T = 2π√(m/k) = 2π√(2/200) = 1 s.

The total energy E is proportional to the square of the amplitude. If the amplitude is halved, the new energy will be E/4.

Total energy E = (1/2)kA^2. 50 = (1/2)k(0.1^2) => k = 500 N/m.

Total energy in SHM is proportional to the square of the amplitude. If amplitude is doubled, energy increases by a factor of 4.

The maximum speed v_max of a simple harmonic oscillator is given by v_max = Aω, where ω is the angular frequency.

The maximum speed (v_max) of a simple harmonic oscillator is given by v_max = Aω, where ω is the angular frequency.

The maximum displacement in simple harmonic motion is equal to the amplitude, which is 5 cm.

Time period (T) is the reciprocal of frequency (f). T = 1/f = 1/1 = 1 s.

The amplitude of a simple harmonic oscillator is defined as the maximum displacement from the equilibrium position, which is 5 cm in this case.

The total energy E is conserved. When the displacement is half the amplitude, the potential energy is (1/2)E, so the kinetic energy is E - (1/2)E = (1/2)E.

Maximum velocity V_max = Aω. If A is doubled, V_max also doubles.

The total energy E in SHM is given by E = (1/2)kA². If A is doubled, E becomes (1/2)k(2A)² = 4(1/2)kA², which is quadrupled.

Maximum velocity V_max = ωA. If A is halved, V_max is also halved.

The total energy in simple harmonic motion is proportional to the square of the amplitude. If amplitude is doubled, energy increases by a factor of 2^2 = 4.

The total energy in SHM is proportional to the square of the amplitude. If amplitude is halved, energy is reduced to (1/2)^2 = 1/4, which is halved.

The time period T is given by T = 2π/ω. Therefore, T = 2π/5 = 0.4 s.

The time period T is inversely proportional to the frequency f. If the frequency is doubled, the time period halves.

Period T = 1/f, if frequency is halved, period doubles.

The period T = 2π√(m/k). If m is doubled, T increases.

Total energy (E) = (1/2)m(v_max)^2. Solving for v_max gives v_max = sqrt(2E/m) = sqrt(2*50/2) = 10 m/s.

Total energy E is proportional to the square of the amplitude. If amplitude is halved, energy is reduced to 1/4, hence it halves.

The total energy in simple harmonic motion is proportional to the square of the amplitude. If the amplitude increases, the total energy increases.

The phase constant φ depends on the initial conditions of the motion, such as the initial position and velocity.

The period (T) increases with mass (T = 2π√(m/k)).

The period T is given by T = 2π√(m/k). If m increases, T increases.

Acceleration is always opposite to displacement in SHM, hence 180 degrees.

In SHM, the restoring force is directly proportional to the displacement from the mean position.

In simple harmonic motion, the restoring force is directly proportional to the displacement from the mean position.

The velocity is maximum at the mean position where the displacement is zero.

The period T = 2π√(m/k) increases with an increase in mass (m).