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Q. A capacitor of capacitance 10 microfarads is charged to a voltage of 5 volts. What is the charge stored in the capacitor?

A. 50 microcoulombs
B. 5 microcoulombs
C. 0.5 microcoulombs
D. 100 microcoulombs

Solution

Charge (Q) is given by Q = C * V. Thus, Q = 10 µF * 5 V = 50 µC.

Correct Answer: A — 50 microcoulombs

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Q. A capacitor of capacitance 5 µF is charged to a voltage of 10V. What is the charge stored in the capacitor? (2022)

A. 50 µC
B. 100 µC
C. 500 µC
D. 1000 µC

Solution

Charge (Q) = Capacitance (C) × Voltage (V) = 5µF × 10V = 50µC.

Correct Answer: B — 100 µC

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Q. A capacitor stores 5 microfarads of charge at a voltage of 10 volts. What is the energy stored in the capacitor?

A. 0.25 mJ
B. 0.5 mJ
C. 0.75 mJ
D. 1 mJ

Solution

The energy stored in a capacitor is given by the formula E = 0.5 * C * V^2. Here, E = 0.5 * 5 * 10^-6 F * (10 V)^2 = 0.5 * 5 * 10^-6 * 100 = 0.25 mJ.

Correct Answer: B — 0.5 mJ

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Q. A capacitor stores energy in the form of which type of field?

A. Electric field
B. Magnetic field
C. Gravitational field
D. Electromagnetic field

Solution

A capacitor stores energy in the form of an electric field between its plates.

Correct Answer: A — Electric field

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Q. A car accelerates from rest at a rate of 2 m/s². How far does it travel in 10 seconds? (2020)

A. 50 m
B. 100 m
C. 150 m
D. 200 m

Solution

Using the formula s = ut + (1/2)at²; s = 0 + (1/2)(2)(10²) = 100 m.

Correct Answer: B — 100 m

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Q. A car accelerates uniformly from rest to a speed of 25 m/s in 10 seconds. What is the distance covered during this time? (2020)

A. 100 m
B. 125 m
C. 150 m
D. 200 m

Solution

Using the formula s = ut + (1/2)at². Here, u = 0, a = (25-0)/10 = 2.5 m/s². s = 0 + (1/2)(2.5)(10²) = 125 m.

Correct Answer: B — 125 m

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Q. A car travels 100 km in 2 hours and then 50 km in 1 hour. What is the average speed of the car for the entire journey? (2021)

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 75 km/h

Solution

Total distance = 100 km + 50 km = 150 km. Total time = 2 h + 1 h = 3 h. Average speed = Total distance / Total time = 150 km / 3 h = 50 km/h.

Correct Answer: C — 70 km/h

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Q. A car travels 100 km in 2 hours and then 50 km in 1 hour. What is the total average speed of the car? (2019)

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 80 km/h

Solution

Total distance = 100 + 50 = 150 km. Total time = 2 + 1 = 3 hours. Average speed = Total distance / Total time = 150/3 = 50 km/h.

Correct Answer: B — 60 km/h

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Q. A car travels a distance of 150 km at a speed of 50 km/h. How long does the journey take?

A. 2 hours
B. 3 hours
C. 4 hours
D. 5 hours

Solution

Time = distance/speed = 150 km / 50 km/h = 3 hours.

Correct Answer: B — 3 hours

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Q. A car travels a distance of 150 m in 5 seconds. What is its average speed?

A. 25 m/s
B. 30 m/s
C. 35 m/s
D. 40 m/s

Solution

Average speed = total distance / total time = 150 m / 5 s = 30 m/s.

Correct Answer: A — 25 m/s

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Q. A car travels at a speed of 60 km/h. How far will it travel in 2.5 hours? (2021)

A. 120 km
B. 150 km
C. 180 km
D. 200 km

Solution

Distance = Speed × Time = 60 km/h × 2.5 h = 150 km

Correct Answer: B — 150 km

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Q. A car travels at a speed of 72 km/h. What is its speed in m/s?

A. 20 m/s
B. 15 m/s
C. 25 m/s
D. 30 m/s

Solution

Speed in m/s = (72 * 1000 m) / (3600 s) = 20 m/s.

Correct Answer: C — 25 m/s

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Q. A concave mirror has a focal length of 20 cm. What is the distance of the object from the mirror if the image formed is at a distance of 30 cm from the mirror? (2021)

A. 10 cm
B. 15 cm
C. 25 cm
D. 30 cm

Solution

Using the mirror formula: 1/f = 1/v + 1/u, where f = -20 cm (concave mirror), v = -30 cm (image distance), we find u = 25 cm.

Correct Answer: C — 25 cm

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Q. A concave mirror has a focal length of 20 cm. What is the radius of curvature of the mirror? (2021)

A. 10 cm
B. 20 cm
C. 30 cm
D. 40 cm

Solution

The radius of curvature (R) is twice the focal length (f). Therefore, R = 2f = 2 * 20 cm = 40 cm.

