Newtons Laws
Q. A 4 kg object is at rest on a table. What is the force of static friction acting on it?
A.
0 N
B.
4 N
C.
40 N
D.
10 N
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Solution
If the object is at rest and no external force is applied, the static friction force is 0 N.
Correct Answer: A — 0 N
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Q. A 4 kg object is at rest on a table. What is the force of static friction if no external force is applied?
A.
0 N
B.
4 N
C.
40 N
D.
None of the above
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Solution
If no external force is applied, the force of static friction is 0 N.
Correct Answer: A — 0 N
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Q. A 4 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
A.
0 N
B.
4 N
C.
40 N
D.
10 N
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Solution
The force acting on the object is its weight, F = mg = 4 kg * 10 m/s² = 40 N.
Correct Answer: C — 40 N
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Q. A 4 kg object is pulled with a force of 20 N. If the frictional force is 4 N, what is the net force acting on the object?
A.
16 N
B.
20 N
C.
24 N
D.
4 N
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Solution
Net force = applied force - frictional force = 20 N - 4 N = 16 N.
Correct Answer: A — 16 N
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Q. A 4 kg object is pushed with a force of 16 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 16 N / 4 kg = 4 m/s².
Correct Answer: C — 4 m/s²
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Q. A 4 kg object is pushed with a force of 20 N. If the frictional force is 4 N, what is the acceleration of the object?
A.
4 m/s²
B.
5 m/s²
C.
6 m/s²
D.
7 m/s²
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Solution
Net force = applied force - friction = 20 N - 4 N = 16 N. Acceleration a = F/m = 16 N / 4 kg = 4 m/s².
Correct Answer: B — 5 m/s²
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Q. A 5 kg block is resting on a frictionless surface. A force of 10 N is applied to it. What is the acceleration of the block?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using Newton's second law, F = ma, we have a = F/m = 10 N / 5 kg = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A 5 kg block is resting on a frictionless surface. If a force of 10 N is applied to it, what will be its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
5 m/s²
D.
10 m/s²
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Solution
Using Newton's second law, F = ma, we have a = F/m = 10 N / 5 kg = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A 5 kg block is resting on a horizontal surface. What is the normal force acting on the block?
A.
5 N
B.
10 N
C.
15 N
D.
20 N
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Solution
The normal force equals the weight of the block, which is mass times gravity: 5 kg * 9.8 m/s² = 49 N.
Correct Answer: B — 10 N
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Q. A 50 kg crate is at rest on a flat surface. What is the normal force acting on the crate?
A.
0 N
B.
50 N
C.
500 N
D.
1000 N
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Solution
The normal force equals the weight of the crate, which is N = mg = 50 kg * 10 m/s² = 500 N.
Correct Answer: C — 500 N
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Q. A 50 kg object is at rest on a surface. What is the normal force acting on it?
A.
0 N
B.
50 N
C.
100 N
D.
500 N
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Solution
The normal force equals the weight of the object, which is F = mg = 50 kg * 9.8 m/s² = 490 N.
Correct Answer: C — 100 N
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Q. A 50 kg object is moving with a constant velocity. What can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
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Solution
If the object is moving with constant velocity, the net force acting on it is zero.
Correct Answer: A — It is zero
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Q. A 50 kg object is pulled with a force of 200 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 6 kg object is in free fall. What is the force acting on it due to gravity?
A.
6 N
B.
60 N
C.
600 N
D.
0 N
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Solution
Force due to gravity F = mg = 6 kg * 10 m/s² = 60 N.
Correct Answer: B — 60 N
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Q. A 6 kg object is moving with a velocity of 3 m/s. What is its kinetic energy?
A.
27 J
B.
36 J
C.
54 J
D.
18 J
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Solution
Kinetic energy KE = 0.5 * m * v² = 0.5 * 6 kg * (3 m/s)² = 27 J.
Correct Answer: B — 36 J
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Q. A 6 kg object is subjected to a net force of 12 N. What is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, acceleration a = F/m = 12 N / 6 kg = 2 m/s².
Correct Answer: B — 3 m/s²
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Q. A car accelerates from rest at a rate of 2 m/s². What is the net force acting on the car if its mass is 1000 kg?
A.
200 N
B.
500 N
C.
1000 N
D.
2000 N
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Solution
Using F = ma, F = 1000 kg * 2 m/s² = 2000 N.
Correct Answer: D — 2000 N
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Q. A car of mass 1000 kg accelerates at 2 m/s². What is the net force acting on the car?
A.
2000 N
B.
500 N
C.
1000 N
D.
1500 N
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Solution
Using F = ma, the net force is F = 1000 kg * 2 m/s² = 2000 N.
Correct Answer: A — 2000 N
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Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. If the brakes are applied and the car comes to a stop in 5 seconds, what is the average force applied by the brakes?
A.
2000 N
B.
4000 N
C.
5000 N
D.
6000 N
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Solution
The change in momentum is 1000 kg * 20 m/s = 20000 kg·m/s. The average force is F = Δp/Δt = 20000 kg·m/s / 5 s = 4000 N.
Correct Answer: B — 4000 N
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Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the net force required to bring it to rest in 5 seconds?
A.
4000 N
B.
2000 N
C.
1000 N
D.
500 N
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Solution
First, find the deceleration: a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s². Then, F = ma = 1000 kg * 4 m/s² = 4000 N.
Correct Answer: A — 4000 N
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Q. A force of 10 N is applied to a 2 kg object. What is the object's acceleration?
A.
5 m/s²
B.
10 m/s²
C.
2 m/s²
D.
20 m/s²
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Solution
Using F = ma, acceleration a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: A — 5 m/s²
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Q. A force of 10 N is applied to a 2 kg object. What is the resulting acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 10 N / 2 kg = 5 m/s².
Correct Answer: A — 2 m/s²
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Q. A force of 15 N is applied to a 3 kg object. What is the object's acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 15 N is applied to a 3 kg object. What is the resulting acceleration?
A.
3 m/s²
B.
5 m/s²
C.
7 m/s²
D.
10 m/s²
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Solution
Using F = ma, we find a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. A force of 15 N is applied to a 5 kg object. What is the object's acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1 m/s²
D.
4 m/s²
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Solution
Using F = ma, acceleration a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. A force of 30 N is applied to a 5 kg object. What is the object's acceleration?
A.
3 m/s²
B.
6 m/s²
C.
9 m/s²
D.
12 m/s²
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Solution
Using F = ma, a = F/m = 30 N / 5 kg = 6 m/s².
Correct Answer: B — 6 m/s²
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Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?
A.
Exerts a greater force on A
B.
Exerts an equal and opposite force on A
C.
Exerts no force
D.
Exerts a lesser force on A
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Solution
Newton's third law states that for every action, there is an equal and opposite reaction.
Correct Answer: B — Exerts an equal and opposite force on A
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Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?
A.
5 N
B.
10 N
C.
15 N
D.
0 N
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Solution
In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.
Correct Answer: A — 5 N
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Q. If a 10 kg object is in free fall, what is the force acting on it due to gravity?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
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Solution
The force due to gravity is F = mg = 10 kg * 9.8 m/s² = 98 N, which rounds to 100 N.
Correct Answer: B — 20 N
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Q. If a 10 kg object is pulled with a force of 30 N, what is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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