Q. What is the molecular orbital configuration of F2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(π2p)⁴(π*2p)²
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
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Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of O2?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)⁴
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Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the molecular orbital configuration of the F2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)⁴
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)³(π*2p)²
Show solution
Solution
The correct configuration for F2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)².
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)⁴(π*2p)²
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Q. What is the molecular orbital configuration of the O2 molecule?
A.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
B.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)²
C.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)¹
D.
(σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)¹(π*2p)²
Show solution
Solution
The correct configuration for O2 is (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹.
Correct Answer:
A
— (σ1s)²(σ*1s)²(σ2s)²(σ*2s)²(σ2p)²(π2p)²(π*2p)¹
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Q. What is the shape of the molecular orbital in the case of a π bond?
A.
Spherical
B.
Dumbbell
C.
Linear
D.
Planar
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Solution
π bonds are formed by the side-to-side overlap of p orbitals, resulting in a planar shape.
Correct Answer:
D
— Planar
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Q. What is the shape of the molecular orbital in the highest occupied molecular orbital (HOMO) of benzene?
A.
Linear
B.
Trigonal planar
C.
Tetrahedral
D.
Cyclic
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Solution
The HOMO of benzene is cyclic due to the delocalization of π electrons in the ring structure.
Correct Answer:
D
— Cyclic
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Q. What is the shape of the molecular orbital of the highest energy in O2?
A.
spherical
B.
dumbbell
C.
double dumbbell
D.
linear
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Solution
The highest energy molecular orbital in O2 is a π* orbital, which has a dumbbell shape.
Correct Answer:
B
— dumbbell
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Q. What is the shape of the molecular orbital of the highest energy in the O2 molecule?
A.
Linear
B.
Bent
C.
Planar
D.
Diatomic
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Solution
The highest energy molecular orbital in O2 is a diatomic molecular orbital, specifically a π* orbital.
Correct Answer:
D
— Diatomic
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Q. Which of the following diatomic molecules has a bond order of 1?
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Solution
H2 has a bond order of 1, calculated as (2 bonding electrons - 0 antibonding electrons)/2 = 1.
Correct Answer:
C
— H2
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Q. Which of the following diatomic molecules has the highest bond order?
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Solution
N2 has the highest bond order of 3, while O2 has a bond order of 2 and F2 has a bond order of 1.
Correct Answer:
A
— N2
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Q. Which of the following has a bond angle of approximately 120 degrees?
A.
H2O
B.
NH3
C.
BF3
D.
CH4
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Solution
BF3 has a trigonal planar geometry with bond angles of approximately 120 degrees.
Correct Answer:
C
— BF3
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Q. Which of the following has a bond order of 0?
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Solution
He2 has a bond order of 0, calculated as (2 bonding electrons - 2 antibonding electrons)/2 = 0.
Correct Answer:
A
— He2
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Q. Which of the following has a bond order of 1?
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Solution
H2 has a bond order of 1, calculated as (2 bonding electrons - 0 antibonding electrons)/2 = 1.
Correct Answer:
C
— H2
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Q. Which of the following has the highest bond order?
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Solution
N2 has the highest bond order of 3 among the given options.
Correct Answer:
A
— N2
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Q. Which of the following has the lowest bond energy?
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Solution
F2 has the lowest bond energy due to the repulsion between the lone pairs on the fluorine atoms.
Correct Answer:
C
— F2
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Q. Which of the following has the lowest bond order?
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Solution
He2 has a bond order of 0, calculated as (2 bonding electrons - 2 antibonding electrons)/2 = 0.
Correct Answer:
D
— He2
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Q. Which of the following molecular orbitals is filled first according to the Aufbau principle?
A.
σ1s
B.
σ*1s
C.
π2p
D.
σ2p
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Solution
According to the Aufbau principle, the σ1s molecular orbital is filled first as it has the lowest energy.
Correct Answer:
A
— σ1s
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Q. Which of the following molecular orbitals is lower in energy than the 2p atomic orbitals?
A.
σ2s
B.
σ*2s
C.
π2p
D.
σ2p
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Solution
σ2s is lower in energy than the 2p atomic orbitals.
Correct Answer:
A
— σ2s
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Q. Which of the following molecules has a bond order of 1?
A.
H2
B.
He2
C.
Li2
D.
B2
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Solution
Li2 has a bond order of 1, calculated as (2 bonding electrons - 0 antibonding electrons)/2 = 1.