Correct Answer: B — 20 cm

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Q. A convex lens has a focal length of 20 cm. If an object is placed 60 cm from the lens, what is the position of the image?

A. 15 cm
B. 20 cm
C. 30 cm
D. 40 cm

Solution

Using the lens formula, 1/f = 1/v - 1/u, we find v = 30 cm.

Correct Answer: D — 40 cm

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Q. A convex lens has a focal length of 25 cm. What is the power of the lens? (2021)

A. +2 D
B. +4 D
C. +6 D
D. +8 D

Solution

Power (P) = 1/f (in meters). Thus, P = 1/0.25 = +4 D.

Correct Answer: B — +4 D

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Q. A cyclist covers a distance of 30 km at a speed of 15 km/h. How long does it take to cover this distance? (2022)

A. 1 hour
B. 2 hours
C. 2.5 hours
D. 3 hours

Solution

Time = Distance / Speed = 30 km / 15 km/h = 2 hours.

Correct Answer: B — 2 hours

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Q. A cyclist covers a distance of 30 km at a speed of 15 km/h. How long does it take to complete the journey? (2022)

A. 1 hour
B. 2 hours
C. 2.5 hours
D. 3 hours

Solution

Time = Distance / Speed = 30 km / 15 km/h = 2 hours.

Correct Answer: B — 2 hours

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Q. A cyclist covers a distance of 30 km in 1.5 hours. What is his speed in m/s? (2022)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Speed = Distance / Time = 30 km / 1.5 h = 20 km/h = (20 × 1000 m) / (3600 s) = 5.56 m/s, approximately 5 m/s.

Correct Answer: B — 10 m/s

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Q. A cyclist covers a distance of 90 km in 3 hours. What is the average speed of the cyclist? (2022)

A. 25 km/h
B. 30 km/h
C. 35 km/h
D. 40 km/h

Solution

Average Speed = Total Distance / Total Time = 90 km / 3 h = 30 km/h.

Correct Answer: B — 30 km/h

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Q. A cyclist travels at a speed of 10 m/s for 30 seconds. How far does the cyclist travel?

A. 300 m
B. 200 m
C. 150 m
D. 250 m

Solution

Distance = speed × time = 10 m/s × 30 s = 300 m.

Correct Answer: A — 300 m

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Q. A force of 10 N is applied to move a box 5 m across a frictionless surface. What is the work done on the box? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

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Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done? (2021)

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done = Force × Distance = 10 N × 5 m = 50 J

Correct Answer: B — 20 J

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Q. A force of 10 N is applied to move an object 5 m in the direction of the force. What is the work done on the object?

A. 10 J
B. 20 J
C. 50 J
D. 5 J

Solution

Work done (W) = Force (F) × Distance (d) × cos(θ). Here, θ = 0° (force and displacement are in the same direction). W = 10 N × 5 m × cos(0°) = 10 N × 5 m = 50 J.

Correct Answer: B — 20 J

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Q. A force of 15 N is applied at an angle of 30° to the horizontal. What is the horizontal component of the force? (2020)

A. 7.5 N
B. 12.99 N
C. 15 N
D. 10 N

Solution

Horizontal component = F × cos(θ) = 15 N × cos(30°) = 15 N × √3/2 ≈ 12.99 N.

Correct Answer: B — 12.99 N

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Q. A force of 15 N is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done by the force?

A. 30 J
B. 60 J
C. 45 J
D. 20 J

Solution

Work done (W) = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 N × 4 m × 0.5 = 30 J.

Correct Answer: C — 45 J

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Q. A force of 50 N is applied at an angle of 30° to the horizontal. What is the horizontal component of the force? (2020)

A. 25 N
B. 43.3 N
C. 50 N
D. 35 N

Solution

Horizontal component = Fcos(θ) = 50 N × cos(30°) = 50 N × (√3/2) ≈ 43.3 N.

Correct Answer: B — 43.3 N

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Q. A force of 50 N is applied at an angle of 60° to the horizontal. What is the horizontal component of the force? (2020)

A. 25 N
B. 50 N
C. 43.3 N
D. 30 N

Solution

Horizontal component = F × cos(θ) = 50 N × cos(60°) = 50 N × 0.5 = 25 N.

Correct Answer: C — 43.3 N

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Q. A gas expands isothermally at 300 K from a volume of 1 m³ to 2 m³. If the pressure of the gas is 100 kPa, what is the work done by the gas during expansion? (2019)

A. 20 kJ
B. 30 kJ
C. 40 kJ
D. 50 kJ

Solution

Work done (W) = PΔV = 100 kPa * (2 m³ - 1 m³) = 100 kPa * 1 m³ = 100 kJ = 20 kJ.

Correct Answer: A — 20 kJ

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Q. A lens forms a real image that is twice the size of the object. If the object distance is 10 cm, what is the image distance? (2021)

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the magnification formula m = -v/u, where m = 2 and u = -10 cm, we find v = -2 * (-10) = 20 cm.

Correct Answer: C — 20 cm

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Physics

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