Laws of Motion
Q. A 15 kg cart is pushed with a force of 60 N. If the frictional force opposing the motion is 15 N, what is the acceleration of the cart?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Net force = 60 N - 15 N = 45 N. Using F = ma, a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 15 kg object is at rest on a horizontal surface. What is the normal force acting on it?
A.
0 N
B.
15 N
C.
150 N
D.
75 N
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Solution
Normal force = weight = mg = 15 kg * 10 m/s² = 150 N.
Correct Answer: C — 150 N
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Q. A 15 kg object is at rest on a table. What is the force exerted by the table on the object?
A.
0 N
B.
15 N
C.
150 N
D.
10 N
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Solution
The normal force equals the weight of the object: 15 kg * 10 m/s² = 150 N.
Correct Answer: C — 150 N
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Q. A 15 kg object is in equilibrium. What is the net force acting on it?
A.
0 N
B.
15 N
C.
30 N
D.
45 N
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Solution
In equilibrium, the net force acting on the object is 0 N.
Correct Answer: A — 0 N
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Q. A 15 kg object is pushed with a force of 45 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 15 kg object is subjected to a net force of 45 N. What is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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Q. A 2 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?
A.
4.9 m/s²
B.
9.8 m/s²
C.
3.9 m/s²
D.
1.96 m/s²
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Solution
The acceleration a = g sin(θ) = 9.8 m/s² * sin(30°) = 9.8 m/s² * 0.5 = 4.9 m/s².
Correct Answer: A — 4.9 m/s²
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Q. A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
6 m/s²
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Solution
Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 2 kg object is in free fall. What is the net force acting on it?
A.
0 N
B.
2 N
C.
20 N
D.
19.6 N
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Solution
The net force is equal to the weight of the object: F = mg = 2 kg * 9.8 m/s² = 19.6 N.
Correct Answer: C — 20 N
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Q. A 2 kg object is moving with a velocity of 5 m/s. If it collides elastically with a stationary object of mass 3 kg, what will be the final velocity of the 2 kg object?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
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Solution
Using conservation of momentum and kinetic energy, the final velocity of the 2 kg object after an elastic collision is 1 m/s.
Correct Answer: A — 1 m/s
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Q. A 2 kg object is pulled with a force of 8 N. What is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
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Solution
Using F = ma, we find a = F/m = 8 N / 2 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the object?
A.
8 kg·m/s
B.
2 kg·m/s
C.
4 kg·m/s
D.
16 kg·m/s
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Solution
Momentum p = mv = 2 kg * 4 m/s = 8 kg·m/s.
Correct Answer: A — 8 kg·m/s
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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 5 m/s. What is the momentum of the object?
A.
10 kg·m/s
B.
5 kg·m/s
C.
2 kg·m/s
D.
1 kg·m/s
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Solution
Momentum p = mv = 2 kg * 5 m/s = 10 kg·m/s.
Correct Answer: A — 10 kg·m/s
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Q. A 20 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
A.
0 N
B.
20 N
C.
200 N
D.
10 N
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Solution
The force acting on the object is its weight: F = mg = 20 kg * 10 m/s² = 200 N.
Correct Answer: C — 200 N
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Q. A 20 kg object is pulled with a force of 100 N. If the frictional force is 40 N, what is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Net force = applied force - friction = 100 N - 40 N = 60 N. Acceleration a = F/m = 60 N / 20 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 25 kg object is pulled with a force of 100 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 100 N / 25 kg = 4 m/s².
Correct Answer: D — 5 m/s²
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Q. A 25 kg object is pushed with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Net force = 100 N - 25 N = 75 N. Acceleration a = F/m = 75 N / 25 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. A 25 kg object is subjected to a force of 50 N. What is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, we find a = F/m = 50 N / 25 kg = 2 m/s².
Correct Answer: B — 2 m/s²
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Q. A 3 kg block is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the block's acceleration assuming no friction?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Acceleration a = F/m = 12 N / 3 kg = 4 m/s².
Correct Answer: A — 2 m/s²
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Q. A 3 kg block is on a table and a horizontal force of 15 N is applied. If the frictional force is 5 N, what is the acceleration of the block?
A.
2 m/s²
B.
3 m/s²
C.
5 m/s²
D.
10 m/s²
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Solution
Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration a = F/m = 10 N / 3 kg = 3.33 m/s².
Correct Answer: A — 2 m/s²
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Q. A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?
A.
3 m/s²
B.
4 m/s²
C.
2 m/s²
D.
1 m/s²
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Solution
Net force = applied force - friction = 12 N - 3 N = 9 N. Acceleration a = F/m = 9 N / 3 kg = 3 m/s².
Correct Answer: B — 4 m/s²
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Q. A 3 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?
A.
3.9 m/s²
B.
4.9 m/s²
C.
9.8 m/s²
D.
1.5 m/s²
Show solution
Solution
The acceleration down the incline is given by a = g * sin(θ) = 9.8 m/s² * sin(30°) = 4.9 m/s².
Correct Answer: A — 3.9 m/s²
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Q. A 3 kg block is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the block?
A.
12 kg·m/s
B.
8 kg·m/s
C.
6 kg·m/s
D.
4 kg·m/s
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Solution
Momentum p = mv = 3 kg * 4 m/s = 12 kg·m/s.
Correct Answer: A — 12 kg·m/s
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Q. A 3 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when stretched?
A.
100 N
B.
200 N
C.
300 N
D.
600 N
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Solution
The maximum force exerted by the spring is F = kx. Assuming maximum stretch x = 1 m, F = 200 N/m * 1 m = 200 N.
Correct Answer: B — 200 N
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Q. A 3 kg object is at rest on a frictionless surface. A force of 9 N is applied. What is the final velocity after 3 seconds?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
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Solution
First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.
Correct Answer: C — 3 m/s
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Q. A 3 kg object is at rest on a frictionless surface. If a force of 9 N is applied, what will be its velocity after 3 seconds?
A.
3 m/s
B.
6 m/s
C.
9 m/s
D.
12 m/s
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Solution
First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.
Correct Answer: B — 6 m/s
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Q. A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².
Correct Answer: C — 4 m/s²
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Q. A 3 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².
Correct Answer: B — 3 m/s²
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Q. A 3 kg object is at rest on a table. If a force of 15 N is applied horizontally, what is the object's acceleration?
A.
5 m/s²
B.
10 m/s²
C.
15 m/s²
D.
20 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².
Correct Answer: A — 5 m/s²
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Q. A 3 kg object is at rest on a table. If a horizontal force of 12 N is applied, what is the acceleration of the object?
A.
4 m/s²
B.
0 m/s²
C.
3 m/s²
D.
12 m/s²
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Solution
Using F = ma, acceleration a = F/m = 12 N / 3 kg = 4 m/s².
Correct Answer: A — 4 m/s²
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