Using inclusion-exclusion, the percentage that likes either fruit is 25% + 15% - 5% = 35%.

The percentage of people who like only apples is 25% - 10% = 15%.

Using inclusion-exclusion, the percentage of people who like either activity is: 25% + 15% - 5% = 35%.

The number of arrangements of 4 distinct books is 4! = 24.

The number of arrangements of 4 distinct books is 4! = 24.

The number of students who like only Mathematics is 40 - 10 = 30.

The number of arrangements of 6 different colored balls is 6! = 720.

Using inclusion-exclusion, the percentage is 60% + 40% - 10% = 90%.

The percentage of students who like only reading is 60% - 10% = 50%.

The percentage of students who like only writing is 40% - 10% = 30%.

Using inclusion-exclusion, the percentage of students who play either cricket or football is: 60% + 40% - 10% = 90%.

The percentage of students who play only cricket is 60% - 10% = 50%.

The percentage playing only cricket is 60% - 10% = 50%, and only football is 40% - 10% = 30%. Thus, total playing only one sport is 50% + 30% = 80%.

Using inclusion-exclusion, the percentage playing either is 60% + 50% - 30% = 80%.

Using inclusion-exclusion, the percentage playing either sport is 60% + 40% - 10% = 90%.

Using inclusion-exclusion, the percentage of students who play either sport is: 60% + 40% - 10% = 90%.

Using inclusion-exclusion, the percentage liking at least one is 80% + 60% - 30% = 110%, which is capped at 100%.

The probability of selecting a non-defective item is 16/(4+16) = 16/20 = 4/5.

The number of ways to choose 3 people from 5 is given by 5C3 = 10.

The number of ways to choose 3 members from 5 is given by 5C3 = 10.

Substituting x = 4 into the function gives f(4) = 2(4) + 3 = 8 + 3 = 11.

To find f(4), substitute 4 into the function: f(4) = 3(4) + 2 = 12 + 2 = 14.

Each digit can be any of the 10 digits (0-9). Therefore, the total combinations = 10^4 = 10000.

Each digit can be any of the 10 digits (0-9), so the total combinations = 10^4 = 10000.

The number of ways to choose 3 different digits from 10 is 10P3 = 720.

Each digit can be any of the 10 digits, so the total combinations are 10^3 = 1000.

The first digit has 10 options, the second has 9, and the third has 8. Total = 10 * 9 * 8 = 720.

The number of ways to choose 3 letters from 3 is 3! and 2 digits from 5 is 5P2. Total = 3! * 5P2 = 6 * 20 = 120.

There are 26 letters and 10 digits. The total combinations are 26^3 * 10^2 = 17576000.

The number of passwords is 26^3 * 10^2 = 17576000.