Q. If a 9V battery is connected to a 3Ω resistor, what is the current flowing through it? (2021)
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Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer:
B
— 2A
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Q. If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10 seconds? (2023)
A.
30J
B.
90J
C.
60J
D.
45J
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Solution
Power (P) = V²/R = 9²/3 = 27W. Energy (E) = P * t = 27W * 10s = 270J.
Correct Answer:
B
— 90J
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Q. If a 9V battery is connected to a 3Ω resistor, what is the power dissipated in the resistor? (2023)
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Solution
Power (P) can be calculated using P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer:
A
— 3W
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Q. If a 9V battery is connected to a 3Ω resistor, what is the voltage drop across the resistor? (2023)
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Solution
The voltage drop across the resistor is equal to the battery voltage, which is 9V.
Correct Answer:
C
— 9V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A flows through it, what is the voltage across the circuit? (2022)
A.
18V
B.
12V
C.
15V
D.
10V
Show solution
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer:
A
— 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A, what is the voltage across the circuit? (2021)
A.
18V
B.
12V
C.
15V
D.
10V
Show solution
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer:
A
— 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 3A flows through it, what is the voltage across the circuit? (2020)
A.
36V
B.
12V
C.
4V
D.
24V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer:
A
— 36V
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Q. If a circuit has a total resistance of 12Ω and a current of 4A, what is the voltage across the circuit? (2023)
A.
48V
B.
36V
C.
24V
D.
12V
Show solution
Solution
Using Ohm's law, V = IR = 4A * 12Ω = 48V.
Correct Answer:
A
— 48V
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Q. If a circuit has a total resistance of 5Ω and a current of 2A, what is the voltage across the circuit? (2022)
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Solution
Using Ohm's law, V = I * R = 2A * 5Ω = 10V.
Correct Answer:
A
— 10V
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Q. If a circuit has a total resistance of 8Ω and a current of 4A, what is the voltage across the circuit? (2023)
A.
32V
B.
24V
C.
16V
D.
12V
Show solution
Solution
Using Ohm's law, V = IR = 4A * 8Ω = 32V.
Correct Answer:
A
— 32V
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Q. If the current through a resistor is tripled, what happens to the power dissipated in the resistor? (2022)
A.
Increases by 3 times
B.
Increases by 9 times
C.
Remains the same
D.
Decreases by 3 times
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Solution
Power is proportional to the square of the current (P = I²R). If I is tripled, P increases by 3² = 9 times.
Correct Answer:
B
— Increases by 9 times
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Q. If the resistance of a conductor is doubled, what happens to the current flowing through it when the voltage remains constant? (2022)
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by 1.5 times
Show solution
Solution
According to Ohm's law, I = V/R. If R is doubled, I will be halved.
Correct Answer:
B
— Halves
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Q. If the voltage across a resistor is halved, what happens to the current through it? (2020)
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's law, if voltage is halved and resistance remains constant, the current also halves.
Correct Answer:
B
— It halves
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Q. If two resistors of 4Ω and 6Ω are connected in series, what is the total resistance? (2023)
A.
10Ω
B.
24Ω
C.
2.4Ω
D.
12Ω
Show solution
Solution
In series, R_eq = R1 + R2 = 4Ω + 6Ω = 10Ω.
Correct Answer:
A
— 10Ω
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Q. If two resistors of 4Ω and 6Ω are connected in series, what is the total voltage across them if the current is 2A? (2022)
A.
20V
B.
12V
C.
8V
D.
10V
Show solution
Solution
Total resistance R = 4Ω + 6Ω = 10Ω. Voltage V = I * R = 2A * 10Ω = 20V.
Correct Answer:
A
— 20V
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Q. In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
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Solution
Total resistance R = 8Ω + 8Ω = 16Ω. Current I = V/R = 24V / 16Ω = 1.5A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in parallel, what is the total current supplied by the battery? (2022)
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Solution
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 24V / (8/3)Ω = 9A.
Correct Answer:
D
— 6A
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Q. In a circuit with a 5Ω and a 10Ω resistor in parallel, what is the total current if the voltage across them is 20V? (2022)
Show solution
Solution
First, find the equivalent resistance: 1/R_eq = 1/5 + 1/10 = 3/10, R_eq = 10/3Ω. Then, I = V/R_eq = 20V / (10/3)Ω = 6A.
