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Q. A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: B — 20 N

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Q. A 10 kg object is hanging at rest from a rope. What is the tension in the rope?

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

The tension in the rope must balance the weight of the object. T = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

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Q. A 10 kg object is hanging from a rope. What is the tension in the rope when the object is at rest?

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

At rest, the tension in the rope equals the weight of the object: T = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

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Q. A 10 kg object is lifted to a height of 10 m. How much work is done against gravity?

A. 0 J
B. 100 J
C. 200 J
D. 1000 J

Solution

Work done against gravity is equal to the change in potential energy, W = mgh = 10 * 9.8 * 10 = 980 J.

Correct Answer: D — 1000 J

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Q. A 10 kg object is lifted to a height of 2 m. What is the work done against gravity?

A. 20 J
B. 40 J
C. 60 J
D. 80 J

Solution

Work done = mass × g × height = 10 kg × 9.8 m/s² × 2 m = 196 J.

Correct Answer: B — 40 J

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Q. A 10 kg object is lifted to a height of 5 m. How much work is done against gravity?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Work done = mgh = 10 * 9.8 * 5 = 490 J.

Correct Answer: B — 100 J

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Q. A 10 kg object is lifted to a height of 5 m. What is the potential energy gained by the object?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential energy (PE) = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J.

Correct Answer: B — 100 J

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Q. A 10 kg object is lifted to a height of 5 m. What is the work done against gravity?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Work done against gravity = mgh = 10 * 9.8 * 5 = 490 J.

Correct Answer: B — 100 J

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Q. A 10 kg object is moving in a circular path of radius 5 m with a speed of 10 m/s. What is the centripetal force acting on the object?

A. 20 N
B. 10 N
C. 5 N
D. 50 N

Solution

Centripetal force F = mv²/r = 10 kg * (10 m/s)² / 5 m = 200 N.

Correct Answer: A — 20 N

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Q. A 10 kg object is moving in a circular path of radius 5 m with a speed of 4 m/s. What is the centripetal force acting on the object?

A. 8 N
B. 16 N
C. 32 N
D. 40 N

Solution

Centripetal force F = mv²/r = 10 kg * (4 m/s)² / 5 m = 32 N.

Correct Answer: B — 16 N

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Q. A 10 kg object is moving with a speed of 3 m/s. If it comes to a stop, how much work is done by the friction force?

A. 45 J
B. 90 J
C. 135 J
D. 180 J

Solution

Work done = Change in Kinetic Energy = 0 - (0.5 × 10 kg × (3 m/s)²) = -45 J.

Correct Answer: B — 90 J

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Q. A 10 kg object is moving with a speed of 3 m/s. What is its kinetic energy?

A. 45 J
B. 30 J
C. 60 J
D. 90 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 10 kg × (3 m/s)² = 45 J.

Correct Answer: A — 45 J

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Q. A 10 kg object is moving with a speed of 5 m/s. What is its total mechanical energy?

A. 125 J
B. 250 J
C. 500 J
D. 1000 J

Solution

Total mechanical energy = KE + PE. KE = 0.5 * 10 * (5)² = 125 J. Assuming PE = 0, total energy = 125 J.

Correct Answer: B — 250 J

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Q. A 10 kg object is moving with a velocity of 2 m/s. If it comes to rest, what is the change in momentum?

A. 20 kg·m/s
B. 10 kg·m/s
C. 5 kg·m/s
D. 0 kg·m/s

Solution

Initial momentum = mv = 10 kg * 2 m/s = 20 kg·m/s. Final momentum = 0. Change in momentum = 20 kg·m/s - 0 = 20 kg·m/s.

Correct Answer: A — 20 kg·m/s

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Q. A 10 kg object is moving with a velocity of 3 m/s. What is its kinetic energy?

A. 15 J
B. 30 J
C. 45 J
D. 60 J

Solution

Kinetic energy = 0.5 × m × v² = 0.5 × 10 kg × (3 m/s)² = 45 J.

Correct Answer: C — 45 J

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Q. A 10 kg object is moving with a velocity of 3 m/s. What is its momentum?

A. 10 kg·m/s
B. 30 kg·m/s
C. 3 kg·m/s
D. 0.3 kg·m/s

Solution

Momentum p = mv = 10 kg * 3 m/s = 30 kg·m/s.

