Laws of Motion Study Guide for Competitive Exams

Laws of Motion

Circular Motion Friction Newtons Laws

Q. A 15 kg cart is pushed with a force of 60 N. If the frictional force opposing the motion is 15 N, what is the acceleration of the cart?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Using F = ma, a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg object is at rest on a horizontal surface. What is the normal force acting on it?

A. 0 N
B. 15 N
C. 150 N
D. 75 N

Solution

Normal force = weight = mg = 15 kg * 10 m/s² = 150 N.

Correct Answer: C — 150 N

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Q. A 15 kg object is at rest on a table. What is the force exerted by the table on the object?

A. 0 N
B. 15 N
C. 150 N
D. 10 N

Solution

The normal force equals the weight of the object: 15 kg * 10 m/s² = 150 N.

Correct Answer: C — 150 N

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Q. A 15 kg object is in equilibrium. What is the net force acting on it?

A. 0 N
B. 15 N
C. 30 N
D. 45 N

Solution

In equilibrium, the net force acting on the object is 0 N.

Correct Answer: A — 0 N

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Q. A 15 kg object is pushed with a force of 45 N. What is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg object is subjected to a net force of 45 N. What is its acceleration?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 2 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?

A. 4.9 m/s²
B. 9.8 m/s²
C. 3.9 m/s²
D. 1.96 m/s²

Solution

The acceleration a = g sin(θ) = 9.8 m/s² * sin(30°) = 9.8 m/s² * 0.5 = 4.9 m/s².

Correct Answer: A — 4.9 m/s²

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Q. A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 6 m/s²

Solution

Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 2 kg object is in free fall. What is the net force acting on it?

A. 0 N
B. 2 N
C. 20 N
D. 19.6 N

Solution

The net force is equal to the weight of the object: F = mg = 2 kg * 9.8 m/s² = 19.6 N.

Correct Answer: C — 20 N

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Q. A 2 kg object is moving with a velocity of 5 m/s. If it collides elastically with a stationary object of mass 3 kg, what will be the final velocity of the 2 kg object?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Using conservation of momentum and kinetic energy, the final velocity of the 2 kg object after an elastic collision is 1 m/s.

Correct Answer: A — 1 m/s

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Q. A 2 kg object is pulled with a force of 8 N. What is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, we find a = F/m = 8 N / 2 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the object?

A. 8 kg·m/s
B. 2 kg·m/s
C. 4 kg·m/s
D. 16 kg·m/s

Solution

Momentum p = mv = 2 kg * 4 m/s = 8 kg·m/s.

Correct Answer: A — 8 kg·m/s

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 5 m/s. What is the momentum of the object?

A. 10 kg·m/s
B. 5 kg·m/s
C. 2 kg·m/s
D. 1 kg·m/s

Solution

Momentum p = mv = 2 kg * 5 m/s = 10 kg·m/s.

Correct Answer: A — 10 kg·m/s

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Q. A 20 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

A. 0 N
B. 20 N
C. 200 N
D. 10 N

Solution

The force acting on the object is its weight: F = mg = 20 kg * 10 m/s² = 200 N.

Correct Answer: C — 200 N

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Q. A 20 kg object is pulled with a force of 100 N. If the frictional force is 40 N, what is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = applied force - friction = 100 N - 40 N = 60 N. Acceleration a = F/m = 60 N / 20 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 25 kg object is pulled with a force of 100 N. What is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 100 N / 25 kg = 4 m/s².

Correct Answer: D — 5 m/s²

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Q. A 25 kg object is pushed with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 100 N - 25 N = 75 N. Acceleration a = F/m = 75 N / 25 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 25 kg object is subjected to a force of 50 N. What is its acceleration?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we find a = F/m = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A 3 kg block is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the block's acceleration assuming no friction?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Acceleration a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: A — 2 m/s²

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Q. A 3 kg block is on a table and a horizontal force of 15 N is applied. If the frictional force is 5 N, what is the acceleration of the block?

A. 2 m/s²
B. 3 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration a = F/m = 10 N / 3 kg = 3.33 m/s².

Correct Answer: A — 2 m/s²

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Q. A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?

A. 3 m/s²
B. 4 m/s²
C. 2 m/s²
D. 1 m/s²

Solution

Net force = applied force - friction = 12 N - 3 N = 9 N. Acceleration a = F/m = 9 N / 3 kg = 3 m/s².

Correct Answer: B — 4 m/s²

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Q. A 3 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?

A. 3.9 m/s²
B. 4.9 m/s²
C. 9.8 m/s²
D. 1.5 m/s²

Solution

The acceleration down the incline is given by a = g * sin(θ) = 9.8 m/s² * sin(30°) = 4.9 m/s².

Correct Answer: A — 3.9 m/s²

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Q. A 3 kg block is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the block?

A. 12 kg·m/s
B. 8 kg·m/s
C. 6 kg·m/s
D. 4 kg·m/s

Solution

Momentum p = mv = 3 kg * 4 m/s = 12 kg·m/s.

Correct Answer: A — 12 kg·m/s

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Q. A 3 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when stretched?

A. 100 N
B. 200 N
C. 300 N
D. 600 N

Solution

The maximum force exerted by the spring is F = kx. Assuming maximum stretch x = 1 m, F = 200 N/m * 1 m = 200 N.

Correct Answer: B — 200 N

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Q. A 3 kg object is at rest on a frictionless surface. A force of 9 N is applied. What is the final velocity after 3 seconds?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: C — 3 m/s

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Q. A 3 kg object is at rest on a frictionless surface. If a force of 9 N is applied, what will be its velocity after 3 seconds?

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 9 N / 3 kg = 3 m/s². Then, v = u + at = 0 + 3 m/s² * 3 s = 9 m/s.

Correct Answer: B — 6 m/s

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Q. A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 3 kg object is at rest on a horizontal surface. If a horizontal force of 12 N is applied, what is the object's acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: B — 3 m/s²

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Q. A 3 kg object is at rest on a table. If a force of 15 N is applied horizontally, what is the object's acceleration?

A. 5 m/s²
B. 10 m/s²
C. 15 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 15 N / 3 kg = 5 m/s².

Correct Answer: A — 5 m/s²

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Q. A 3 kg object is at rest on a table. If a horizontal force of 12 N is applied, what is the acceleration of the object?

A. 4 m/s²
B. 0 m/s²
C. 3 m/s²
D. 12 m/s²

Solution

Using F = ma, acceleration a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: A — 4 m/s²

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Laws of Motion

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