MHT-CET Exam Prep Resources | Soulshift Education

MHT-CET

Chemistry Mathematics Physics

Q. A 1000 kg car is moving at a speed of 15 m/s. What is its kinetic energy?

A. 112,500 J
B. 75,000 J
C. 50,000 J
D. 25,000 J

Solution

Kinetic Energy = 0.5 * m * v² = 0.5 * 1000 kg * (15 m/s)² = 112,500 J.

Correct Answer: A — 112,500 J

Learn More →

Q. A 1000 kg car is moving at a speed of 20 m/s. What is its momentum? (2000)

A. 2000 kg m/s
B. 10000 kg m/s
C. 5000 kg m/s
D. 4000 kg m/s

Solution

Momentum (p) is calculated using the formula p = m * v. Here, p = 1000 kg * 20 m/s = 20000 kg m/s.

Correct Answer: B — 10000 kg m/s

Learn More →

Q. A 1000 kg car is moving at a speed of 36 km/h. What is its kinetic energy? (1 km/h = 1/3.6 m/s) (2000)

A. 500 J
B. 1000 J
C. 2000 J
D. 5000 J

Solution

First convert speed: 36 km/h = 10 m/s. KE = 0.5 × m × v² = 0.5 × 1000 kg × (10 m/s)² = 0.5 × 1000 × 100 = 50000 J.

Correct Answer: C — 2000 J

Learn More →

Q. A 1000 W electric motor runs for 2 hours. How much work does it do? (2023)

A. 720,000 J
B. 1,000,000 J
C. 2,000,000 J
D. 1,440,000 J

Solution

Work = Power × Time = 1000 W × (2 × 3600 s) = 7,200,000 J.

Correct Answer: D — 1,440,000 J

Learn More →

Q. A 1000 W heater is used to heat water. How much heat is supplied in 10 minutes? (2020)

A. 600 kJ
B. 300 kJ
C. 100 kJ
D. 150 kJ

Solution

Heat (Q) = Power (P) * Time (t) = 1000 W * 600 s = 600 kJ.

Correct Answer: A — 600 kJ

Learn More →

Q. A 100W bulb operates at 220V. What is the resistance of the bulb? (2021)

A. 484Ω
B. 220Ω
C. 110Ω
D. 100Ω

Solution

Using P = V^2/R, we rearrange to find R = V^2/P = (220V)^2 / 100W = 484Ω.

Correct Answer: A — 484Ω

Learn More →

Q. A 12 kg object is pushed with a force of 36 N. What is its acceleration? (2023)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we find a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

Learn More →

Q. A 12V battery is connected across a 4Ω resistor. What is the current flowing through the resistor? (2020)

A. 2A
B. 3A
C. 4A
D. 6A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: A — 2A

Learn More →

Q. A 12V battery is connected to a resistor of 4Ω. What is the current flowing through the circuit? (2022)

A. 2A
B. 3A
C. 4A
D. 1A

Solution

Using Ohm's law, I = V/R = 12V / 4Ω = 3A.

Correct Answer: A — 2A

Learn More →

Q. A 15 kg box is pulled with a force of 60 N at an angle of 30° to the horizontal. What is the horizontal component of the force? (2022)

A. 30 N
B. 60 N
C. 51.96 N
D. 15 N

Solution

Horizontal component = F * cos(θ) = 60 N * cos(30°) = 60 N * (√3/2) = 51.96 N.

Correct Answer: C — 51.96 N

Learn More →

Q. A 15 kg object is dropped from a height. What is the force acting on it due to gravity? (2023)

A. 15 N
B. 30 N
C. 45 N
D. 150 N

Solution

Using F = mg, where g = 9.8 m/s², we have F = 15 kg * 9.8 m/s² = 147 N, which rounds to 150 N.

Correct Answer: B — 30 N

Learn More →

Q. A 15 kg object is lifted to a height of 4 m. What is the work done against gravity? (g = 9.8 m/s²) (2021)

A. 588 J
B. 5880 J
C. 392 J
D. 294 J

Solution

Work = mgh = 15 kg * 9.8 m/s² * 4 m = 588 J.

Correct Answer: A — 588 J

Learn More →

Q. A 15 kg object is moving at a speed of 4 m/s. What is its kinetic energy?

A. 120 J
B. 240 J
C. 480 J
D. 60 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 15 kg × (4 m/s)² = 0.5 × 15 × 16 = 120 J.

Correct Answer: B — 240 J

Learn More →

Q. A 15 kg object is moving with a velocity of 4 m/s. What is its momentum? (2019)

A. 60 kg m/s
B. 30 kg m/s
C. 45 kg m/s
D. 75 kg m/s

Solution

Momentum = mass × velocity = 15 kg × 4 m/s = 60 kg m/s.

