Q. A torque of 30 Nm is applied to a wheel with a radius of 0.5 m. What is the force applied at the edge of the wheel?
A.
60 N
B.
30 N
C.
15 N
D.
75 N
Show solution
Solution
Torque (τ) = Force (F) × Radius (r) => F = τ / r = 30 Nm / 0.5 m = 60 N.
Correct Answer:
A
— 60 N
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Q. A torque of 30 Nm is applied to a wheel. If the radius of the wheel is 0.5 m, what is the force applied tangentially?
A.
15 N
B.
30 N
C.
60 N
D.
75 N
Show solution
Solution
Torque (τ) = Force (F) × Radius (r) => F = τ / r = 30 Nm / 0.5 m = 60 N.
Correct Answer:
C
— 60 N
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Q. A torque of 30 Nm is applied to a wheel. If the radius of the wheel is 0.5 m, what is the force applied tangentially at the edge of the wheel?
A.
15 N
B.
30 N
C.
60 N
D.
75 N
Show solution
Solution
Torque (τ) = F × r, thus F = τ / r = 30 Nm / 0.5 m = 60 N.
Correct Answer:
C
— 60 N
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Q. A torque of 40 Nm is required to rotate a wheel. If the radius of the wheel is 0.4 m, what is the force applied tangentially?
A.
100 N
B.
80 N
C.
60 N
D.
40 N
Show solution
Solution
Force = Torque / Radius = 40 Nm / 0.4 m = 100 N.
Correct Answer:
B
— 80 N
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Q. A torque of 5 Nm is applied to a wheel. If the radius of the wheel is 0.25 m, what is the force applied tangentially?
A.
10 N
B.
20 N
C.
5 N
D.
15 N
Show solution
Solution
Torque (τ) = F × r, thus F = τ / r = 5 Nm / 0.25 m = 20 N.
Correct Answer:
A
— 10 N
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Q. A torque of 50 Nm is applied to a wheel with a radius of 0.25 m. What is the force applied at the edge of the wheel?
A.
100 N
B.
200 N
C.
250 N
D.
300 N
Show solution
Solution
Force = Torque / Radius = 50 Nm / 0.25 m = 200 N.
Correct Answer:
B
— 200 N
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Q. A torque of 50 Nm is applied to a wheel with a radius of 0.5 m. What is the force applied tangentially to the wheel?
A.
100 N
B.
50 N
C.
25 N
D.
75 N
Show solution
Solution
Torque (τ) = Force (F) × Radius (r) => F = τ / r = 50 Nm / 0.5 m = 100 N.
Correct Answer:
A
— 100 N
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Q. A torque of 50 Nm is created by a force acting at a distance of 2 m. What is the force applied?
A.
20 N
B.
25 N
C.
30 N
D.
35 N
Show solution
Solution
Force = Torque / Distance = 50 Nm / 2 m = 25 N.
Correct Answer:
B
— 25 N
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Q. If a force of 12 N is applied at an angle of 30 degrees to a lever arm of 1 m, what is the torque about the pivot?
A.
6 Nm
B.
10 Nm
C.
12 Nm
D.
15 Nm
Show solution
Solution
Torque = Force × Distance × sin(θ) = 12 N × 1 m × sin(30°) = 12 N × 1 m × 0.5 = 6 Nm.
Correct Answer:
A
— 6 Nm
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Q. If a force of 15 N is applied at a distance of 0.4 m from the pivot, what is the torque?
A.
6 Nm
B.
12 Nm
C.
15 Nm
D.
20 Nm
Show solution
Solution
Torque = Force × Distance = 15 N × 0.4 m = 6 Nm.
Correct Answer:
B
— 12 Nm
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Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1.5 m, what is the torque about the pivot?
A.
3.75 Nm
B.
7.5 Nm
C.
11.25 Nm
D.
12.99 Nm
Show solution
Solution
Torque (τ) = F × r × sin(θ) = 15 N × 1.5 m × sin(30°) = 15 × 1.5 × 0.5 = 11.25 Nm.
