitance is the sum: C_total = C1 + C2.

Frequency (f) is the reciprocal of the period (T). Thus, f = 1/T = 1/0.02 s = 50 Hz.

A capacitor is used to store electrical energy in an electric field, which can be released when needed.

The magnetic field around a straight conductor carrying current forms concentric circles around the wire.

The magnetic field around a straight current-carrying conductor forms concentric circles around the wire, as described by Ampère's circuital law.

The magnetic field at the center of a circular loop is given by B = (μ₀ * I) / (2 * R). Using μ₀ = 4π x 10^-7 Tm/A, B = (4π x 10^-7 * 5) / (2 * 0.1) = 0.1 T.

The magnetic field (B) at the center of a circular loop is given by B = (μ₀ * I) / (2 * R). Using μ₀ = 4π x 10^-7 Tm/A, B = (4π x 10^-7 * 3) / (2 * 0.1) = 0.1 T.

The magnetic field at the center of a circular loop is given by B = (μ0I)/(2r).

Using Ohm's Law (V = I * R), V = 3 A * 10 Ω = 30 V.

Power (P) is given by P = V * I. Thus, P = 12 V * 2 A = 24 W.

Power (P) is calculated using the formula P = V * I. Therefore, P = 120 V * 2 A = 240 W.

Power P is calculated using P = V * I. Therefore, P = 120 V * 3 A = 360 W.

Power (P) = Voltage (V) × Current (I) = 120V × 3A = 360W.

Power (P) is calculated as P = V * I. Thus, P = 120 V * 3 A = 360 W.

Resistance R = ρ * (L/A). Here, R = (1.7 x 10^-8 Ωm) * (2 m / (1 x 10^-6 m²)) = 0.034 Ω.

For capacitors in series, 1/C_total = 1/C1 + 1/C2. Thus, 1/C_total = 1/2 + 1/3 = 5/6, so C_total = 1.2 µF.

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3 µF + 6 µF = 9 µF.

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3 µF + 6 µF = 9 µF.

For capacitors in series, 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/4 + 1/6 = 5/12. Therefore, C_eq = 2.4 microfarads.

The formula for total capacitance in series is 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/3 + 1/6 = 1/2, so C_eq = 2μF.

In a parallel circuit, the total current is the sum of the currents in each branch: I_total = 2 A + 3 A + 5 A = 10 A.

In a parallel circuit, the total current is the sum of the currents in each branch: I_total = I1 + I2 = 3 A + 5 A = 8 A.

Energy (E) stored in a capacitor is given by E = 0.5 * C * V^2. Thus, E = 0.5 * 20 x 10^-6 F * (10 V)^2 = 0.1 joules.

In a series circuit, total resistance (R_total) is the sum of individual resistances: R_total = 4 + 6 + 10 = 20 ohms.