Correct Answer:
C
— Li2
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Q. Which of the following molecules has a bond order of 2?
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Solution
N2 has a bond order of 2, calculated as (number of bonding electrons - number of antibonding electrons)/2 = (10-6)/2 = 2.
Correct Answer:
B
— N2
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Q. Which of the following molecules has a higher bond order than N2?
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Solution
O2 has a bond order of 2, while N2 has a bond order of 3, so none have a higher bond order than N2.
Correct Answer:
A
— O2
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Q. Which of the following molecules has a higher bond order: N2 or O2?
A.
N2
B.
O2
C.
Both are equal
D.
Cannot be determined
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Solution
N2 has a bond order of 3, while O2 has a bond order of 2, so N2 has a higher bond order.
Correct Answer:
A
— N2
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Q. Which of the following molecules has a triple bond?
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Solution
N2 has a triple bond, consisting of one sigma bond and two pi bonds.
Correct Answer:
A
— N2
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Q. Which of the following molecules has the highest bond order?
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Solution
N2 has the highest bond order of 3, calculated as (10 bonding electrons - 2 antibonding electrons)/2 = 3.
Correct Answer:
A
— N2
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Q. Which of the following molecules is diamagnetic?
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Solution
F2 is diamagnetic as it has all electrons paired in its molecular orbitals.
Correct Answer:
C
— F2
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Q. Which of the following molecules is isoelectronic with N2?
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Solution
C2 is isoelectronic with N2, both having 10 electrons.
Correct Answer:
B
— C2
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Q. Which of the following molecules is isoelectronic with Ne?
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Solution
N2 is isoelectronic with Ne, both having 10 electrons.
Correct Answer:
C
— N2
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Q. Which of the following molecules is predicted to be stable according to molecular orbital theory?
A.
He2
B.
Li2
C.
Be2
D.
B2
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Solution
Li2 is stable with a bond order of 1, while He2 and Be2 are not stable.
Correct Answer:
B
— Li2
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Q. Which of the following pairs of atoms will form a bond with the highest bond order?
A.
C and O
B.
N and O
C.
C and N
D.
O and O
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Solution
C and N will form a bond with the highest bond order of 3, as seen in the molecule CN.
Correct Answer:
C
— C and N
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Q. Which of the following pairs of atoms will form a stable diatomic molecule according to molecular orbital theory?
A.
N and O
B.
O and F
C.
C and N
D.
B and O
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Solution
C and N will form a stable diatomic molecule as they have suitable bond orders and electron configurations.
Correct Answer:
C
— C and N
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Showing 31 to 60 of 73 (3 Pages)
Molecular Orbital Theory MCQ & Objective Questions
Molecular Orbital Theory is a crucial topic in chemistry that helps students understand the behavior of electrons in molecules. Mastering this theory is essential for scoring well in exams, as it frequently appears in various formats, including MCQs and objective questions. Practicing Molecular Orbital Theory MCQ questions not only enhances conceptual clarity but also boosts confidence in tackling important questions during exam preparation.
What You Will Practise Here
Fundamentals of Molecular Orbital Theory
Key concepts of bonding and antibonding orbitals
Electron configuration in diatomic molecules
Energy level diagrams and their significance
Paramagnetism and diamagnetism in molecules
Hybridization and its relation to Molecular Orbital Theory
Important Molecular Orbital Theory questions for exams
Exam Relevance
Molecular Orbital Theory is a significant part of the syllabus for CBSE, State Boards, NEET, and JEE. Students can expect questions that require them to analyze molecular structures, predict magnetic properties, and interpret energy diagrams. Common question patterns include direct MCQs, assertion-reason type questions, and numerical problems related to electron configurations.
Common Mistakes Students Make
Confusing bonding and antibonding orbitals and their energy levels.
Misunderstanding the concept of hybridization and its application in molecular geometry.
Overlooking the significance of electron spin in determining magnetic properties.
Failing to accurately draw and interpret energy level diagrams.
FAQs
Question: What is the significance of Molecular Orbital Theory in chemistry?Answer: Molecular Orbital Theory provides a deeper understanding of molecular structure and bonding, which is essential for predicting chemical behavior.
Question: How can I effectively prepare for Molecular Orbital Theory questions in exams?Answer: Regular practice of MCQs and objective questions will help reinforce your understanding and improve your problem-solving skills.
Don't miss the opportunity to enhance your knowledge! Start solving practice MCQs on Molecular Orbital Theory today and test your understanding to excel in your exams.