Correct Answer:
B
— 7.5 Nm
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Q. If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1 m, what is the torque about the pivot?
A.
7.5 Nm
B.
15 Nm
C.
12.99 Nm
D.
10 Nm
Show solution
Solution
Torque (τ) = F × r × sin(θ) = 15 N × 1 m × sin(30°) = 15 N × 1 m × 0.5 = 7.5 Nm.
Correct Answer:
C
— 12.99 Nm
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Q. If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
A.
50 N
B.
45 N
C.
40 N
D.
30 N
Show solution
Solution
Force = Torque / Distance = 15 Nm / 0.3 m = 50 N.
Correct Answer:
A
— 50 N
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Q. If a torque of 25 Nm is applied and the lever arm is 5 m, what is the angle at which the force is applied if the force is 10 N?
A.
0 degrees
B.
30 degrees
C.
60 degrees
D.
90 degrees
Show solution
Solution
Torque = Force × Distance × sin(θ) => 25 Nm = 10 N × 5 m × sin(θ) => sin(θ) = 0.5 => θ = 30 degrees.
Correct Answer:
C
— 60 degrees
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Q. If a torque of 25 Nm is applied to a wheel with a radius of 0.5 m, what is the force applied at the edge of the wheel?
A.
50 N
B.
40 N
C.
30 N
D.
20 N
Show solution
Solution
Force = Torque / Radius = 25 Nm / 0.5 m = 50 N.
Correct Answer:
A
— 50 N
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Q. If a torque of 25 Nm is generated by a force acting at a distance of 0.5 m, what is the force applied?
A.
50 N
B.
40 N
C.
30 N
D.
20 N
Show solution
Solution
Force = Torque / Distance = 25 Nm / 0.5 m = 50 N.
Correct Answer:
A
— 50 N
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Q. If a torque of 30 Nm is applied to a lever arm of 3 m, what is the force applied?
A.
5 N
B.
10 N
C.
15 N
D.
20 N
Show solution
Solution
Force = Torque / Distance = 30 Nm / 3 m = 10 N.
Correct Answer:
B
— 10 N
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Q. If a torque of 8 Nm is produced by a force acting at a distance of 0.2 m, what is the force?
A.
20 N
B.
30 N
C.
40 N
D.
50 N
Show solution
Solution
Force = Torque / Distance = 8 Nm / 0.2 m = 40 N.
Correct Answer:
A
— 20 N
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Q. If the angle between the force and the lever arm is 90 degrees, how does it affect the torque?
A.
Torque is zero
B.
Torque is maximum
C.
Torque is half
D.
Torque is minimum
Show solution
Solution
Torque is maximum when the angle is 90 degrees because τ = F × r × sin(θ) and sin(90°) = 1.
Correct Answer:
B
— Torque is maximum
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Q. If the angle between the force and the lever arm is 90 degrees, what is the torque produced by a 15 N force applied at a distance of 2 m?
A.
0 Nm
B.
15 Nm
C.
30 Nm
D.
45 Nm
Show solution
Solution
Torque (τ) = F × d × sin(θ) = 15 N × 2 m × sin(90°) = 30 Nm.
Correct Answer:
C
— 30 Nm
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Q. If the lever arm is doubled while keeping the force constant, how does the torque change?
A.
It doubles
B.
It triples
C.
It remains the same
D.
It halves
Show solution
Solution
Torque is directly proportional to the lever arm; if the lever arm is doubled, the torque also doubles.
Correct Answer:
A
— It doubles
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Q. If the torque is doubled while keeping the distance constant, what happens to the force applied?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Torque = Force × Distance; if Torque is doubled and Distance is constant, Force must also double.
Correct Answer:
A
— It doubles
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Q. If the torque on a rotating object is doubled while the radius remains constant, what happens to the force applied?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
If torque is doubled and radius remains constant, the force must also double to maintain the relationship τ = F × r.
Correct Answer:
A
— It doubles
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Q. If the torque on an object is zero, what can be said about the forces acting on it?
A.
The object is at rest.
B.
The net force is zero.
C.
