Q. What is the integral of tan(x) with respect to x? (2021)
-
A.
-ln
-
B.
cos(x)
-
C.
+ C
-
D.
ln
-
.
sin(x)
-
.
+ C
-
.
ln
-
.
tan(x)
-
.
+ C
-
.
-ln
-
.
sin(x)
-
.
+ C
Solution
The integral of tan(x) is -ln|cos(x)| + C.
Correct Answer:
A
— -ln
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Q. What is the integral of tan(x)? (2021)
-
A.
-ln
-
B.
cos(x)
-
C.
+ C
-
D.
ln
-
.
sin(x)
-
.
+ C
-
.
ln
-
.
tan(x)
-
.
+ C
-
.
-ln
-
.
sin(x)
-
.
+ C
Solution
The integral of tan(x) is -ln|cos(x)| + C.
Correct Answer:
A
— -ln
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Q. What is the integral of x^2 with respect to x? (2021)
-
A.
(1/3)x^3 + C
-
B.
(1/2)x^2 + C
-
C.
(1/4)x^4 + C
-
D.
(1/5)x^5 + C
Solution
The integral of x^n is (1/(n+1))x^(n+1) + C. Here, n=2, so the integral is (1/3)x^3 + C.
Correct Answer:
A
— (1/3)x^3 + C
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Q. What is the integral of x^3 + 2x? (2021)
-
A.
(1/4)x^4 + x^2 + C
-
B.
(1/3)x^3 + x^2 + C
-
C.
(1/4)x^4 + (1/2)x^2 + C
-
D.
(1/5)x^5 + (1/2)x^2 + C
Solution
Integrating term by term, ∫x^3dx = (1/4)x^4 and ∫2xdx = x^2. Thus, ∫(x^3 + 2x)dx = (1/4)x^4 + (1/2)x^2 + C.
Correct Answer:
C
— (1/4)x^4 + (1/2)x^2 + C
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Q. What is the integral of x^n where n ≠ -1? (2021)
-
A.
(1/n)x^(n+1) + C
-
B.
(1/(n+1))x^n + C
-
C.
(1/(n+1))x^(n+1) + C
-
D.
nx^(n-1) + C
Solution
The integral of x^n is (1/(n+1))x^(n+1) + C, provided n ≠ -1.
Correct Answer:
C
— (1/(n+1))x^(n+1) + C
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Showing 31 to 35 of 35 (2 Pages)
