Q. What happens to the electric field if the charge is tripled while keeping the distance constant?
A.
It triples
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
The electric field is directly proportional to the charge. Tripling the charge will triple the electric field.
Correct Answer:
A
— It triples
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Q. What happens to the electric field inside a conductor in electrostatic equilibrium?
A.
It is zero
B.
It is constant
C.
It varies linearly
D.
It is maximum at the center
Show solution
Solution
In electrostatic equilibrium, the electric field inside a conductor is zero.
Correct Answer:
A
— It is zero
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Q. What happens to the electric field strength if the distance from a point charge is tripled?
A.
It becomes one-third
B.
It becomes one-ninth
C.
It becomes three times
D.
It remains the same
Show solution
Solution
The electric field strength E ∝ 1/r², so if distance is tripled, the field strength becomes 1/9 of the original.
Correct Answer:
B
— It becomes one-ninth
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Q. What is the direction of the electric field due to a negative point charge?
A.
Away from the charge
B.
Towards the charge
C.
Perpendicular to the charge
D.
None of the above
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Solution
The electric field due to a negative charge points towards the charge.
Correct Answer:
B
— Towards the charge
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Q. What is the direction of the electric field due to a positive charge?
A.
Towards the charge
B.
Away from the charge
C.
Perpendicular to the charge
D.
None of the above
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Solution
The electric field due to a positive charge points away from the charge.
Correct Answer:
B
— Away from the charge
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Q. What is the electric field at a distance of 1m from a charge of +1μC?
A.
9 × 10^9 N/C
B.
9 × 10^6 N/C
C.
9 × 10^3 N/C
D.
9 × 10^12 N/C
Show solution
Solution
Electric field E = k * q / r^2 = (9 × 10^9) * (1 × 10^-6) / (1)^2 = 9 × 10^3 N/C.
Correct Answer:
B
— 9 × 10^6 N/C
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Q. What is the electric field at a point due to a positive charge?
A.
Directed towards the charge
B.
Directed away from the charge
C.
Zero
D.
Depends on the distance from the charge
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Solution
The electric field due to a positive charge is directed away from the charge.
Correct Answer:
B
— Directed away from the charge
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Q. What is the electric field at a point midway between two equal and opposite charges?
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on distance
Show solution
Solution
The electric fields due to both charges cancel each other out at the midpoint, resulting in zero electric field.
Correct Answer:
A
— Zero
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1 m?
A.
4500 N/C
B.
5000 N/C
C.
5500 N/C
D.
6000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 4500 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.3m? (2000)
A.
1500 N/C
B.
5000 N/C
C.
1000 N/C
D.
2000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.3)^2 = 5000 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field inside a uniformly charged spherical shell?
A.
Zero
B.
Uniform
C.
Varies linearly
D.
Depends on the charge outside
Show solution
Solution
The electric field inside a uniformly charged spherical shell is zero.
Correct Answer:
A
— Zero
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Q. What is the potential difference between two points A and B in an electric field if the work done in moving a charge of +2C from A to B is 10J?
A.
5 V
B.
10 V
C.
20 V
D.
2 V
Show solution
Solution
V = W/Q = 10 J / 2 C = 5 V.
Correct Answer:
B
— 10 V
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Q. What is the potential difference between two points A and B in an electric field of 200 N/C if the distance between them is 0.5 m?
A.
100 V
B.
200 V
C.
50 V
D.
25 V
Show solution
Solution
Potential difference V = E * d = 200 N/C * 0.5 m = 100 V.
Correct Answer:
A
— 100 V
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Q. What is the potential difference between two points in a uniform electric field of strength 200 N/C separated by 3m?
A.
600 V
B.
200 V
C.
300 V
D.
400 V
Show solution
Solution
V = E * d = 200 N/C * 3 m = 600 V.
Correct Answer:
A
— 600 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
Show solution
Solution
Potential difference V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer:
A
— 20 V
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Q. What is the potential difference between two points in an electric field if the work done in moving a charge of +2μC between them is 0.04 J?
A.
20 V
B.
10 V
C.
5 V
D.
2 V
Show solution
Solution
V = W/q = 0.04 J / (2 × 10^-6 C) = 20 V.
Correct Answer:
A
— 20 V
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Q. What is the potential difference between two points in an electric field if the work done to move a charge of 2C is 10J?
A.
5V
B.
20V
C.
2V
D.
10V
Show solution
Solution
Potential difference V = W/Q = 10J / 2C = 5V.
Correct Answer:
B
— 20V
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Q. What is the potential energy of a system of two charges +3μC and +4μC separated by 0.2m?
A.
0.54 J
B.
0.72 J
C.
0.36 J
D.