The forces are balanced.
D.
The forces are acting along the same line.
Show solution
Solution
If the torque is zero, it means that the forces are acting along the same line, resulting in no rotational effect.
Correct Answer:
D
— The forces are acting along the same line.
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Q. If the torque on an object is zero, which of the following must be true?
A.
The net force is zero.
B.
The object is at rest.
C.
The forces are balanced.
D.
The line of action of the forces passes through the pivot.
Show solution
Solution
If the torque is zero, it means that the line of action of the forces passes through the pivot point.
Correct Answer:
D
— The line of action of the forces passes through the pivot.
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Q. If two equal and opposite forces are applied at the ends of a lever arm of length 4 m, what is the net torque about the center?
A.
0 Nm
B.
8 Nm
C.
4 Nm
D.
16 Nm
Show solution
Solution
The net torque is zero because the forces are equal and opposite, resulting in no rotational effect.
Correct Answer:
A
— 0 Nm
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Q. If two equal and opposite forces are applied at the ends of a lever arm of length 1 m, what is the net torque about the center?
A.
0 Nm
B.
1 Nm
C.
2 Nm
D.
4 Nm
Show solution
Solution
The net torque is zero because the forces are equal and opposite, producing no rotational effect.
Correct Answer:
A
— 0 Nm
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Q. If two equal and opposite forces are applied at the ends of a lever arm, what is the net torque about the center?
A.
Zero
B.
Equal to the force
C.
Depends on the distance
D.
Twice the force
Show solution
Solution
The net torque is zero because the forces are equal and opposite, producing no rotational effect.
Correct Answer:
A
— Zero
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Q. If two forces of 5 N and 10 N are applied at the same distance from a pivot, which force produces more torque?
A.
5 N
B.
10 N
C.
Both produce the same torque
D.
It depends on the angle of application
Show solution
Solution
Torque is directly proportional to the force applied; hence, the 10 N force produces more torque.
Correct Answer:
B
— 10 N
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Q. If two forces of equal magnitude are applied at different distances from a pivot, which will produce a greater torque?
A.
The force applied further away
B.
The force applied closer
C.
Both produce equal torque
D.
It depends on the angle
Show solution
Solution
Torque is greater when the force is applied further away from the pivot, given equal magnitudes.
Correct Answer:
A
— The force applied further away
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Showing 31 to 60 of 75 (3 Pages)
Torque MCQ & Objective Questions
Understanding torque is crucial for students preparing for school exams and competitive tests. Torque is a fundamental concept in physics that often appears in various forms in objective questions. Practicing MCQs related to torque not only enhances your grasp of the topic but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Definition of torque and its significance in rotational motion.
Key formulas related to torque, including torque = force x distance.
Understanding the concept of the moment of inertia and its relation to torque.
Applications of torque in real-life scenarios and mechanical systems.
Diagrams illustrating the direction and magnitude of torque.
Common units of torque and conversions between them.
Problem-solving techniques for torque-related MCQs.
Exam Relevance
Torque is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. It frequently appears in the form of conceptual questions, numerical problems, and application-based scenarios. Students can expect to encounter questions that require them to calculate torque, analyze rotational systems, or interpret diagrams. Familiarity with torque MCQ questions can greatly enhance your performance in these exams.
Common Mistakes Students Make
Confusing torque with linear force, leading to incorrect application of formulas.
Overlooking the direction of torque, which is essential for solving problems accurately.
Neglecting to consider the point of application of force when calculating torque.
Misunderstanding the relationship between torque and angular acceleration.
FAQs
Question: What is the formula for calculating torque?Answer: The formula for torque is τ = r × F, where τ is torque, r is the distance from the pivot point to the point of force application, and F is the applied force.
Question: How does torque relate to rotational motion?Answer: Torque is the rotational equivalent of linear force and is responsible for causing an object to rotate about an axis.
Get ready to enhance your understanding of torque! Start solving practice MCQs today to test your knowledge and prepare effectively for your exams. Remember, mastering torque will not only help you in physics but also in achieving your academic goals.