Correct Answer:
A
— 4A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
Show solution
Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
Show solution
Solution
Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.
Correct Answer:
B
— 9W
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Q. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Show solution
Solution
Power P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer:
B
— 9W
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power consumed? (2020)
A.
It doubles
B.
It triples
C.
It remains the same
D.
It halves
Show solution
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which means power quadruples.
Correct Answer:
A
— It doubles
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Q. In a circuit, if the current is doubled while the resistance remains constant, what happens to the power? (2020)
A.
It doubles
B.
It quadruples
C.
It remains the same
D.
It halves
Show solution
Solution
Power is given by P = I²R. If I is doubled, P becomes (2I)²R = 4I²R, which is quadrupled.
Correct Answer:
B
— It quadruples
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Q. In a circuit, if the resistance is halved while the voltage remains constant, what happens to the current? (2022)
A.
It halves
B.
It doubles
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's law, I = V/R. If R is halved, I will double.
Correct Answer:
B
— It doubles
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Q. In a circuit, if the voltage is doubled and the resistance remains constant, what happens to the current? (2020)
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
Show solution
Solution
According to Ohm's law, I = V/R. If V is doubled, I also doubles.
Correct Answer:
A
— Doubles
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Q. In a parallel circuit with two resistors of 4Ω and 12Ω, what is the total current if the voltage across them is 24V? (2022)
Show solution
Solution
Total current I = V/R_eq. First, find R_eq = 1/(1/4 + 1/12) = 3Ω. Then, I = 24V / 3Ω = 8A.
Correct Answer:
A
— 6A
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Q. In a parallel circuit with two resistors of 4Ω and 12Ω, what is the total current if the voltage across the circuit is 24V? (2022)
Show solution
Solution
First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 3/12 + 1/12 = 4/12, R_eq = 3Ω. Then, I = V/R_eq = 24V / 3Ω = 8A.
Correct Answer:
C
— 8A
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total current if a 12V battery is connected? (2021)
Show solution
Solution
First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, so R_eq = 2Ω. Then, I = V/R_eq = 12V / 2Ω = 6A.
Correct Answer:
C
— 6A
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Q. In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)
A.
2Ω
B.
4Ω
C.
1.5Ω
D.
9Ω
Show solution
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.
Correct Answer:
B
— 4Ω
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Q. In a parallel circuit with two resistors of 8Ω and 4Ω, what is the total current if the voltage across the circuit is 16V? (2022)
Show solution
Solution
First, find the equivalent resistance: 1/R_eq = 1/8 + 1/4 = 1/8 + 2/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 16V / (8/3)Ω = 16 * 3/8 = 6A.
Correct Answer:
D
— 8A
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Showing 31 to 60 of 93 (4 Pages)
Current Electricity MCQ & Objective Questions
Current Electricity is a vital topic in physics that plays a significant role in various school and competitive exams. Understanding this concept not only helps in grasping fundamental principles but also enhances your ability to tackle MCQs and objective questions effectively. Practicing Current Electricity MCQ questions can significantly improve your exam preparation and boost your confidence in answering important questions.
What You Will Practise Here
Ohm's Law and its applications
Series and parallel circuits
Electrical power and energy calculations
Resistance, capacitance, and inductance concepts
Kirchhoff's laws and circuit analysis
Understanding current, voltage, and resistance relationships
Practical applications of Current Electricity in daily life
Exam Relevance
Current Electricity is a crucial topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that assess their understanding of key concepts, calculations, and application-based scenarios. Common question patterns include numerical problems, theoretical questions, and circuit diagram analysis, making it essential to master this topic for scoring well in exams.
Common Mistakes Students Make
Confusing series and parallel circuit calculations
Misapplying Ohm's Law in complex circuits
Overlooking units in calculations, leading to incorrect answers
Failing to understand the significance of Kirchhoff's laws
Neglecting practical applications, which can lead to conceptual gaps
FAQs
Question: What is Ohm's Law?Answer: Ohm's Law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, provided the temperature remains constant.
Question: How do you calculate total resistance in a series circuit?Answer: In a series circuit, the total resistance is the sum of all individual resistances: R_total = R1 + R2 + R3 + ...
Ready to enhance your understanding of Current Electricity? Dive into our practice MCQs and test your knowledge to excel in your exams!