0.18 J
Show solution
Solution
U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6 * 4 × 10^-6) / 0.2 = 0.54 J.
Correct Answer:
B
— 0.72 J
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Q. What is the potential energy of a system of two charges +3μC and +5μC separated by 0.2m?
A.
-6.75 J
B.
6.75 J
C.
0.75 J
D.
-0.75 J
Show solution
Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (3 × 10^-6) * (5 × 10^-6) / 0.2 = 6.75 J.
Correct Answer:
B
— 6.75 J
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Q. What is the potential energy of a system of two charges +3μC and -5μC separated by 0.3m?
A.
-0.45 J
B.
0.45 J
C.
-0.15 J
D.
0.15 J
Show solution
Solution
Potential energy U = k * q1 * q2 / r = (9 × 10^9) * (3 × 10^-6) * (-5 × 10^-6) / 0.3 = -0.45 J.
Correct Answer:
A
— -0.45 J
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Q. What is the potential energy of a system of two charges +5μC and +10μC separated by 0.2m?
A.
-0.225 J
B.
0.225 J
C.
0.45 J
D.
0.9 J
Show solution
Solution
Potential energy U = k * (q1 * q2) / r = (9 × 10^9) * (5 × 10^-6) * (10 × 10^-6) / 0.2 = 0.225 J.
Correct Answer:
B
— 0.225 J
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Q. What is the potential energy of a system of two charges +q and +q separated by a distance r?
A.
0
B.
k*q²/r
C.
-k*q²/r
D.
2k*q²/r
Show solution
Solution
Potential energy U = k * (q1 * q2) / r = k * (q * q) / r = k*q²/r.
Correct Answer:
B
— k*q²/r
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Q. What is the work done in moving a charge of +2μC from a point A to B in a uniform electric field of 500 N/C over a distance of 0.4m?
A.
400 J
B.
200 J
C.
100 J
D.
80 J
Show solution
Solution
Work done W = F * d = q * E * d = (2 × 10^-6 C) * (500 N/C) * (0.4 m) = 0.4 J = 80 J.
Correct Answer:
D
— 80 J
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Q. What is the work done in moving a charge of +2μC through a potential difference of 10V?
A.
20 μJ
B.
200 μJ
C.
2 μJ
D.
0.2 μJ
Show solution
Solution
W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.
Correct Answer:
B
— 200 μJ
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Q. Which of the following statements is true about electric field lines?
A.
They can cross each other
B.
They are always straight
C.
They point from positive to negative
D.
They are always circular
Show solution
Solution
Electric field lines point from positive to negative charges and never cross each other.
Correct Answer:
C
— They point from positive to negative
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Q. Which of the following statements is true regarding electric field lines?
A.
They can cross each other
B.
They are always straight
C.
They point from positive to negative charges
D.
They are always circular
Show solution
Solution
Electric field lines point from positive to negative charges and never cross each other.
Correct Answer:
C
— They point from positive to negative charges
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Showing 31 to 56 of 56 (2 Pages)
Electric Charges & Fields MCQ & Objective Questions
Understanding "Electric Charges & Fields" is crucial for students preparing for school exams and competitive tests in India. This topic lays the foundation for various concepts in physics and is frequently tested in exams. Practicing MCQs and objective questions on this subject not only enhances conceptual clarity but also boosts your confidence, helping you score better in your exams. Engage with our practice questions to tackle important questions effectively.
What You Will Practise Here
Fundamental concepts of electric charges and their properties
Understanding Coulomb's Law and its applications
Electric field intensity and its calculation
Electric field lines and their significance
Gauss's Law and its practical implications
Potential due to point charges and equipotential surfaces
Key formulas and definitions related to electric fields
Exam Relevance
The topic of "Electric Charges & Fields" is a staple in CBSE, State Boards, NEET, and JEE exams. Questions often focus on the application of Coulomb's Law, calculations involving electric fields, and conceptual understanding of electric forces. Students can expect both theoretical and numerical questions, making it essential to master this topic through consistent practice of objective questions.
Common Mistakes Students Make
Confusing the concepts of electric field and electric potential
Misapplying Coulomb's Law in different scenarios
Overlooking the direction of electric field lines
Neglecting to consider the superposition principle in electric fields
FAQs
Question: What are electric charges?Answer: Electric charges are fundamental properties of matter that cause it to experience a force when placed in an electric field. They can be positive or negative.
Question: How do I calculate the electric field due to a point charge?Answer: The electric field (E) due to a point charge (Q) at a distance (r) is calculated using the formula E = k * |Q| / r², where k is Coulomb's constant.
Start your journey towards mastering "Electric Charges & Fields" today! Solve our practice MCQs to test your understanding and enhance your exam preparation. Your success is just a question away!