Correct Answer: B — 30 kg·m/s

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Q. A 10 kg object is moving with a velocity of 3 m/s. What is the total mechanical energy if it is at a height of 5 m?

A. 150 J
B. 180 J
C. 300 J
D. 450 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy = 0.5 × 10 kg × (3 m/s)² + 10 kg × 9.8 m/s² × 5 m = 45 J + 490 J = 535 J.

Correct Answer: C — 300 J

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Q. A 10 kg object is moving with a velocity of 4 m/s. What is its momentum?

A. 40 kg m/s
B. 20 kg m/s
C. 10 kg m/s
D. 30 kg m/s

Solution

Momentum (p) = m * v = 10 kg * 4 m/s = 40 kg m/s

Correct Answer: A — 40 kg m/s

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Q. A 10 kg object is moving with a velocity of 5 m/s. What is its momentum?

A. 10 kg·m/s
B. 25 kg·m/s
C. 50 kg·m/s
D. 75 kg·m/s

Solution

Momentum p = mv = 10 kg * 5 m/s = 50 kg·m/s.

Correct Answer: C — 50 kg·m/s

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Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Net force = applied force - friction = 30 N - 10 N = 20 N.

Correct Answer: B — 20 N

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Q. A 10 kg object is thrown upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)

A. 11.5 m
B. 22.5 m
C. 15.3 m
D. 10.0 m

Solution

Using conservation of energy, KE at the bottom = PE at the top. 0.5mv² = mgh. Solving gives h = v²/(2g) = (15)²/(2*9.8) = 11.5 m.

Correct Answer: A — 11.5 m

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Q. A 10 kg object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)

A. 11.25 m
B. 22.5 m
C. 15 m
D. 7.5 m

Solution

Using energy conservation: KE_initial = PE_max; 1/2 * m * v^2 = m * g * h; h = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m

Correct Answer: A — 11.25 m

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Q. A 10 Ω resistor and a 20 Ω resistor are connected in series. What is the total resistance?

A. 10 Ω
B. 20 Ω
C. 30 Ω
D. 5 Ω

Solution

In series, the total resistance R = R1 + R2 = 10 Ω + 20 Ω = 30 Ω.

Correct Answer: C — 30 Ω

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Q. A 10-ohm resistor and a 20-ohm resistor are connected in series. What is the total resistance?

A. 10 ohms
B. 20 ohms
C. 30 ohms
D. 5 ohms

Solution

In series, the total resistance R = R1 + R2 = 10 + 20 = 30 ohms.

Correct Answer: C — 30 ohms

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Q. A 10-ohm resistor has a voltage of 20 volts across it. What is the current flowing through the resistor?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Using Ohm's Law, I = V / R = 20 V / 10 Ω = 2 A.

Correct Answer: B — 2 A

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Q. A 10-ohm resistor has a voltage of 50 volts across it. What is the current flowing through the resistor?

A. 5 A
B. 10 A
C. 15 A
D. 20 A

Solution

Using Ohm's Law, I = V / R = 50 V / 10 Ω = 5 A.

Correct Answer: B — 10 A

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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?

A. 40 W
B. 20 W
C. 10 W
D. 2 W

Solution

Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.

Correct Answer: A — 40 W

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Q. A 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the average power exerted by the engine?

A. 2000 W
B. 4000 W
C. 5000 W
D. 6000 W

Solution

First, calculate the work done: W = (1/2)mv^2 = (1/2)(1000 kg)(20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.

Correct Answer: C — 5000 W

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Q. A 1000 W heater operates for 1 hour. How much energy does it consume?

A. 3600 J
B. 1000 J
C. 3600000 J
D. 100000 J

Solution

Energy consumed is E = P * t. Here, P = 1000 W and t = 1 hour = 3600 seconds. Thus, E = 1000 W * 3600 s = 3600000 J.

Correct Answer: C — 3600000 J

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Q. A 1000 W heater operates for 2 hours. How much energy does it consume?

A. 7200000 J
B. 2000000 J
C. 3600000 J
D. 1000000 J

Solution

Energy consumed can be calculated using E = P * t. Here, P = 1000 W and t = 2 hours = 7200 seconds. Thus, E = 1000 W * 7200 s = 7200000 J.

Correct Answer: C — 3600000 J

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Engineering & Architecture Admissions

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