Correct Answer: A — 60 kg m/s

Learn More →

Q. A 1500 kg car accelerates from rest to a speed of 25 m/s. What is the work done on the car?

A. 468,750 J
B. 375,000 J
C. 250,000 J
D. 187,500 J

Solution

Work done = Change in Kinetic Energy = 0.5 * m * v² = 0.5 * 1500 kg * (25 m/s)² = 468,750 J.

Correct Answer: A — 468,750 J

Learn More →

Q. A 1500 kg car is moving at a speed of 25 m/s. What is its kinetic energy? (2021)

A. 468,750 J
B. 1,875,000 J
C. 937,500 J
D. 750,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1500 kg × (25 m/s)² = 468,750 J

Correct Answer: B — 1,875,000 J

Learn More →

Q. A 2 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height reached? (2020)

A. 20 m
B. 40 m
C. 10 m
D. 30 m

Solution

Using v² = u² + 2as, 0 = (20 m/s)² + 2(-9.8 m/s²)(h). Solving gives h = 20.4 m.

Correct Answer: A — 20 m

Learn More →

Q. A 2 kg block is sliding down a frictionless incline of height 5 m. What is its speed at the bottom?

A. 10 m/s
B. 5 m/s
C. 20 m/s
D. 15 m/s

Solution

Using conservation of energy, potential energy at the top = kinetic energy at the bottom: mgh = 0.5mv². Solving gives v = √(2gh) = √(2 * 9.8 * 5) = 10 m/s.

Correct Answer: A — 10 m/s

Learn More →

Q. A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorbed if the latent heat of fusion of ice is 334,000 J/kg?

A. 668,000 J
B. 334,000 J
C. 167,000 J
D. 500,000 J

Solution

Heat absorbed = mass * latent heat = 2 kg * 334,000 J/kg = 668,000 J.

Correct Answer: A — 668,000 J

Learn More →

Q. A 2 kg block of metal at 100°C is placed in 1 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the heat transfer equation, the final temperature can be calculated to be 50°C.

Correct Answer: C — 50°C

Learn More →

Q. A 2 kg object is heated from 20°C to 80°C. If the specific heat capacity is 0.5 kJ/kg°C, how much heat is absorbed? (2023)

A. 30 kJ
B. 40 kJ
C. 20 kJ
D. 10 kJ

Solution

Q = mcΔT = 2 kg * 0.5 kJ/kg°C * (80°C - 20°C) = 60 kJ.

Correct Answer: B — 40 kJ

Learn More →

Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (2022)

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Potential Energy = mass × g × height = 2 kg × 10 m/s² × 5 m = 100 J

Correct Answer: B — 20 J

Learn More →

Q. A 2 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (g = 9.8 m/s²)

A. 98 J
B. 19.6 J
C. 39.2 J
D. 49 J

Solution

Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J

Correct Answer: A — 98 J

Learn More →

Q. A 2 kg object is pushed with a force of 10 N over a distance of 5 m. What is the work done on the object?

A. 25 J
B. 50 J
C. 75 J
D. 100 J

Solution

Work done = Force * Distance = 10 N * 5 m = 50 J.

Correct Answer: B — 50 J

Learn More →

Q. A 2 kg object is subjected to a net force of 8 N. What is its acceleration? (2020)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 8 N / 2 kg = 4 m/s².

Correct Answer: C — 4 m/s²

Learn More →

Q. A 20 kg cart is pulled with a force of 80 N. What is the acceleration of the cart? (2023)

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, we find a = F/m = 80 N / 20 kg = 4 m/s².

Correct Answer: B — 4 m/s²

Learn More →

Q. A 200 g piece of metal at 100°C is placed in 300 g of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.18 J/g°C, specific heat of metal = 0.9 J/g°C) (2022)

A. 22.5°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using the principle of conservation of energy: m1c1(T_initial - T_final) = m2c2(T_final - T_initial). Solving gives T_final = 35°C.

Correct Answer: C — 35°C

Learn More →

Q. A 25 kg object is acted upon by a force of 100 N. What is its acceleration? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we find a = F/m = 100 N / 25 kg = 4 m/s².

Correct Answer: D — 5 m/s²

Learn More →

Q. A 3 kg object is dropped from a height of 10 m. What is its potential energy at the top? (g = 9.8 m/s²)

A. 294 J
B. 30 J
C. 39.2 J
D. 19.6 J

Solution

Potential Energy (PE) = m × g × h = 3 kg × 9.8 m/s² × 10 m = 294 J.

Correct Answer: A — 294 J

Learn More →

Q. A 3 kg object is dropped from a height of 10 m. What is the potential energy at the top? (2022)

A. 30 J
B. 60 J
C. 90 J
D. 120 J

Solution

Potential Energy = mass × g × height = 3 kg × 10 m/s² × 10 m = 300 J

Correct Answer: C — 90 J

Learn More →

Showing 31 to 60 of 2530 (85 Pages)

MHT-CET

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?